{"id":458,"date":"2023-07-29T20:18:10","date_gmt":"2023-07-29T20:18:10","guid":{"rendered":"https:\/\/statorials.org\/ja\/dbinom-pbinom-qbinom-rbinom-in-r\/"},"modified":"2023-07-29T20:18:10","modified_gmt":"2023-07-29T20:18:10","slug":"dbinom-pbinom-qbinom-rbinom-in-r","status":"publish","type":"post","link":"https:\/\/statorials.org\/ja\/dbinom-pbinom-qbinom-rbinom-in-r\/","title":{"rendered":"R \u306e dbinom\u3001pbinom\u3001qbinom\u3001rbinom \u306e\u30ac\u30a4\u30c9"},"content":{"rendered":"

<\/p>\n

\n

\u3053\u306e\u30c1\u30e5\u30fc\u30c8\u30ea\u30a2\u30eb\u3067\u306f\u3001\u95a2\u6570dbinom<\/strong> \u3001 pbinom<\/strong> \u3001 qbinom<\/strong> \u3001\u304a\u3088\u3073rbinom<\/strong>\u3092\u4f7f\u7528\u3057\u3066 R \u3067\u4e8c\u9805\u5206\u5e03<\/a>\u3092\u4f7f\u7528\u3059\u308b\u65b9\u6cd5\u306b\u3064\u3044\u3066\u8aac\u660e\u3057\u307e\u3059\u3002<\/span><\/p>\n

\u30c7\u30d3\u30ce\u30e0<\/span><\/strong><\/h2>\n

dbinom<\/b>\u95a2\u6570\u306f\u3001\u78ba\u7387\u5909\u6570x<\/em> \u3001\u8a66\u884c\u6570 (\u30b5\u30a4\u30ba)\u3001\u304a\u3088\u3073\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387 (\u78ba\u7387) \u3092\u8003\u616e\u3057\u305f\u4e8c\u9805\u5206\u5e03\u306e\u78ba\u7387\u5bc6\u5ea6\u95a2\u6570 (pdf) \u306e\u5024\u3092\u8fd4\u3057\u307e\u3059\u3002 dbinom \u3092\u4f7f\u7528\u3059\u308b\u305f\u3081\u306e\u69cb\u6587\u306f\u6b21\u306e\u3068\u304a\u308a\u3067\u3059\u3002<\/span><\/p>\n

dbinom(x, \u30b5\u30a4\u30ba, \u78ba\u7387)<\/span><\/strong><\/p>\n

\u7c21\u5358\u306b\u8a00\u3046\u3068\u3001 dbinom \u306f<\/b>\u7279\u5b9a\u306e\u6570\u306e\u30c7\u30fc\u30bf\u3092\u53d6\u5f97\u3059\u308b\u78ba\u7387\u3092\u6c42\u3081\u307e\u3059\u3002  <\/em>\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387\u304c\u56fa\u5b9a\u3055\u308c\u3066\u3044\u308b(prob)<\/strong>\u5834\u5408\u3001\u7279\u5b9a\u306e\u8a66\u884c\u6570(\u30b5\u30a4\u30ba)<\/strong>\u3067\u306e\u6210\u529f(x)<\/strong> \u3002<\/span><\/p>\n

\u6b21\u306e\u4f8b\u306f\u3001dbinom \u3092\u4f7f\u7528\u3057\u3066\u3044\u304f\u3064\u304b\u306e\u78ba\u7387\u306e\u554f\u984c\u3092\u89e3\u304f\u65b9\u6cd5\u3092\u793a\u3057\u3066\u3044\u307e\u3059\u3002<\/span><\/p>\n

\u4f8b 1:<\/strong>\u30dc\u30d6\u306f\u30d5\u30ea\u30fc\u30b9\u30ed\u30fc\u8a66\u6295\u306e 60% \u3092\u6210\u529f\u3055\u305b\u307e\u3059\u3002\u5f7c\u304c\u30d5\u30ea\u30fc\u30b9\u30ed\u30fc\u3092 12 \u56de\u6210\u529f\u3055\u305b\u305f\u5834\u5408\u3001\u3061\u3087\u3046\u3069 10 \u56de\u6210\u529f\u3059\u308b\u78ba\u7387\u306f\u3069\u308c\u304f\u3089\u3044\u3067\u3059\u304b?<\/em><\/span><\/p>\n

