{"id":454,"date":"2023-07-29T20:50:57","date_gmt":"2023-07-29T20:50:57","guid":{"rendered":"https:\/\/statorials.org\/id\/distribusi-seragam-r\/"},"modified":"2023-07-29T20:50:57","modified_gmt":"2023-07-29T20:50:57","slug":"distribusi-seragam-r","status":"publish","type":"post","link":"https:\/\/statorials.org\/id\/distribusi-seragam-r\/","title":{"rendered":"Distribusi seragam di r"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\"><a href=\"https:\/\/statorials.org\/id\/distribusi-seragam\/\" target=\"_blank\" rel=\"noopener\">Distribusi seragam<\/a> adalah distribusi probabilitas yang setiap nilai antara interval <em>a<\/em> sampai <em>b<\/em> mempunyai probabilitas yang sama untuk dipilih.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Peluang terambilnya nilai antara x <sub>1<\/sub> dan x <sub>2<\/sub> pada selang waktu <em>a<\/em> sampai <em>b<\/em> dapat dicari dengan menggunakan rumus:<\/span><\/p>\n<p style=\"text-align: center;\"> <span style=\"color: #000000;\">P(dapatkan nilai antara x <sub>1<\/sub> dan x <sub>2<\/sub> ) = (x <sub>2<\/sub> \u2013 x <sub>1<\/sub> ) \/ (b \u2013 a)<\/span> <\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"aligncenter wp-image-1565 size-full\" src=\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/uniforme_pic.jpg\" sizes=\"\" srcset=\"\" alt=\"Contoh distribusi seragam\" width=\"336\" height=\"203\"><\/p>\n<p> <span style=\"color: #000000;\">Distribusi seragam mempunyai ciri-ciri sebagai berikut:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">Rata-rata distribusinya adalah <strong>\u03bc<\/strong> = (a + b) \/ 2<\/span><\/li>\n<li> <span style=\"color: #000000;\">Varians distribusinya adalah <strong>\u03c3 <sup>2<\/sup><\/strong> = (b \u2013 a) <sup>2\/12<\/sup><\/span><\/li>\n<li> <span style=\"color: #000000;\">Simpangan baku distribusinya adalah <strong>\u03c3<\/strong> = \u221a\u03c3 <sup>2<\/sup><\/span><\/li>\n<\/ul>\n<h2> <strong>Distribusi seragam di R: sintaksis<\/strong><\/h2>\n<p> <span style=\"color: #000000;\">Dua fungsi bawaan di R yang akan kita gunakan untuk menjawab pertanyaan menggunakan distribusi seragam adalah:<\/span><\/p>\n<p> <strong><span style=\"color: #000000;\">dunif(x, min, max)<\/span><\/strong> <span style=\"color: #000000;\">\u2013 menghitung fungsi kepadatan probabilitas (pdf) untuk distribusi seragam di mana <em>x<\/em> adalah nilai variabel acak, dan <em>min<\/em> dan <em>max<\/em> masing-masing adalah bilangan minimum dan maksimum dari distribusi.<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>punif(x, min, max)<\/strong> \u2013 menghitung fungsi distribusi kumulatif (cdf) untuk distribusi seragam di mana <em>x<\/em> adalah nilai variabel acak, dan <em>min<\/em> dan <em>max<\/em> masing-masing adalah bilangan minimum dan maksimum dari distribusi.<\/span><\/p>\n<p> <em><span style=\"color: #000000;\">Temukan dokumentasi R lengkap untuk distribusi seragam <a href=\"https:\/\/stat.ethz.ch\/R-manual\/R-devel\/library\/stats\/html\/Uniform.html\" target=\"_blank\" rel=\"noopener\">di sini<\/a> .<\/span><\/em><\/p>\n<h2> <span style=\"color: #000000;\"><strong>Selesaikan masalah menggunakan distribusi seragam di R<\/strong><\/span><\/h2>\n<p> <span style=\"color: #000000;\"><strong>Contoh 1:<\/strong> <i>Sebuah bus tiba di halte setiap 20 menit. Jika Anda tiba di halte bus, berapa peluang bus tersebut tiba dalam waktu 8 menit atau kurang?<\/i><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>Solusi:<\/strong> Karena kita ingin mengetahui probabilitas bahwa bus akan muncul dalam 8 menit atau kurang, kita cukup menggunakan fungsi punif() karena kita ingin mengetahui probabilitas kumulatif bahwa bus akan muncul dalam 8 menit atau kurang, mengingat bahwa waktu minimum adalah 0 menit dan waktu maksimum adalah 20 menit:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>punitive(8, min=0, max=20)<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>## [1] 0.4<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Peluang bus tiba dalam waktu 8 menit atau kurang adalah <strong>0,4<\/strong> .<\/span><\/p>\n<hr>\n<p> <span style=\"color: #000000;\"><strong>Contoh 2:<\/strong> <i>Berat suatu spesies katak tertentu tersebar merata antara 15 dan 25 gram. Jika seekor katak diambil secara acak, berapa peluang terambilnya katak dengan berat antara 17 dan 19 gram?