{"id":2515,"date":"2023-07-21T22:43:02","date_gmt":"2023-07-21T22:43:02","guid":{"rendered":"https:\/\/statorials.org\/pt\/compartimentacao-de-dados-em-r\/"},"modified":"2023-07-21T22:43:02","modified_gmt":"2023-07-21T22:43:02","slug":"compartimentacao-de-dados-em-r","status":"publish","type":"post","link":"https:\/\/statorials.org\/pt\/compartimentacao-de-dados-em-r\/","title":{"rendered":"Como realizar agrupamento de dados em r: com exemplos"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\">Voc\u00ea pode usar um dos dois m\u00e9todos para realizar o agrupamento de dados em R:<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>M\u00e9todo 1: use a fun\u00e7\u00e3o cut()<\/strong><\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #107d3f;\">library<\/span> (dplyr)\n\n<span style=\"color: #008080;\">#perform binning with custom breaks<\/span>\ndf %&gt;% mutate(new_bin = cut(variable_name, breaks=c(0, 10, 20, 30)))\n\n<span style=\"color: #008080;\">#perform binning with specific number of bins\n<\/span>df %&gt;% mutate(new_bin = cut(variable_name, breaks= <span style=\"color: #008000;\">3<\/span> ))\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\"><strong>M\u00e9todo 2: use a fun\u00e7\u00e3o ntile()<\/strong><\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #107d3f;\">library<\/span> (dplyr)\n\n<span style=\"color: #008080;\">#perform binning with specific number of bins<\/span>\ndf %&gt;% mutate(new_bin = ntile(variable_name, n= <span style=\"color: #008000;\">3<\/span> ))\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Os exemplos a seguir mostram como usar cada m\u00e9todo na pr\u00e1tica com o seguinte quadro de dados:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\">#create data frame\n<span style=\"color: #000000;\">df &lt;- data. <span style=\"color: #3366ff;\">frame<\/span> (points=c(4, 4, 7, 8, 12, 13, 15, 18, 22, 23, 23, 25),\n                 assists=c(2, 5, 4, 7, 7, 8, 5, 4, 5, 11, 13, 8),\n                 rebounds=c(7, 7, 4, 6, 3, 8, 9, 9, 12, 11, 8, 9))\n\n<span style=\"color: #008080;\">#view head of data frame\n<\/span>head(df)\n\n  points assists rebounds\n1 4 2 7\n2 4 5 7\n3 7 4 4\n4 8 7 6\n5 12 7 3\n6 13 8 8<\/span><\/span><\/strong><\/pre>\n<h3> <span style=\"color: #000000;\"><strong>Exemplo 1: Realize o agrupamento de dados com a fun\u00e7\u00e3o cut()<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">O c\u00f3digo a seguir mostra como realizar o agrupamento de dados na vari\u00e1vel <strong>points<\/strong> usando a fun\u00e7\u00e3o <strong>cut()<\/strong> com marcas de quebra espec\u00edficas:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #000000;\"><span style=\"color: #008000;\">library<\/span> (dplyr)\n\n<span style=\"color: #008080;\">#perform data binning on variable <em>points<\/em>\n<\/span>df %&gt;% mutate(points_bin = cut(points, breaks=c(0, 10, 20, 30)))\n\n   points assists rebounds points_bin\n1 4 2 7 (0.10]\n2 4 5 7 (0.10]\n3 7 4 4 (0.10]\n4 8 7 6 (0.10]\n5 12 7 3 (10.20]\n6 13 8 8 (10.20]\n7 15 5 9 (10.20]\n8 18 4 9 (10.20]\n9 22 5 12 (20.30]\n10 23 11 11 (20.30]\n11 23 13 8 (20.30]\n12 25 8 9 (20.30]\n<\/span><\/span><\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Observe que cada linha no quadro de dados foi colocada em um dos tr\u00eas grupos com base no valor da coluna de pontos.