 #find the probability of 10 successes during 12 trials where the probability of\n#success on each trial is 0.6<\/span>\ndbinom(x=10, size=12, prob=.6)\n#[1]0.06385228\n<\/strong><\/pre>\n
\u5f7c\u304c\u3061\u3087\u3046\u3069 10 \u767a\u306e\u30b7\u30e7\u30c3\u30c8\u3092\u6253\u3064\u78ba\u7387\u306f0.0639<\/strong>\u3067\u3059\u3002<\/span><\/p>\n
\u4f8b 2:<\/strong>\u30b5\u30fc\u30b7\u30e3\u306f\u516c\u6b63\u306a\u30b3\u30a4\u30f3\u3092 20 \u56de\u6295\u3052\u307e\u3059\u3002\u30b3\u30a4\u30f3\u304c\u3061\u3087\u3046\u3069 7 \u3064\u306e\u8868\u3092\u51fa\u3059\u78ba\u7387\u306f\u3069\u308c\u304f\u3089\u3044\u3067\u3059\u304b?<\/em><\/span><\/p>\n
 #find the probability of 7 successes during 20 trials where the probability of\n#success on each trial is 0.5\n<\/span>dbinom(x=7, size=20, prob=.5)\n#[1]0.07392883\n<\/strong><\/pre>\n
\u30b3\u30a4\u30f3\u304c\u3061\u3087\u3046\u3069 7 \u56de\u8868\u306b\u306a\u308b\u78ba\u7387\u306f0.0739<\/strong>\u3067\u3059\u3002<\/span><\/p>\n
\u30d4\u30ce\u30e0<\/span><\/strong><\/h2>\n
pbinom<\/b>\u95a2\u6570\u306f\u3001\u7279\u5b9a\u306e\u78ba\u7387\u5909\u6570q<\/em> \u3001\u8a66\u884c\u6570 (\u30b5\u30a4\u30ba)\u3001\u304a\u3088\u3073\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387 (\u78ba\u7387) \u3092\u8003\u616e\u3057\u305f\u4e8c\u9805\u5206\u5e03\u306e\u7d2f\u7a4d\u5bc6\u5ea6\u95a2\u6570 (cdf) \u306e\u5024\u3092\u8fd4\u3057\u307e\u3059\u3002 pbinom \u3092\u4f7f\u7528\u3059\u308b\u305f\u3081\u306e\u69cb\u6587\u306f\u6b21\u306e\u3068\u304a\u308a\u3067\u3059\u3002<\/span><\/p>\n
 pbinom(q, \u30b5\u30a4\u30ba, \u78ba\u7387)<\/span><\/strong><\/p>\n
\u7c21\u5358\u306b\u8a00\u3048\u3070\u3001 pbinom \u306f<\/b>\u6307\u5b9a\u3055\u308c\u305fq<\/em>\u5024\u306e\u5de6\u5074\u306e\u9818\u57df\u3092\u8fd4\u3057\u307e\u3059\u3002  <\/em>\u4e8c\u9805\u5206\u5e03\u3067\u3002\u7279\u5b9a\u306eq<\/em>\u5024\u306e\u53f3\u5074\u306e\u9818\u57df\u306b\u8208\u5473\u304c\u3042\u308b\u5834\u5408\u306f\u3001\u5f15\u6570lower.tail = FALSE<\/strong>\u3092\u8ffd\u52a0\u3059\u308b\u3060\u3051\u3067\u3059\u3002<\/span><\/p>\n
 pbinom(q, \u30b5\u30a4\u30ba, \u78ba\u7387, lower.tail = FALSE)<\/span><\/strong><\/p>\n
\u6b21\u306e\u4f8b\u306f\u3001pbinom \u3092\u4f7f\u7528\u3057\u3066\u3044\u304f\u3064\u304b\u306e\u78ba\u7387\u306e\u554f\u984c\u3092\u89e3\u304f\u65b9\u6cd5\u3092\u793a\u3057\u3066\u3044\u307e\u3059\u3002<\/span><\/p>\n
\u4f8b 1:<\/strong>\u5b89\u85e4\u306f\u516c\u6b63\u306a\u30b3\u30a4\u30f3\u3092 5 \u56de\u6295\u3052\u307e\u3059\u3002\u30b3\u30a4\u30f3\u306e\u8868\u304c 2 \u56de\u4ee5\u4e0a\u51fa\u308b\u78ba\u7387\u306f\u3069\u308c\u304f\u3089\u3044\u3067\u3059\u304b?<\/em><\/span><\/p>\n
 #find the probability of more than 2 successes during 5 trials where the\n#probability of success on each trial is 0.5<\/span>\npbinom(2, size=5, prob=.5, lower.tail=FALSE)\n# [1] 0.5<\/span><\/span><\/strong><\/pre>\n
