{"id":1294,"date":"2023-07-26T23:35:44","date_gmt":"2023-07-26T23:35:44","guid":{"rendered":"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/"},"modified":"2023-07-26T23:35:44","modified_gmt":"2023-07-26T23:35:44","slug":"odleglosc-hamminga-pythona","status":"publish","type":"post","link":"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/","title":{"rendered":"Jak obliczy\u0107 odleg\u0142o\u015b\u0107 hamminga w pythonie (z przyk\u0142adami)"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\"><strong>Odleg\u0142o\u015b\u0107 Hamminga<\/strong> mi\u0119dzy dwoma wektorami jest po prostu sum\u0105 odpowiednich element\u00f3w, kt\u00f3re r\u00f3\u017cni\u0105 si\u0119 mi\u0119dzy wektorami.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Za\u0142\u00f3\u017cmy na przyk\u0142ad, \u017ce mamy nast\u0119puj\u0105ce dwa wektory:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>x = [1, 2, 3, 4]\n\ny = [1, 2, 5, 7]\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwoma wektorami wyniesie <strong>2<\/strong> , poniewa\u017c jest to ca\u0142kowita liczba pasuj\u0105cych element\u00f3w o r\u00f3\u017cnych warto\u015bciach.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Aby obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tablicami w Pythonie, mo\u017cemy u\u017cy\u0107 funkcji <a href=\"https:\/\/docs.scipy.org\/doc\/scipy\/reference\/generated\/scipy.spatial.distance.hamming.html\" target=\"_blank\" rel=\"noopener\">hamming()<\/a> z biblioteki scipy.spatial.distance, kt\u00f3ra wykorzystuje nast\u0119puj\u0105c\u0105 sk\u0142adni\u0119:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>scipy. <span style=\"color: #3366ff;\">spatial<\/span> . <span style=\"color: #3366ff;\">distance<\/span> . <span style=\"color: #3366ff;\">hamming<\/span> (array1, array2)<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Nale\u017cy pami\u0119ta\u0107, \u017ce ta funkcja zwraca <strong>procent<\/strong> pasuj\u0105cych element\u00f3w, kt\u00f3re r\u00f3\u017cni\u0105 si\u0119 w obu tablicach.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Zatem, aby otrzyma\u0107 odleg\u0142o\u015b\u0107 Hamminga, mo\u017cemy po prostu pomno\u017cy\u0107 przez d\u0142ugo\u015b\u0107 jednej z tabel:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>scipy. <span style=\"color: #3366ff;\">spatial<\/span> . <span style=\"color: #3366ff;\">distance<\/span> . <span style=\"color: #3366ff;\">hamming<\/span> (array1, array2) * <span style=\"color: #3366ff;\">len<\/span> (array1)<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">W tym samouczku przedstawiono kilka przyk\u0142ad\u00f3w praktycznego wykorzystania tej funkcji.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Przyk\u0142ad 1: Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy tablicami binarnymi<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">Poni\u017cszy kod pokazuje, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tablicami, z kt\u00f3rych ka\u017cda zawiera tylko dwie mo\u017cliwe warto\u015bci:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008000;\">from<\/span> scipy. <span style=\"color: #3366ff;\">spatial<\/span> . <span style=\"color: #3366ff;\">distance<\/span> <span style=\"color: #008000;\">import<\/span> hamming\n\n<span style=\"color: #008080;\">#define arrays\n<\/span>x = [0, 1, 1, 1, 0, 1]\ny = [0, 0, 1, 1, 0, 0]\n\n<span style=\"color: #008080;\">#calculate Hamming distance between the two arrays\n<\/span>hamming(x, y) * <span style=\"color: #3366ff;\">len<\/span> (x)\n\n2.0\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tabelami wynosi <strong>2<\/strong> .<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Przyk\u0142ad 2: Odleg\u0142o\u015b\u0107 Hamminga pomi\u0119dzy tablicami numerycznymi<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">Poni\u017cszy kod pokazuje, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tablicami, z kt\u00f3rych ka\u017cda zawiera kilka warto\u015bci liczbowych:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008000;\">from<\/span> scipy. <span style=\"color: #3366ff;\">spatial<\/span> . <span style=\"color: #3366ff;\">distance<\/span> <span style=\"color: #008000;\">import<\/span> hamming\n\n<span style=\"color: #008080;\">#define arrays\n<\/span>x = [7, 12, 14, 19, 22]\ny = [7, 12, 16, 26, 27]\n\n<span style=\"color: #008080;\">#calculate Hamming distance between the two arrays\n<\/span>hamming(x, y) * <span style=\"color: #3366ff;\">len<\/span> (x)\n\n3.0<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwoma tabelami wynosi <strong>3<\/strong> .<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Przyk\u0142ad 3: Odleg\u0142o\u015b\u0107 Hamminga pomi\u0119dzy tablicami strun<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">Poni\u017cszy kod pokazuje, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tablicami, z kt\u00f3rych ka\u017cda zawiera kilka warto\u015bci znakowych:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #008000;\">from<\/span> <span style=\"color: #000000;\">scipy.