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Tamb\u00e9m poder\u00edamos especificar o n\u00famero de saltos a serem usados para criar caixas de igual largura indo do valor m\u00ednimo ao valor m\u00e1ximo da coluna <strong>de pontos<\/strong> :<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #000000;\"><span style=\"color: #008000;\">library<\/span> (dplyr)\n\n<span style=\"color: #008080;\">#perform data binning on variable <em>points<\/em>\n<\/span>df %&gt;% mutate(points_bin = cut(points, breaks= <span style=\"color: #008000;\">3<\/span> ))\n\n   points assists rebounds points_bin\n1 4 2 7 (3.98.11]\n2 4 5 7 (3.98.11]\n3 7 4 4 (3.98.11]\n4 8 7 6 (3.98.11]\n5 12 7 3 (11.18]\n6 13 8 8 (11.18]\n7 15 5 9 (11.18]\n8 18 4 9 (11.18]\n9 22 5 12 (18.25]\n10 23 11 11 (18.25]\n11 23 13 8 (18.25]\n12 25 8 9 (18.25]\n<\/span><\/span><\/strong><\/pre>\n<h3> <span style=\"color: #000000;\"><strong>Exemplo 2:<\/strong><\/span> <span style=\"color: #000000;\"><strong>Execute o agrupamento de dados com a fun\u00e7\u00e3o ntile()<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">O c\u00f3digo a seguir mostra como realizar o agrupamento de dados na vari\u00e1vel <strong>points<\/strong> usando a fun\u00e7\u00e3o <strong>ntile()<\/strong> com um n\u00famero espec\u00edfico de grupos resultantes:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #000000;\"><span style=\"color: #008000;\">library<\/span> (dplyr)\n\n<span style=\"color: #008080;\">#perform data binning on variable <em>points<\/em>\n<\/span>df %&gt;% mutate(points_bin = ntile(points, n= <span style=\"color: #008000;\">3<\/span> ))\n\n   points assists rebounds points_bin\n1 4 2 7 1\n2 4 5 7 1\n3 7 4 4 1\n4 8 7 6 1\n5 12 7 3 2\n6 13 8 8 2\n7 15 5 9 2\n8 18 4 9 2\n9 22 5 12 3\n10 23 11 11 3\n11 23 13 8 3\n12 25 8 9 3\n<\/span><\/span><\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Observe que cada linha recebeu uma caixa de 1 a 3 com base no valor da coluna <strong>de pontos<\/strong> .<\/span><\/p>\n<p> <span style=\"color: #000000;\">\u00c9 melhor usar a fun\u00e7\u00e3o <strong>ntile()<\/strong> quando desejar que um valor inteiro seja exibido em cada linha em vez de um intervalo indicando o intervalo da caixa.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Recursos adicionais<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">Os tutoriais a seguir explicam como realizar outras tarefas comuns em R:<\/span><\/p>\n<p> <a href=\"https:\/\/statorials.org\/pt\/r-substitui-valores-no-quadro-de-dados-condicionalmente\/\" target=\"_blank\" rel=\"noopener\">Como substituir condicionalmente valores no quadro de dados em R<\/a><br \/> <a href=\"https:\/\/statorials.org\/pt\/media-de-r-truncado\/\" target=\"_blank\" rel=\"noopener\">Como calcular uma m\u00e9dia aparada em R<\/a><br \/> <a href=\"https:\/\/statorials.org\/pt\/media-condicional-em-r\/\" target=\"_blank\" rel=\"noopener\">Como calcular a m\u00e9dia condicional em R<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Voc\u00ea pode usar um dos dois m\u00e9todos para realizar o agrupamento de dados em R: M\u00e9todo 1: use a fun\u00e7\u00e3o cut() library (dplyr) #perform binning with custom breaks df %&gt;% mutate(new_bin = cut(variable_name, breaks=c(0, 10, 20, 30))) #perform binning with specific number of bins df %&gt;% mutate(new_bin = cut(variable_name, breaks= 3 )) M\u00e9todo 2: use [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2515","post","type-post","status-publish","format-standard","hentry","category-guia"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Como realizar clustering de dados em R (com exemplos) - Estatoriais<\/title>\n<meta name=\"description\" content=\"Este tutorial explica como realizar agrupamento de dados em R, com v\u00e1rios exemplos.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" 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