\u30b3\u30a4\u30f3\u304c 2 \u56de\u4ee5\u4e0a\u8868\u306b\u306a\u308b\u78ba\u7387\u306f0.5<\/strong>\u3067\u3059\u3002<\/span><\/p>\n
\u4f8b 2:<\/strong>\u30bf\u30a4\u30e9\u30fc\u304c\u30d7\u30ec\u30fc\u4e2d\u306b\u8a66\u884c\u306e 30% \u3067\u30b9\u30c8\u30e9\u30a4\u30af\u3092\u7372\u5f97\u3057\u305f\u3068\u3057\u307e\u3059\u3002\u5f7c\u304c 10 \u56de\u30d7\u30ec\u30fc\u3057\u305f\u5834\u5408\u3001\u30b9\u30c8\u30e9\u30a4\u30af\u304c 4 \u3064\u4ee5\u4e0b\u306b\u306a\u308b\u78ba\u7387\u306f\u3069\u308c\u304f\u3089\u3044\u3067\u3059\u304b?<\/em><\/span><\/p>\n
 #find the probability of 4 or fewer successes during 10 trials where the\n#probability of success on each trial is 0.3<\/span>\npbinom(4, size=10, prob=.3)\n# [1]0.8497317<\/span><\/span><\/strong><\/pre>\n
\u5f7c\u304c 4 \u30b9\u30c8\u30e9\u30a4\u30af\u4ee5\u4e0b\u3092\u7372\u5f97\u3059\u308b\u78ba\u7387\u306f0.8497<\/strong>\u3067\u3059\u3002<\/span><\/p>\n
\u30af\u30d3\u30ce\u30e0<\/span><\/strong><\/h2>\n
qbinom<\/b>\u95a2\u6570\u306f\u3001\u7279\u5b9a\u306e\u78ba\u7387\u5909\u6570q<\/em> \u3001\u8a66\u884c\u56de\u6570 (\u30b5\u30a4\u30ba)\u3001\u304a\u3088\u3073\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387 (\u78ba\u7387) \u3092\u6307\u5b9a\u3057\u305f\u5834\u5408\u306e\u4e8c\u9805\u5206\u5e03\u306e\u9006\u7d2f\u7a4d\u5bc6\u5ea6\u95a2\u6570 (cdf) \u306e\u5024\u3092\u8fd4\u3057\u307e\u3059\u3002 qbinom \u3092\u4f7f\u7528\u3059\u308b\u305f\u3081\u306e\u69cb\u6587\u306f\u6b21\u306e\u3068\u304a\u308a\u3067\u3059\u3002<\/span><\/p>\n
 qbinom(q, \u30b5\u30a4\u30ba, \u78ba\u7387)<\/span><\/strong><\/p>\n
\u7c21\u5358\u306b\u8a00\u3048\u3070\u3001 qbinom<\/strong>\u3092\u4f7f\u7528\u3057\u3066\u4e8c\u9805\u5206\u5e03\u306e p \u756a\u76ee\u306e\u5206<\/sup>\u4f4d\u6570\u3092\u898b\u3064\u3051\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/span><\/p>\n
\u6b21\u306e\u30b3\u30fc\u30c9\u306f\u3001 qbinom<\/b>\u306e\u52d5\u4f5c\u4f8b\u3092\u3044\u304f\u3064\u304b\u793a\u3057\u3066\u3044\u307e\u3059\u3002<\/span><\/p>\n
 #find the 10th quantile of a binomial distribution with 10 trials and prob\n#of success on each trial = 0.4\n<\/span>qbinom(.10, size=10, prob=.4)\n# [1] 2\n\n#find the 40th quantile of a binomial distribution with 30 trials and prob\n#of success on each trial = 0.25<\/span>\nqbinom(.40, size=30, prob=.25)\n# [1] 7\n<\/span><\/span><\/strong><\/pre>\n
\u30eb\u30d3\u30ce\u30e0<\/span><\/strong><\/h2>\n
\u95a2\u6570rbinom<\/b>\u306f\u3001\u30d9\u30af\u30c8\u30eb\u9577n<\/em> \u3001\u8a66\u884c\u6570 (\u30b5\u30a4\u30ba)\u3001\u304a\u3088\u3073\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387 (\u78ba\u7387) \u3092\u6307\u5b9a\u3057\u3066\u3001\u4e8c\u9805\u5206\u5e03\u78ba\u7387\u5909\u6570\u306e\u30d9\u30af\u30c8\u30eb\u3092\u751f\u6210\u3057\u307e\u3059\u3002 rbinom \u3092\u4f7f\u7528\u3059\u308b\u305f\u3081\u306e\u69cb\u6587\u306f\u6b21\u306e\u3068\u304a\u308a\u3067\u3059\u3002<\/span><\/p>\n
