{"id":1615,"date":"2023-07-25T15:51:22","date_gmt":"2023-07-25T15:51:22","guid":{"rendered":"https:\/\/statorials.org\/tr\/balikcilar-arasindaki-en-az-anlamli-fark\/"},"modified":"2023-07-25T15:51:22","modified_gmt":"2023-07-25T15:51:22","slug":"balikcilar-arasindaki-en-az-anlamli-fark","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/balikcilar-arasindaki-en-az-anlamli-fark\/","title":{"rendered":"Fisher&#39;\u0131n en az \u00f6nemli fark\u0131: tan\u0131m + \u00f6rnek"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\">\u00dc\u00e7 veya daha fazla ba\u011f\u0131ms\u0131z grubun ortalamalar\u0131 aras\u0131nda istatistiksel olarak anlaml\u0131 bir fark olup olmad\u0131\u011f\u0131n\u0131 belirlemek i\u00e7in <a href=\"https:\/\/statorials.org\/tr\/tek-yonlu-anova\/\" target=\"_blank\" rel=\"noopener\">tek y\u00f6nl\u00fc ANOVA<\/a> kullan\u0131l\u0131r.<\/span><\/p>\n<p> <span style=\"color: #000000;\">ANOVA&#8217;da kullan\u0131lan varsay\u0131mlar a\u015fa\u011f\u0131daki gibidir:<\/span><\/p>\n<p> <span style=\"color: #000000;\">H <sub>0<\/sub> : Ortalamalar her grup i\u00e7in e\u015fittir.<\/span><\/p>\n<p> <span style=\"color: #000000;\">H <sub>A<\/sub> : En az\u0131ndan yollardan biri di\u011ferlerinden farkl\u0131.<\/span><\/p>\n<p> <span style=\"color: #000000;\">ANOVA&#8217;n\u0131n p de\u011feri belirli bir anlaml\u0131l\u0131k d\u00fczeyinin alt\u0131ndaysa (\u03b1 = 0,05 gibi), s\u0131f\u0131r hipotezini reddedebilir ve grup ortalamalar\u0131ndan en az birinin di\u011ferlerinden farkl\u0131 oldu\u011fu sonucuna varabiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ancak hangi gruplar\u0131n birbirinden farkl\u0131 oldu\u011funu tam olarak bilmek i\u00e7in post-hoc bir test yapmam\u0131z gerekiyor.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Yayg\u0131n olarak kullan\u0131lan bir post-hoc testi, <strong>Fisher&#8217;in en az anlaml\u0131 fark testidir<\/strong> .<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bu testi ger\u00e7ekle\u015ftirmek i\u00e7in \u00f6ncelikle a\u015fa\u011f\u0131daki test istatisti\u011fini hesapl\u0131yoruz:<\/span><\/p>\n<p> <strong><span style=\"color: #000000;\">LSD = t <sub>0,025<\/sub> , <sub>DF <sub>w<\/sub><\/sub> * \u221a <span style=\"border-top: 1px solid black;\">MS <sub>W<\/sub> (1\/n <sub>1<\/sub> + 1\/n <sub>1<\/sub> )<\/span><\/span><\/strong><\/p>\n<p> <span style=\"color: #000000;\">Alt\u0131n:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\"><strong>t<\/strong> <strong><sub>.025<\/sub> , <sub>DFw<\/sub> :<\/strong> \u03b1 = .025 ve DF <sub>w<\/sub> ile t da\u011f\u0131l\u0131m tablosunun t-kritik de\u011feri, ANOVA tablosunun gruplar\u0131 i\u00e7indeki serbestlik derecelerine kar\u015f\u0131l\u0131k gelir.<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>MS <sub>W<\/sub> :<\/strong> ANOVA tablosundaki gruplar i\u00e7indeki ortalama kareler.<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>n <sub>1<\/sub> , n <sub>2<\/sub> :<\/strong> Her grubun \u00f6rneklem b\u00fcy\u00fckl\u00fckleri<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Daha sonra her grup aras\u0131ndaki ortalama fark\u0131 bu test istatisti\u011fiyle kar\u015f\u0131la\u015ft\u0131rabiliriz. \u0130ki grup aras\u0131ndaki ortalama fark\u0131n mutlak de\u011feri test istatisti\u011finden b\u00fcy\u00fckse grup ortalamalar\u0131 aras\u0131nda istatistiksel olarak anlaml\u0131 bir fark oldu\u011funu s\u00f6yleyebiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki \u00f6rnek, Fisher&#8217;in en az anlaml\u0131 fark testinin pratikte nas\u0131l ger\u00e7ekle\u015ftirilece\u011fini g\u00f6stermektedir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>\u00d6rnek: Fisher En Az Anlaml\u0131 Fark Testi<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">Bir profes\u00f6r\u00fcn, \u00fc\u00e7 farkl\u0131 \u00e7al\u0131\u015fma tekni\u011finin \u00f6\u011frenciler aras\u0131nda farkl\u0131 test puanlar\u0131na yol a\u00e7\u0131p a\u00e7mad\u0131\u011f\u0131n\u0131 bilmek istedi\u011fini varsayal\u0131m. Bunu test etmek i\u00e7in rastgele 10 \u00f6\u011frenciyi her \u00e7al\u0131\u015fma tekni\u011fini kullanmalar\u0131 i\u00e7in g\u00f6revlendiriyor ve s\u0131nav sonu\u00e7lar\u0131n\u0131 kaydediyor.