{"id":391,"date":"2023-08-01T05:30:46","date_gmt":"2023-08-01T05:30:46","guid":{"rendered":"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/"},"modified":"2023-08-01T05:30:46","modified_gmt":"2023-08-01T05:30:46","slug":"probabilidade-de-intersecao-de-eventos","status":"publish","type":"post","link":"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/","title":{"rendered":"Probabilidade de intersec\u00e7\u00e3o de eventos"},"content":{"rendered":"<p>Este artigo explica como calcular a probabilidade de intersec\u00e7\u00e3o de eventos. Assim voc\u00ea descobrir\u00e1 qual \u00e9 a f\u00f3rmula da probabilidade de intersec\u00e7\u00e3o de eventos e, al\u00e9m disso, exerc\u00edcios resolvidos passo a passo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-la-interseccion-de-sucesos\"><\/span> Qual \u00e9 a intersec\u00e7\u00e3o de eventos?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Na teoria das probabilidades, a <strong>intersec\u00e7\u00e3o de eventos<\/strong> \u00e9 uma opera\u00e7\u00e3o de eventos cujo resultado \u00e9 composto por eventos elementares comuns a todos os eventos da opera\u00e7\u00e3o. Ou seja, a intersec\u00e7\u00e3o dos eventos A e B \u00e9 formada por todos os eventos que pertencem a A e B ao mesmo tempo.<\/p>\n<p> A interse\u00e7\u00e3o de dois eventos \u00e9 expressa pelo s\u00edmbolo \u22c2. Assim, a interse\u00e7\u00e3o dos eventos A e B \u00e9 escrita A\u22c2B.<\/p>\n<p> Por exemplo, no experimento aleat\u00f3rio de lan\u00e7ar um dado, se um evento \u00e9 que um n\u00famero par \u00e9 lan\u00e7ado A={2, 4, 6} e outro evento \u00e9 que um n\u00famero maior que tr\u00eas \u00e9 lan\u00e7ado B={4, 5, 6}, a interse\u00e7\u00e3o dos dois eventos \u00e9 A\u22c2B={4, 6}. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"formula-de-la-probabilidad-de-la-interseccion-de-sucesos\"><\/span> F\u00f3rmula para a probabilidade de intersec\u00e7\u00e3o de eventos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A <strong>probabilidade de intersec\u00e7\u00e3o de dois eventos<\/strong> \u00e9 igual \u00e0 probabilidade de um evento ocorrer vezes a probabilidade condicional de o outro evento ocorrer, dado o primeiro evento.<\/p>\n<p> Portanto, a <strong>f\u00f3rmula para a probabilidade de intersec\u00e7\u00e3o de dois eventos<\/strong> \u00e9 P(A\u22c2B)=P(A) P(B|A)=P(B) P(A|B).<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-acadb606c53d2237406ab492ad5c26ff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)=P(A)\\cdot P(B|A)=P(B)\\cdot P(A|B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"350\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:7px\"> Ouro:<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-816b613a4f79d4bf9cb51396a9654120_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-c74288aabc0e2ca280d25d92bf1a1ec2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"B\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> Esses s\u00e3o dois eventos dependentes.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-5e28c16735c6423d27941ce417b5fb4e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade da interse\u00e7\u00e3o do evento A e do evento B.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-f0e9e218bb5d81f21881e6c57e37c7a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"40\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade de que o evento A ocorra.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-4c0c4ce70731e4b1321acc93f53679ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(B|A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"59\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade condicional de o evento B ocorrer dado o evento A.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-3cf84b3bfcc955798a43fce91458ff42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"41\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade de que o evento B ocorra.