 rbinom(n, \u30b5\u30a4\u30ba, \u78ba\u7387)<\/span><\/strong><\/p>\n
\u6b21\u306e\u30b3\u30fc\u30c9\u306f\u3001 rnorm<\/strong>\u306e\u52d5\u4f5c\u4f8b\u3092\u3044\u304f\u3064\u304b\u793a\u3057\u3066\u3044\u307e\u3059\u3002<\/span><\/p>\n
 #generate a vector that shows the number of successes of 10 binomial experiments with\n#100 trials where the probability of success on each trial is 0.3.\n<\/span>results <- rbinom(10, size=100, prob=.3)\nresults\n# [1] 31 29 28 30 35 30 27 39 30 28\n\n#find mean number of successes in the 10 experiments (compared to expected<\/span>\n#mean of 30)<\/span>\nmean(results)\n# [1] 32.8\n\n<\/span>#generate a vector that shows the number of successes of 1000 binomial experiments\n#with 100 trials where the probability of success on each trial is 0.3.\nresults <- rbinom(1000, size=100, prob=.3)<\/span>\n\n#find mean number of successes in the 100 experiments (compared to expected\n#mean of 30)\nmean(results)<\/span>\n# [1] 30.105\n<\/span><\/span><\/span><\/span><\/strong><\/pre>\n
\u4f5c\u6210\u3059\u308b\u78ba\u7387\u5909\u6570\u306e\u6570\u304c\u5897\u3048\u308b\u307b\u3069\u3001\u5e73\u5747\u6210\u529f\u6570\u304c\u4e88\u60f3\u3055\u308c\u308b\u6210\u529f\u6570\u306b\u8fd1\u3065\u304f\u3053\u3068\u306b\u6ce8\u610f\u3057\u3066\u304f\u3060\u3055\u3044\u3002<\/span><\/p>\n
\u6ce8: \u300c\u671f\u5f85\u3055\u308c\u308b\u6210\u529f\u6570\u300d = n<\/strong> * p<\/strong>\u3053\u3053\u3067\u3001 n<\/strong>\u306f\u8a66\u884c\u56de\u6570\u3001 p<\/strong>\u306f\u5404\u8a66\u884c\u306e\u6210\u529f\u78ba\u7387\u3067\u3059\u3002<\/em><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"
\u3053\u306e\u30c1\u30e5\u30fc\u30c8\u30ea\u30a2\u30eb\u3067\u306f\u3001\u95a2\u6570dbinom \u3001 pbinom \u3001 qbinom \u3001\u304a\u3088\u3073rbinom\u3092\u4f7f\u7528\u3057\u3066 R \u3067\u4e8c\u9805\u5206\u5e03\u3092\u4f7f\u7528\u3059\u308b\u65b9\u6cd5\u306b\u3064\u3044\u3066\u8aac\u660e\u3057\u307e\u3059\u3002 \u30c7\u30d3\u30ce\u30e0 dbinom\u95a2\u6570\u306f\u3001\u78ba\u7387\u5909\u6570x \u3001\u8a66\u884c\u6570 (\u30b5\u30a4\u30ba […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[16],"tags":[],"class_list":["post-458","post","type-post","status-publish","format-standard","hentry","category-16"],"yoast_head":"\nR \u306e dbinom\u3001pbinom\u3001qbinom\u3001rbinom \u306e\u30ac\u30a4\u30c9 - \u7d71\u8a08<\/title>\n<meta name=\"description\" content=\"R \u306e dbinom\u3001pbinom\u3001qbinom\u3001rbinom \u95a2\u6570\u306e\u7c21\u5358\u306a\u30ac\u30a4\u30c9\u3002\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/ja\/dbinom-pbinom-qbinom-rbinom-in-r\/\" \/>\n<meta property=\"og:locale\" content=\"ja_JP\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"R \u306e dbinom\u3001pbinom\u3001qbinom\u3001rbinom \u306e\u30ac\u30a4\u30c9 - 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