<\/p>\n
R’de kar\u015f\u0131la\u015fabilece\u011finiz yayg\u0131n bir hata:<\/span><\/p>\n Bu hata, var olmayan bir matrisin s\u00fctununa veya sat\u0131r\u0131na eri\u015fmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar.<\/span><\/p>\n Bu e\u011fitimde, a\u015fa\u011f\u0131daki matrisi \u00f6rnek olarak kullanarak bu hatay\u0131 \u00e7\u00f6zmek i\u00e7in uygulayabilece\u011finiz tam ad\u0131mlar g\u00f6sterilmektedir:<\/span><\/p>\n A\u015fa\u011f\u0131daki kod, matrisin mevcut olmayan 11. sat\u0131r\u0131na eri\u015fmeye \u00e7al\u0131\u015f\u0131r:<\/span><\/p>\n Matrisin 11. sat\u0131r\u0131 bulunmad\u0131\u011f\u0131ndan indeksin s\u0131n\u0131r d\u0131\u015f\u0131<\/strong> hatas\u0131 al\u0131yoruz.<\/span><\/p>\n Matriste ka\u00e7 sat\u0131r oldu\u011funu bilmiyorsak, bulmak i\u00e7in nrow()<\/strong> i\u015flevini kullanabiliriz:<\/span><\/p>\n Matriste sadece 10 sat\u0131r\u0131n oldu\u011funu g\u00f6rebiliriz. Yani sat\u0131rlara eri\u015fmek i\u00e7in yaln\u0131zca 10’dan k\u00fc\u00e7\u00fck veya ona e\u015fit say\u0131lar\u0131 kullanabiliriz.<\/span><\/p>\n \u00d6rne\u011fin matrisin 10. sat\u0131r\u0131n\u0131 g\u00f6r\u00fcnt\u00fclemek i\u00e7in a\u015fa\u011f\u0131daki s\u00f6zdizimini kullanabiliriz:<\/span><\/p>\n A\u015fa\u011f\u0131daki kod, matrisin mevcut olmayan 4. s\u00fctununa eri\u015fmeye \u00e7al\u0131\u015f\u0131r:<\/span><\/p>\n Matrisin 4. s\u00fctunu bulunmad\u0131\u011f\u0131ndan indeksin s\u0131n\u0131r d\u0131\u015f\u0131<\/strong> hatas\u0131 al\u0131yoruz.<\/span><\/p>\n Matrisin ka\u00e7 s\u00fctun i\u00e7erdi\u011fini bilmiyorsak, \u015funu bulmak i\u00e7in ncol()<\/strong> i\u015flevini kullanabiliriz:<\/span><\/p>\n Matriste sadece 3 s\u00fctunun oldu\u011funu g\u00f6r\u00fcyoruz. Bu nedenle s\u00fctunlara eri\u015fmek i\u00e7in yaln\u0131zca 3’ten k\u00fc\u00e7\u00fck veya ona e\u015fit say\u0131lar\u0131 kullanabiliriz.<\/span><\/p>\n \u00d6rne\u011fin matrisin 3. s\u00fctununu g\u00f6r\u00fcnt\u00fclemek i\u00e7in a\u015fa\u011f\u0131daki s\u00f6zdizimini kullanabiliriz:<\/span><\/p>\n A\u015fa\u011f\u0131daki kod, matrisin mevcut olmayan 11. sat\u0131r\u0131n\u0131n ve 4. s\u00fctununun de\u011ferine eri\u015fmeye \u00e7al\u0131\u015f\u0131r:<\/span><\/p>\n Matrisin ne 11. sat\u0131r\u0131 ne de 4. s\u00fctunu bulunmad\u0131\u011f\u0131ndan indeks s\u0131n\u0131r d\u0131\u015f\u0131<\/strong> hatas\u0131 al\u0131yoruz.<\/span><\/p>\n Matriste ka\u00e7 sat\u0131r ve s\u00fctun oldu\u011funu bilmiyorsak, \u015funu bulmak i\u00e7in dim()<\/strong> i\u015flevini kullanabiliriz:<\/span><\/p>\n Matriste sadece 10 sat\u0131r ve 3 s\u00fctun bulundu\u011funu g\u00f6r\u00fcyoruz. Yani sat\u0131r ve s\u00fctunlara eri\u015firken yaln\u0131zca bu de\u011ferlerden k\u00fc\u00e7\u00fck veya bu de\u011ferlere e\u015fit say\u0131lar\u0131 kullanabiliriz.