<\/span> <span style=\"color: #3366ff;\">spatial<\/span> . <span style=\"color: #3366ff;\">distance<\/span> <span style=\"color: #008000;\">import<\/span> <span style=\"color: #000000;\">hamming<\/span> \n\n#define arrays\n<\/span>x = ['a', 'b', 'c', 'd']\ny = ['a', 'b', 'c', 'r']\n\n<span style=\"color: #008080;\">#calculate Hamming distance between the two arrays\n<\/span>hamming(x, y) * <span style=\"color: #3366ff;\">len<\/span> (x)\n\n1.0\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwiema tabelami wynosi <strong>1<\/strong> .<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Dodatkowe zasoby<\/strong><\/span><\/h3>\n<p> <a href=\"https:\/\/statorials.org\/pl\/pyton-odleg\u0142osci-euklidesowej\/\" target=\"_blank\" rel=\"noopener\">Jak obliczy\u0107 odleg\u0142o\u015b\u0107 euklidesow\u0105 w Pythonie<\/a><br \/> <a href=\"https:\/\/statorials.org\/pl\/zdalny-pyton-mahalanobisa\/\" target=\"_blank\" rel=\"noopener\">Jak obliczy\u0107 odleg\u0142o\u015b\u0107 Mahalanobisa w Pythonie<\/a><br \/> <a href=\"https:\/\/statorials.org\/pl\/python-podobienstwa-jaccarda\/\" target=\"_blank\" rel=\"noopener\">Jak obliczy\u0107 podobie\u0144stwo Jaccarda w Pythonie<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwoma wektorami jest po prostu sum\u0105 odpowiednich element\u00f3w, kt\u00f3re r\u00f3\u017cni\u0105 si\u0119 mi\u0119dzy wektorami. Za\u0142\u00f3\u017cmy na przyk\u0142ad, \u017ce mamy nast\u0119puj\u0105ce dwa wektory: x = [1, 2, 3, 4] y = [1, 2, 5, 7] Odleg\u0142o\u015b\u0107 Hamminga mi\u0119dzy dwoma wektorami wyniesie 2 , poniewa\u017c jest to ca\u0142kowita liczba pasuj\u0105cych element\u00f3w o r\u00f3\u017cnych warto\u015bciach. Aby [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"class_list":["post-1294","post","type-post","status-publish","format-standard","hentry","category-przewodnik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie (z przyk\u0142adami)<\/title>\n<meta name=\"description\" content=\"W tym samouczku wyja\u015bniono, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie, podaj\u0105c kilka przyk\u0142ad\u00f3w.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/\" \/>\n<meta property=\"og:locale\" content=\"pl_PL\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie (z przyk\u0142adami)\" \/>\n<meta property=\"og:description\" content=\"W tym samouczku wyja\u015bniono, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie, podaj\u0105c kilka przyk\u0142ad\u00f3w.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/\" \/>\n<meta property=\"og:site_name\" content=\"Statorials\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-26T23:35:44+00:00\" \/>\n<meta name=\"author\" content=\"Benjamin Anderson\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Napisane przez\" \/>\n\t<meta name=\"twitter:data1\" content=\"Benjamin Anderson\" \/>\n\t<meta name=\"twitter:label2\" content=\"Szacowany czas czytania\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minuty\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/\",\"url\":\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/\",\"name\":\"Jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie (z przyk\u0142adami)\",\"isPartOf\":{\"@id\":\"https:\/\/statorials.org\/pl\/#website\"},\"datePublished\":\"2023-07-26T23:35:44+00:00\",\"dateModified\":\"2023-07-26T23:35:44+00:00\",\"author\":{\"@id\":\"https:\/\/statorials.org\/pl\/#\/schema\/person\/6484727a4612df3e69f016c3129c6965\"},\"description\":\"W tym samouczku wyja\u015bniono, jak obliczy\u0107 odleg\u0142o\u015b\u0107 Hamminga w Pythonie, podaj\u0105c kilka przyk\u0142ad\u00f3w.\",\"breadcrumb\":{\"@id\":\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/#breadcrumb\"},\"inLanguage\":\"pl-PL\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/statorials.org\/pl\/odleglosc-hamminga-pythona\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Dom\",\"item\":\"https:\/\/statorials.org\/pl\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Jak obliczy\u0107 odleg\u0142o\u015b\u0107 hamminga w pythonie (z przyk\u0142adami)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/statorials.org\/pl\/#website\",\"url\":\"https:\/\/statorials.org\/pl\/\",\"name\":\"Statorials\",\"description\":\"Tw\u00f3j przewodnik po kompetencjach statystycznych!\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/statorials.org\/pl\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pl-PL\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/statorials.org\/pl\/#\/schema\/person\/6484727a4612df3e69f016c3129c6965\",\"name\":\"Benjamin Anderson\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pl-PL\",\"@id\":\"https:\/\/statorials.org\/pl\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/statorials.org\/pl\/wp-content\/uploads\/2023\/11\/Benjamin-Anderson-96x96.jpg\",\"contentUrl\":\"https:\/\/statorials.org\/pl\/wp-content\/uploads\/2023\/11\/Benjamin-Anderson-96x96.jpg\",\"caption\":\"Benjamin Anderson\"},\"description\":\"Cze\u015b\u0107, jestem Benjamin i jestem emerytowanym profesorem statystyki, kt\u00f3ry zosta\u0142 oddanym nauczycielem Statorials. 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