{"id":1083,"date":"2023-07-27T17:45:27","date_gmt":"2023-07-27T17:45:27","guid":{"rendered":"https:\/\/statorials.org\/tr\/rdeki-birden-fazla-sutundaki-aykiri-degerleri-kaldirin\/"},"modified":"2023-07-27T17:45:27","modified_gmt":"2023-07-27T17:45:27","slug":"rdeki-birden-fazla-sutundaki-aykiri-degerleri-kaldirin","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/rdeki-birden-fazla-sutundaki-aykiri-degerleri-kaldirin\/","title":{"rendered":"R&#39;deki birden fazla s\u00fctundan ayk\u0131r\u0131 de\u011ferler nas\u0131l kald\u0131r\u0131l\u0131r"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\">Genellikle R&#8217;de birden fazla s\u00fctundaki ayk\u0131r\u0131 de\u011ferleri ayn\u0131 anda kald\u0131rmak isteyebilirsiniz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bir g\u00f6zlemi ayk\u0131r\u0131 de\u011fer olarak tan\u0131mlaman\u0131n yayg\u0131n bir yolu, \u00fc\u00e7\u00fcnc\u00fc \u00e7eyre\u011fin (Q3) \u00e7eyrekler aras\u0131 aral\u0131\u011f\u0131n\u0131n 1,5 kat\u0131 veya birinci \u00e7eyre\u011fin (Q1) alt\u0131ndaki \u00e7eyrekler aras\u0131 aral\u0131\u011f\u0131n 1,5 kat\u0131 olmas\u0131d\u0131r.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bu tan\u0131m\u0131 kullanarak, ayk\u0131r\u0131 de\u011ferleri tan\u0131mlamak i\u00e7in basit bir i\u015flev olu\u015fturmak ve ard\u0131ndan bu i\u015flevi bir R veri \u00e7er\u00e7evesindeki birden \u00e7ok s\u00fctuna uygulamak i\u00e7in a\u015fa\u011f\u0131daki ad\u0131mlar\u0131 kullanabiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>Ad\u0131m 1: Bir veri \u00e7er\u00e7evesi olu\u015fturun.<\/strong><\/span><\/p>\n<p> <span style=\"color: #000000;\">R&#8217;de bir veri \u00e7er\u00e7evesi olu\u015fturarak ba\u015flayal\u0131m:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>df &lt;- data.frame(index=c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10),\n                 var1=c(4, 4, 5, 4, 3, 2, 8, 9, 4, 5),\n                 var2=c(1, 2, 4, 4, 6, 9, 7, 8, 5, 29),\n                 var3=c(9, 9, 9, 5, 5, 3, 4, 5, 11, 34))\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\"><strong>Ad\u0131m 2: Ayk\u0131r\u0131 de\u011fer fonksiyonunu tan\u0131mlay\u0131n.<\/strong><\/span><\/p>\n<p> <span style=\"color: #000000;\">Sonra, ayk\u0131r\u0131 de\u011ferleri tan\u0131mlayabilen ve daha sonra ayk\u0131r\u0131 de\u011ferleri kald\u0131rabilen bir i\u015flev tan\u0131mlayal\u0131m:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>outliers &lt;- <span style=\"color: #008000;\">function<\/span> (x) {\n\n  Q1 &lt;- quantile(x, <span style=\"color: #3366ff;\">probs<\/span> =.25)\n  Q3 &lt;- quantile(x, <span style=\"color: #3366ff;\">probs<\/span> =.75)\n  iqr = Q3-Q1\n\n upper_limit = Q3 + (iqr*1.5)\n lower_limit = Q1 - (iqr*1.5)\n\n x &gt; upper_limit | x &lt; lower_limit\n}\n\nremove_outliers &lt;- <span style=\"color: #008000;\">function<\/span> (df, cols = <span style=\"color: #3366ff;\">names<\/span> (df)) {\n  for (col <span style=\"color: #008000;\">in<\/span> cols) {\n    df &lt;- df[!outliers(df[[col]]),]\n  }\n  df\n}<\/strong><\/pre>\n<p> <span style=\"color: #000000;\"><strong>Ad\u0131m 3: Ayk\u0131r\u0131 de\u011fer fonksiyonunu veri \u00e7er\u00e7evesine uygulay\u0131n.<\/strong><\/span><\/p>\n<p> <span style=\"color: #000000;\">Son olarak, ayk\u0131r\u0131 de\u011ferleri kald\u0131rmak i\u00e7in bu i\u015flevi veri \u00e7er\u00e7evesinin birka\u00e7 s\u00fctununa uygulayal\u0131m:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>remove_outliers(df, c('var1', 'var2', 'var3'))\n\n  index var1 var2 var3\n1 1 4 1 9\n2 2 4 2 9\n3 3 5 4 9\n4 4 4 4 5\n5 5 3 6 5\n9 9 4 5 11\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\"><em>Daha fazla R e\u011fitimini burada bulabilirsiniz.<\/em><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Genellikle R&#8217;de birden fazla s\u00fctundaki ayk\u0131r\u0131 de\u011ferleri ayn\u0131 anda kald\u0131rmak isteyebilirsiniz. Bir g\u00f6zlemi ayk\u0131r\u0131 de\u011fer olarak tan\u0131mlaman\u0131n yayg\u0131n bir yolu, \u00fc\u00e7\u00fcnc\u00fc \u00e7eyre\u011fin (Q3) \u00e7eyrekler aras\u0131 aral\u0131\u011f\u0131n\u0131n 1,5 kat\u0131 veya birinci \u00e7eyre\u011fin (Q1) alt\u0131ndaki \u00e7eyrekler aras\u0131 aral\u0131\u011f\u0131n 1,5 kat\u0131 olmas\u0131d\u0131r. Bu tan\u0131m\u0131 kullanarak, ayk\u0131r\u0131 de\u011ferleri tan\u0131mlamak i\u00e7in basit bir i\u015flev olu\u015fturmak ve ard\u0131ndan bu i\u015flevi bir [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-1083","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>R&#039;deki birden fazla s\u00fctundan ayk\u0131r\u0131 de\u011ferler nas\u0131l kald\u0131r\u0131l\u0131r<\/title>\n<meta name=\"description\" content=\"R&#039;de birden fazla s\u00fctundaki ayk\u0131r\u0131 de\u011ferlerin ayn\u0131 anda nas\u0131l kald\u0131r\u0131laca\u011f\u0131na dair basit bir a\u00e7\u0131klama.\" \/>\n<meta name=\"robots\" content=\"index, follow, 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