<\/span><\/p>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki tablo,<\/span> <span style=\"color: #000000;\">kullan\u0131lan \u00e7al\u0131\u015fma tekni\u011fine g\u00f6re her \u00f6\u011frencinin s\u0131nav sonu\u00e7lar\u0131n\u0131 g\u00f6sterir:<\/span> <\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\" wp-image-16018 aligncenter\" src=\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/moinssigdiff1.png\" alt=\"\" width=\"267\" height=\"287\" srcset=\"\" sizes=\"auto, \"><\/p>\n<p> <span style=\"color: #000000;\">Profes\u00f6r tek y\u00f6nl\u00fc bir ANOVA ger\u00e7ekle\u015ftirir ve a\u015fa\u011f\u0131daki sonu\u00e7lar\u0131 elde eder:<\/span> <\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\" wp-image-16019 aligncenter\" src=\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/moinssigdiff2.png\" alt=\"\" width=\"547\" height=\"314\" srcset=\"\" sizes=\"auto, \"><\/p>\n<p> <span style=\"color: #000000;\">ANOVA tablosundaki p de\u011feri (0,018771) 0,05&#8217;ten k\u00fc\u00e7\u00fck oldu\u011fundan, \u00fc\u00e7 grup aras\u0131ndaki ortalama s\u0131nav puanlar\u0131n\u0131n hepsinin e\u015fit olmad\u0131\u011f\u0131 sonucuna varabiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Dolay\u0131s\u0131yla hangi grup ortalamalar\u0131n\u0131n farkl\u0131 oldu\u011funu belirlemek i\u00e7in Fisher&#8217;in en az anlaml\u0131 fark testini yapabiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">ANOVA sonucundaki de\u011ferleri kullanarak Fisher test istatisti\u011fini \u015fu \u015fekilde hesaplayabiliriz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">LSD = t <sub>0,025<\/sub> , <sub>DFw<\/sub> * \u221a <span style=\"border-top: 1px solid black;\">MS <sub>W<\/sub> (1\/n <sub>1<\/sub> + 1\/n <sub>1<\/sub> )<\/span><\/span><\/li>\n<li> <span style=\"color: #000000;\">LSD = t <sub>0,025<\/sub> , <sub>27<\/sub> * \u221a <span style=\"border-top: 1px solid black;\">36,948*(1\/10 + 1\/10)<\/span><\/span><\/li>\n<li> <span style=\"color: #000000;\">LSD = 2,052 * \u221a <span style=\"border-top: 1px solid black;\">7,3896<\/span><\/span><\/li>\n<li> <span style=\"color: #000000;\">LSD = <strong>5,578<\/strong><\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Daha sonra her grup aras\u0131ndaki mutlak ortalama fark\u0131 hesaplayabiliriz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">Teknik 1&#8217;e kar\u015f\u0131 Teknik 2: |80 \u2013 85.8| = <strong>5,8<\/strong><\/span><\/li>\n<li> <span style=\"color: #000000;\">Teknik 1 ve Teknik 3: |80 \u2013 88| = <strong>8<\/strong><\/span><\/li>\n<li> <span style=\"color: #000000;\">Teknik 2 ve Teknik 3: |85.8 \u2013 88| = <strong>2,2<\/strong><\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Teknik 1 ile teknik 2 ve teknik 1 ile teknik 3 aras\u0131ndaki mutlak ortalama farklar Fisher testi istatistiklerinden daha b\u00fcy\u00fckt\u00fcr. Dolay\u0131s\u0131yla bu tekniklerin istatistiksel olarak anlaml\u0131 derecede farkl\u0131 ortalama s\u0131nav puanlar\u0131na yol a\u00e7t\u0131\u011f\u0131 sonucuna varabiliriz.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ayr\u0131ca teknik 2 ile teknik 3 aras\u0131nda ortalama s\u0131nav puanlar\u0131 aras\u0131nda anlaml\u0131 bir fark olmad\u0131\u011f\u0131 sonucuna varabiliriz.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u00dc\u00e7 veya daha fazla ba\u011f\u0131ms\u0131z grubun ortalamalar\u0131 aras\u0131nda istatistiksel olarak anlaml\u0131 bir fark olup olmad\u0131\u011f\u0131n\u0131 belirlemek i\u00e7in tek y\u00f6nl\u00fc ANOVA kullan\u0131l\u0131r. ANOVA&#8217;da kullan\u0131lan varsay\u0131mlar a\u015fa\u011f\u0131daki gibidir: H 0 : Ortalamalar her grup i\u00e7in e\u015fittir. H A : En az\u0131ndan yollardan biri di\u011ferlerinden farkl\u0131. ANOVA&#8217;n\u0131n p de\u011feri belirli bir anlaml\u0131l\u0131k d\u00fczeyinin alt\u0131ndaysa (\u03b1 = 0,05 gibi), [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-1615","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Fisher&#039;\u0131n en az \u00f6nemli fark\u0131: tan\u0131m + \u00f6rnek<\/title>\n<meta name=\"description\" content=\"Bu e\u011fitim, bir tan\u0131m ve \u00f6rnek de dahil olmak \u00fczere Fisher&#039;in en az anlaml\u0131 fark\u0131n\u0131n (LSD) basit bir a\u00e7\u0131klamas\u0131n\u0131 sa\u011flar.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, 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