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-aa17d530df1f8fd53a077cb6af545add_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A|B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"59\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade condicional do evento A ocorrer dado o evento B. <\/li>\n<\/ul>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 20px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/statorials.org\/pt\/probabilidade-condicional-condicional\/\">Probabilidade condicional (ou probabilidade condicional)<\/a><\/div>\n<p> No entanto, se os dois eventos forem independentes, isso significa que a probabilidade de um evento ocorrer n\u00e3o depende da ocorr\u00eancia do outro evento. Portanto, a f\u00f3rmula para a probabilidade de intersec\u00e7\u00e3o dos dois eventos independentes \u00e9 a seguinte:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-593a1a131cab23d805d8324e21e6b4ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)=P(A)\\cdot P(B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"193\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:7px\"> Ouro:<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-816b613a4f79d4bf9cb51396a9654120_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-c74288aabc0e2ca280d25d92bf1a1ec2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"B\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> Estes s\u00e3o dois eventos independentes.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-5e28c16735c6423d27941ce417b5fb4e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade da intersec\u00e7\u00e3o do evento evento A e evento B.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-f0e9e218bb5d81f21881e6c57e37c7a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"40\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade de que o evento A ocorra.<\/li>\n<li style=\"margin-bottom:8px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-3cf84b3bfcc955798a43fce91458ff42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"41\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e9 a probabilidade de que o evento B ocorra. <\/li>\n<\/ul>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 20px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/statorials.org\/pt\/eventos-eventos-independentes\/\">Eventos Independentes<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplos-resueltos-de-la-probabilidad-de-la-interseccion-de-sucesos\"><\/span> Exemplos do mundo real de probabilidade de intersec\u00e7\u00e3o de eventos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A seguir, deixamos dois exemplos resolvidos passo a passo para que voc\u00ea possa ver como \u00e9 calculada a probabilidade de intersec\u00e7\u00e3o de dois eventos. Veremos primeiro um exemplo da intersec\u00e7\u00e3o de dois acontecimentos independentes e depois de dois acontecimentos dependentes, para que possa ver ambos os casos. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"probabilidad-de-la-interseccion-de-dos-sucesos-independientes\"><\/span> Probabilidade da intersec\u00e7\u00e3o de dois eventos independentes<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li> Um sorteio \u00e9 lan\u00e7ado tr\u00eas vezes consecutivas. Encontre a probabilidade de obter cara nos tr\u00eas lan\u00e7amentos.<\/li>\n<\/ul>\n<p> Neste caso, os eventos para os quais queremos calcular a probabilidade conjunta s\u00e3o independentes, pois o resultado de um empate n\u00e3o depende do resultado obtido no sorteio anterior. Portanto, para determinar a probabilidade de obter tr\u00eas caras consecutivas, devemos usar a f\u00f3rmula de probabilidade de interse\u00e7\u00e3o para eventos independentes:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-593a1a131cab23d805d8324e21e6b4ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)=P(A)\\cdot P(B)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"193\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> No sorteio, existem apenas dois resultados poss\u00edveis, podemos obter cara ou coroa. Portanto, a probabilidade de obter cara ou coroa no lan\u00e7amento de uma moeda \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-24700638f62e83613a39f2b566e2fb9c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(\\text{cara})=\\cfrac{1}{2}=0,5\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"143\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Portanto, para encontrar a probabilidade de obter cara em todos os tr\u00eas lan\u00e7amentos de moeda, precisamos multiplicar a probabilidade de obter cara por tr\u00eas:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-54abe4c41545eb6e46fd1cf97f8a3253_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}P(\\text{cara}\\cap \\text{cara}\\cap \\text{cara})&amp;=P(\\text{cara})\\cdot P(\\text{cara})\\cdot P(\\text{cara})\\\\[2ex]&amp;=0,5\\cdot 0,5\\cdot 0,5\\\\[2ex]&amp;=0,125\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"102\" width=\"394\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Resumindo, a probabilidade de obter cara tr\u00eas vezes seguidas \u00e9 de 12,5%. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"probabilidad-de-la-interseccion-de-dos-sucesos-dependientes\"><\/span> Probabilidade da intersec\u00e7\u00e3o de dois eventos dependentes<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li> Numa caixa vazia colocamos 8 bolas azuis, 4 bolas laranja e 2 bolas verdes. Se tirarmos primeiro uma bola e depois outra bola sem colocar a primeira bola retirada de volta na caixa, qual \u00e9 a probabilidade de a primeira bola ser azul e a segunda bola laranja?<\/li>\n<\/ul>\n<p> Nesse caso, os eventos s\u00e3o dependentes, pois a probabilidade de pegar uma bola laranja no segundo sorteio depende da cor da bola sorteada no primeiro sorteio. Portanto, para calcular a probabilidade que o problema nos pede, devemos utilizar a f\u00f3rmula da probabilidade de interse\u00e7\u00e3o para eventos dependentes:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-dddb39f8c7ff49e40025c3aae59044d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(A\\cap B)=P(A)\\cdot P(B|A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"211\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> A probabilidade de obter uma bola azul no primeiro sorteio \u00e9 f\u00e1cil de determinar, bastando dividir o n\u00famero de bolas azuis pelo n\u00famero total de bolas:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-01c2ac51c56664735750a0821834727d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(\\text{bola azul})=\\cfrac{8}{8+4+2}=\\cfrac{8}{14}=0,57\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"295\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Por outro lado, a probabilidade de tirar uma bola laranja depois de tirar uma bola azul \u00e9 calculada de forma diferente porque o n\u00famero de bolas laranja \u00e9 diferente e, al\u00e9m disso, h\u00e1 agora uma bola a menos dentro da caixa:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-a4dfda0193e549c67dabe2e6065d84f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(\\text{bola naranja}|\\text{bola azul})=\\cfrac{4}{7+4+2}=\\cfrac{4}{13}=0,31\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"397\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Assim, a probabilidade de tirar primeiro uma bola azul e depois uma bola laranja \u00e9 calculada multiplicando as duas probabilidades encontradas acima: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-94896f8575aeb7e73cc056595920fedb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}P(\\text{bola azul}\\cap\\text{bola naranja})=\\\\[2ex]=P(\\text{bola azul})\\cdot P(\\text{bola naranja}|\\text{bola azul})=\\\\[2ex]=0,57\\cdot 0,31= \\\\[2ex]=0,18\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"130\" width=\"348\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 20px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/statorials.org\/pt\/probabilidade-da-uniao-de-eventos\/\">Probabilidade de uni\u00e3o de eventos<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"propiedades-de-la-interseccion-de-sucesos\"><\/span> Propriedades de interse\u00e7\u00e3o de eventos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Na teoria das probabilidades, a intersec\u00e7\u00e3o de eventos tem as seguintes propriedades:<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Propriedade comutativa:<\/strong> A ordem dos eventos de interse\u00e7\u00e3o n\u00e3o altera o resultado da opera\u00e7\u00e3o.<\/span><\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-bf8f77ee754a8baedd35ff8cd79fbbd1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\\cap B=B\\cap A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"118\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Propriedade associativa:<\/strong> A intersec\u00e7\u00e3o de tr\u00eas eventos pode ser calculada em qualquer ordem, desde que o resultado seja o mesmo.<\/span><\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-fb1da58ec6bf1f24f459a5edf91507eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(A\\cap B)\\cap C=A\\cap (B\\cap C)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"211\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Propriedade distributiva:<\/strong> a intersec\u00e7\u00e3o de eventos satisfaz a propriedade distributiva na uni\u00e3o de eventos.