<\/i><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>Solusi:<\/strong> Untuk mencari solusinya, kita akan menghitung probabilitas kumulatif bahwa seekor katak memiliki berat kurang dari 19 pon, kemudian mengurangi probabilitas kumulatif bahwa seekor katak memiliki berat kurang dari 17 pon menggunakan sintaks berikut:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>punitive(19, 15, 25) - punitive(17, 15, 25)\n<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"><strong>## [1] 0.2<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Jadi peluang terambilnya katak tersebut beratnya antara 17 dan 19 gram adalah <strong>0,2<\/strong> .<\/span><\/p>\n<hr>\n<p> <span style=\"color: #000000;\"><strong>Contoh 3:<\/strong> <em>Durasi permainan NBA didistribusikan secara merata antara 120 dan 170 menit. Berapa peluang pertandingan NBA yang dipilih secara acak akan berlangsung lebih dari 150 menit?<\/em><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>Solusi:<\/strong> Untuk menjawab pertanyaan ini, kita dapat menggunakan rumus 1 \u2013 (probabilitas permainan berlangsung kurang dari 150 menit). Ini diberikan oleh:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>1 - punitive(150, 120, 170)<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>## [1] 0.4<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Peluang suatu pertandingan NBA yang dipilih secara acak berlangsung lebih dari 150 menit adalah <strong>0,4<\/strong> .<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Distribusi seragam adalah distribusi probabilitas yang setiap nilai antara interval a sampai b mempunyai probabilitas yang sama untuk dipilih. Peluang terambilnya nilai antara x 1 dan x 2 pada selang waktu a sampai b dapat dicari dengan menggunakan rumus: P(dapatkan nilai antara x 1 dan x 2 ) = (x 2 \u2013 x 1 ) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Distribusi seragam di R - Statorials<\/title>\n<meta name=\"description\" content=\"Tutorial sederhana tentang cara menyelesaikan masalah menggunakan distribusi seragam di R.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Distribusi seragam di R - Statorials\" \/>\n<meta property=\"og:description\" content=\"Tutorial sederhana tentang cara menyelesaikan masalah menggunakan distribusi seragam di R.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/\" \/>\n<meta property=\"og:site_name\" content=\"Statorials\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-29T20:50:57+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/uniforme_pic.jpg\" \/>\n<meta name=\"author\" content=\"Benjamin anderson\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Ditulis oleh\" \/>\n\t<meta name=\"twitter:data1\" content=\"Benjamin anderson\" \/>\n\t<meta name=\"twitter:label2\" content=\"Estimasi waktu membaca\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 menit\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/\",\"url\":\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/\",\"name\":\"Distribusi seragam di R - Statorials\",\"isPartOf\":{\"@id\":\"https:\/\/statorials.org\/id\/#website\"},\"datePublished\":\"2023-07-29T20:50:57+00:00\",\"dateModified\":\"2023-07-29T20:50:57+00:00\",\"author\":{\"@id\":\"https:\/\/statorials.org\/id\/#\/schema\/person\/3d17a1160dd2d052b7c78e502cb9ec81\"},\"description\":\"Tutorial sederhana tentang cara menyelesaikan masalah menggunakan distribusi seragam di R.\",\"breadcrumb\":{\"@id\":\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/#breadcrumb\"},\"inLanguage\":\"id\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/statorials.org\/id\/distribusi-seragam-r\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/statorials.org\/id\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Distribusi seragam di r\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/statorials.org\/id\/#website\",\"url\":\"https:\/\/statorials.org\/id\/\",\"name\":\"Statorials\",\"description\":\"Panduan anda untuk kompetensi statistik!\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/statorials.org\/id\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"id\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/statorials.org\/id\/#\/schema\/person\/3d17a1160dd2d052b7c78e502cb9ec81\",\"name\":\"Benjamin anderson\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"id\",\"@id\":\"https:\/\/statorials.org\/id\/#\/schema\/person\/image\/\",\"url\":\"http:\/\/statorials.org\/id\/wp-content\/uploads\/2023\/10\/Dr.-Benjamin-Anderson-96x96.jpg\",\"contentUrl\":\"http:\/\/statorials.org\/id\/wp-content\/uploads\/2023\/10\/Dr.-Benjamin-Anderson-96x96.jpg\",\"caption\":\"Benjamin anderson\"},\"description\":\"Halo, saya Benjamin, pensiunan profesor statistika yang menjadi guru Statorial yang berdedikasi. 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