<\/p>\n
R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata:<\/span><\/p>\n Bu hata, bir vekt\u00f6r veya veri \u00e7er\u00e7evesi s\u00fctunundaki belirli say\u0131da \u00f6\u011feyi (3 \u00f6\u011fe varsayal\u0131m) farkl\u0131 say\u0131da \u00f6\u011feyle (6 \u00f6\u011fe varsayal\u0131m) de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar.<\/span><\/p>\n Bu e\u011fitimde bu hatan\u0131n nas\u0131l d\u00fczeltilece\u011fi tam olarak a\u00e7\u0131klanmaktad\u0131r.<\/span><\/p>\n R’de, ilk s\u00fctununda birka\u00e7 eksik de\u011fer bulunan a\u015fa\u011f\u0131daki veri \u00e7er\u00e7evesine sahip oldu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n \u015eimdi birinci s\u00fctundaki eksik de\u011ferleri ikinci s\u00fctundaki de\u011ferlerle de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131m\u0131z\u0131 varsayal\u0131m:<\/span><\/p>\n Birinci s\u00fctundaki eksik 3<\/strong> de\u011feri ikinci s\u00fctundaki 6<\/strong> de\u011ferle de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131m\u0131z i\u00e7in hata al\u0131yoruz.<\/span><\/p>\n Bu hatay\u0131 d\u00fczeltmenin en kolay yolu ifelse()<\/strong> ifadesini kullanmakt\u0131r:<\/span><\/p>\n Bu ifelse()<\/strong> ifadesi, \u201ca\u201d s\u00fctununun de\u011ferinin bo\u015f olup olmad\u0131\u011f\u0131n\u0131 kontrol eder. E\u011fer \u00f6yleyse, “b” s\u00fctunundaki kar\u015f\u0131l\u0131k gelen de\u011ferle de\u011fi\u015ftirilir, aksi takdirde tek ba\u015f\u0131na b\u0131rak\u0131l\u0131r.<\/span><\/p>\n Bu hatay\u0131 d\u00fczeltmenin ba\u015fka bir yolu da t\u00fcm eksik de\u011ferleri belirli bir say\u0131yla de\u011fi\u015ftirmektir:<\/span><\/p>\n Bu y\u00f6ntemi kullanarak “a” s\u00fctunundaki eksik de\u011ferlerin her biri s\u0131f\u0131rla de\u011fi\u015ftirilir.<\/span><\/p>\n R’de nas\u0131l d\u00fczeltilir: Zorlamayla ortaya \u00e7\u0131kan NA’lar<\/a> R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata: Warning message: number of items to replace is not a multiple of replacement length Bu hata, bir vekt\u00f6r veya veri \u00e7er\u00e7evesi s\u00fctunundaki belirli say\u0131da \u00f6\u011feyi (3 \u00f6\u011fe varsayal\u0131m) farkl\u0131 say\u0131da \u00f6\u011feyle (6 \u00f6\u011fe varsayal\u0131m) de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar. Bu e\u011fitimde bu hatan\u0131n nas\u0131l d\u00fczeltilece\u011fi tam olarak a\u00e7\u0131klanmaktad\u0131r. Hata nas\u0131l yeniden olu\u015fturulur? […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-1859","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n Warning message:\n number of items to replace is not a multiple of replacement length\n<\/strong><\/pre>\n
Hata nas\u0131l yeniden olu\u015fturulur?<\/strong><\/h3>\n
#create data frame\n<\/span>df <- data. frame<\/span> (a=c(3, NA, 7, NA, NA, 14),\n b=c(4, 4, 5, 12, 13, 18))\n\n#view data frame\n<\/span>df\n\n ab\n1 3 4\n2 NA 4\n3 7 5\n4 NA 12\n5 NA 13\n6 14 18<\/strong><\/pre>\n #attempt to replace missing values in first column with values in second column\n<\/span>df$a[is. na<\/span> (df$a)] <- df$b\n\nWarning message:\nIn df$a[is.na(df$a)] <- df$b:\n number of items to replace is not a multiple of replacement length\n<\/strong><\/pre>\n Hata nas\u0131l d\u00fczeltilir?<\/strong><\/span><\/h3>\n
#replace missing values in column 'a' with corresponding values in column 'b'\ndf$a <- ifelse(is. na<\/span> (df$a), df$b, df$a)\n<\/span>\n#view updated data frame\ndf\n\n ab\n1 3 4\n2 4 4\n3 7 5\n4 12 12\n5 13 13\n6 14 18<\/span><\/span><\/strong><\/pre>\n #replace all missing values in column 'a' with zero\ndf$a[is. na<\/span> (df$a)] <- 0\n<\/span>\n#view updated data frame\ndf\n\n ab\n1 3 4\n2 0 4\n3 7 5\n4 0 12\n5 0 13\n6 14 18<\/span><\/span><\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
R’de nas\u0131l onar\u0131l\u0131r: s\u0131n\u0131rlar\u0131n d\u0131\u015f\u0131nda dizin<\/a>
R’de nas\u0131l d\u00fczeltilir: daha uzun bir nesnenin uzunlu\u011fu, daha k\u0131sa bir nesnenin uzunlu\u011funun kat\u0131 de\u011fildir<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"