<\/span><\/p>\n \u00d6rne\u011fin matrisin 10. sat\u0131r\u0131nda ve 3. s\u00fctununda yer alan de\u011feri g\u00f6r\u00fcnt\u00fclemek i\u00e7in a\u015fa\u011f\u0131daki s\u00f6zdizimini kullanabiliriz:<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’deki di\u011fer yayg\u0131n hatalar\u0131n nas\u0131l \u00e7\u00f6z\u00fclece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de nas\u0131l d\u00fczeltilir: Adlar \u00f6nceki adlarla e\u015fle\u015fmiyor<\/a> R’de kar\u015f\u0131la\u015fabilece\u011finiz yayg\u0131n bir hata: Error in x[, 4]: subscript out of bounds Bu hata, var olmayan bir matrisin s\u00fctununa veya sat\u0131r\u0131na eri\u015fmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar. Bu e\u011fitimde, a\u015fa\u011f\u0131daki matrisi \u00f6rnek olarak kullanarak bu hatay\u0131 \u00e7\u00f6zmek i\u00e7in uygulayabilece\u011finiz tam ad\u0131mlar g\u00f6sterilmektedir: #make this example reproducible set. seeds (0) #create matrix with 10 rows and 3 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-1772","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n Error in x[, 4]: subscript out of bounds\n<\/strong><\/pre>\n
#make this example reproducible<\/span>\nset. seeds<\/span> (0)\n\n#create matrix with 10 rows and 3 columns<\/span>\nx = matrix(data = sample. int<\/span> (100, 30), nrow = 10, ncol = 3)\n\n#print matrix\n<\/span>print<\/span> (x)\n\n [,1] [,2] [,3]\n [1,] 14 51 96\n [2,] 68 85 44\n [3,] 39 21 33\n [4,] 1 54 35\n [5,] 34 74 70\n [6,] 87 7 86\n [7,] 43 73 42\n [8,] 100 79 38\n [9,] 82 37 20\n[10,] 59 92 28\n<\/strong><\/pre>\n \u00d6rnek 1: aral\u0131k d\u0131\u015f\u0131nda dizin (\u00e7izgilerle)<\/strong><\/h3>\n
#attempt to display 11th row of matrix<\/span>\nx[11, ]\n\nError in x[11, ]: subscript out of bounds\n<\/strong><\/pre>\n #display number of rows in matrix<\/span>\nnrow(x)\n\n[1] 10\n<\/strong><\/pre>\n #display 10th row of matrix<\/span>\nx[10, ]\n\n[1] 59 92 28\n<\/strong><\/pre>\n \u00d6rnek #2: aral\u0131k d\u0131\u015f\u0131nda dizin (s\u00fctunlarla)<\/strong><\/h3>\n
#attempt to display 4th column of matrix<\/span>\nx[, 4]\n\nError in x[, 4]: subscript out of bounds\n<\/strong><\/pre>\n #display number of columns in matrix<\/span>\nncol(x)\n\n[1] 3\n<\/strong><\/pre>\n #display 3rd column of matrix<\/span>\nx[, 3]\n\n[1] 96 44 33 35 70 86 42 38 20 28<\/strong><\/pre>\n \u00d6rnek 3: aral\u0131k d\u0131\u015f\u0131nda dizin (sat\u0131rlar ve s\u00fctunlar)<\/strong><\/h3>\n
#attempt to display value in 11th row and 4th column<\/span>\nx[11, 4]\n\nError in x[11, 4]: subscript out of bounds\n<\/strong><\/pre>\n #display number of rows and columns in matrix<\/span>\ndim(x)\n\n[1] 10 3\n<\/strong><\/pre>\n #display value in 10th row and 3rd column of matrix<\/span>\nx[10, 3]\n\n[1] 28\n<\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
R’de nas\u0131l d\u00fczeltilir: daha uzun bir nesnenin uzunlu\u011fu, daha k\u0131sa bir nesnenin uzunlu\u011funun kat\u0131 de\u011fildir<\/a>
R’de nas\u0131l d\u00fczeltilir: kontrastlar yaln\u0131zca 2 veya daha fazla seviyeye sahip fakt\u00f6rlere uygulanabilir<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"