<\/p>\n
\u00c7o\u011funlukla R’deki iki s\u00fctunu kar\u015f\u0131la\u015ft\u0131rmak ve kar\u015f\u0131la\u015ft\u0131rma sonu\u00e7lar\u0131n\u0131 \u00fc\u00e7\u00fcnc\u00fc bir s\u00fctuna yazmak isteyebilirsiniz.<\/span><\/p>\n A\u015fa\u011f\u0131daki s\u00f6zdizimini kullanarak bunu kolayca yapabilirsiniz:<\/span><\/p>\n Bu tek sat\u0131rl\u0131k kod a\u015fa\u011f\u0131dakileri yapar:<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnekte bu kodun pratikte nas\u0131l kullan\u0131laca\u011f\u0131 g\u00f6sterilmektedir.<\/span><\/p>\n \u0130ki futbol tak\u0131m\u0131n\u0131n be\u015f farkl\u0131 ma\u00e7ta att\u0131\u011f\u0131 gol say\u0131s\u0131n\u0131 g\u00f6steren a\u015fa\u011f\u0131daki veri \u00e7er\u00e7evesine sahip oldu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n Sat\u0131r ba\u015f\u0131na gol say\u0131s\u0131n\u0131 kar\u015f\u0131la\u015ft\u0131rmak ve ma\u00e7\u0131n galibini \u00fc\u00e7\u00fcnc\u00fc bir s\u00fctunda g\u00f6r\u00fcnt\u00fclemek i\u00e7in a\u015fa\u011f\u0131daki kodu kullanabiliriz:<\/span><\/p>\n Kar\u015f\u0131la\u015ft\u0131rma sonu\u00e7lar\u0131 kazanan<\/em> ad\u0131 verilen yeni s\u00fctunda g\u00f6r\u00fcnt\u00fclenir.<\/span><\/p>\n R’de veri \u00e7er\u00e7evesi s\u00fctunlar\u0131 nas\u0131l istiflenir<\/a> \u00c7o\u011funlukla R’deki iki s\u00fctunu kar\u015f\u0131la\u015ft\u0131rmak ve kar\u015f\u0131la\u015ft\u0131rma sonu\u00e7lar\u0131n\u0131 \u00fc\u00e7\u00fcnc\u00fc bir s\u00fctuna yazmak isteyebilirsiniz. A\u015fa\u011f\u0131daki s\u00f6zdizimini kullanarak bunu kolayca yapabilirsiniz: df$ new_col <- ifelse (df$ col1 > df$ col2 , ‘ A ‘, ifelse (df$ col1 < df$ col2 , ‘ B ‘, ‘ C ‘)) Bu tek sat\u0131rl\u0131k kod a\u015fa\u011f\u0131dakileri yapar: 1. s\u00fctun 2. s\u00fctundan […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-1087","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n df$ new_col<\/span> <- ifelse<\/span> (df$ col1<\/span> ><\/span> df$ col2<\/span> , ' A<\/span> ',\nifelse<\/span> (df$ col1<\/span> <<\/span> df$ col2<\/span> , ' B<\/span> ', ' C<\/span> '))\n<\/strong><\/pre>\n\n
\u00d6rnek: R’deki iki s\u00fctunu kar\u015f\u0131la\u015ft\u0131r\u0131n<\/strong><\/span><\/h3>\n
#create data frame<\/span>\ndf <- data.frame(A_points=c(1, 3, 3, 3, 5),\n B_points=c(4, 5, 2, 3, 2))\n\n#view data frame<\/span>\ndf\n\n A_points B_points\n1 1 4\n2 3 5\n3 3 2\n4 3 3\n5 5 2\n<\/strong><\/pre>\n #compare A_points<\/em> and B_points<\/em> and output results to new column titled winner<\/em><\/span>\ndf$winner <- ifelse<\/span> (df$A_points ><\/span> df$B_points, ' A<\/span> ',\n ifelse<\/span> (df$A_points <<\/span> df$B_points, ' B<\/span> ', ' Tie<\/span> '))\n\n#view data frame<\/span>\ndf\n\n A_points B_points winner\n1 1 4 B\n2 3 5 B\n3 3 2 A\n4 3 3 Tie\n5 5 2 A<\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
R’de iki s\u00fctun bir s\u00fctunda nas\u0131l birle\u015ftirilir<\/a>
R’de s\u00fctun adlar\u0131 \u00fczerinde yineleme nas\u0131l yap\u0131l\u0131r<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"