<\/span> <\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-e43f1e4d6e688179f911a63ac3b46789_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\\cap (B\\cup C)=(A\\cap B)\\cup (A\\cap C)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"259\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 20px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/statorials.org\/pt\/operacoes-com-eventos\/\">Opera\u00e7\u00f5es com eventos<\/a><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica como calcular a probabilidade de intersec\u00e7\u00e3o de eventos. Assim voc\u00ea descobrir\u00e1 qual \u00e9 a f\u00f3rmula da probabilidade de intersec\u00e7\u00e3o de eventos e, al\u00e9m disso, exerc\u00edcios resolvidos passo a passo. Qual \u00e9 a intersec\u00e7\u00e3o de eventos? Na teoria das probabilidades, a intersec\u00e7\u00e3o de eventos \u00e9 uma opera\u00e7\u00e3o de eventos cujo resultado \u00e9 composto [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"class_list":["post-391","post","type-post","status-publish","format-standard","hentry","category-probabilidade"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Probabilidade de intersec\u00e7\u00e3o de eventos<\/title>\n<meta name=\"description\" content=\"Aqui voc\u00ea aprender\u00e1 o que \u00e9 interse\u00e7\u00e3o de eventos, como calcular a probabilidade de interse\u00e7\u00e3o de eventos (f\u00f3rmula) e exemplos resolvidos.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/\" \/>\n<meta property=\"og:locale\" content=\"pt_PT\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 Probabilidade de intersec\u00e7\u00e3o de eventos\" \/>\n<meta property=\"og:description\" content=\"Aqui voc\u00ea aprender\u00e1 o que \u00e9 interse\u00e7\u00e3o de eventos, como calcular a probabilidade de interse\u00e7\u00e3o de eventos (f\u00f3rmula) e exemplos resolvidos.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/\" \/>\n<meta property=\"og:site_name\" content=\"Statorials\" \/>\n<meta property=\"article:published_time\" content=\"2023-08-01T05:30:46+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/statorials.org\/wp-content\/ql-cache\/quicklatex.com-acadb606c53d2237406ab492ad5c26ff_l3.png\" \/>\n<meta name=\"author\" content=\"Dr. benjamim anderson\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Dr. benjamim anderson\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tempo estimado de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"4 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/\",\"url\":\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/\",\"name\":\"\u25b7 Probabilidade de intersec\u00e7\u00e3o de eventos\",\"isPartOf\":{\"@id\":\"https:\/\/statorials.org\/pt\/#website\"},\"datePublished\":\"2023-08-01T05:30:46+00:00\",\"dateModified\":\"2023-08-01T05:30:46+00:00\",\"author\":{\"@id\":\"https:\/\/statorials.org\/pt\/#\/schema\/person\/e08f98e8db95e0aa9c310e1b27c9c666\"},\"description\":\"Aqui voc\u00ea aprender\u00e1 o que \u00e9 interse\u00e7\u00e3o de eventos, como calcular a probabilidade de interse\u00e7\u00e3o de eventos (f\u00f3rmula) e exemplos resolvidos.\",\"breadcrumb\":{\"@id\":\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/#breadcrumb\"},\"inLanguage\":\"pt-PT\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/statorials.org\/pt\/probabilidade-de-intersecao-de-eventos\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Lar\",\"item\":\"https:\/\/statorials.org\/pt\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Probabilidade de intersec\u00e7\u00e3o de eventos\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/statorials.org\/pt\/#website\",\"url\":\"https:\/\/statorials.org\/pt\/\",\"name\":\"Statorials\",\"description\":\"O seu guia para a literacia estat\u00edstica!\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/statorials.org\/pt\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-PT\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/statorials.org\/pt\/#\/schema\/person\/e08f98e8db95e0aa9c310e1b27c9c666\",\"name\":\"Dr. benjamim anderson\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-PT\",\"@id\":\"https:\/\/statorials.org\/pt\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/statorials.org\/pt\/wp-content\/uploads\/2023\/10\/Dr.-Benjamin-Anderson-96x96.jpg\",\"contentUrl\":\"https:\/\/statorials.org\/pt\/wp-content\/uploads\/2023\/10\/Dr.-Benjamin-Anderson-96x96.jpg\",\"caption\":\"Dr. benjamim anderson\"},\"description\":\"Ol\u00e1, sou Benjamin, um professor aposentado de estat\u00edstica que se tornou professor dedicado na Statorials. 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