<\/p>\n
R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata:<\/span><\/p>\n Bu hata, bir vekt\u00f6rdeki bir de\u011feri “s\u0131f\u0131r uzunlu\u011fa sahip”, yani var olmayan ba\u015fka bir de\u011ferle de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar.<\/span><\/p>\n Bu e\u011fitimde bu hatan\u0131n nas\u0131l d\u00fczeltilece\u011fi tam olarak a\u00e7\u0131klanmaktad\u0131r.<\/span><\/p>\n R’de 10 de\u011fere sahip a\u015fa\u011f\u0131daki vekt\u00f6r\u00fc olu\u015fturdu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n \u015eimdi vekt\u00f6rdeki her de\u011feri kendisinden \u00f6nceki de\u011ferle \u00e7arpmak i\u00e7in a\u015fa\u011f\u0131daki for()<\/strong> d\u00f6ng\u00fcs\u00fcn\u00fc kullanmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131m\u0131z\u0131 varsayal\u0131m:<\/span><\/p>\n \u0130lk d\u00f6ng\u00fcde a\u015fa\u011f\u0131daki \u00e7arpma i\u015flemini ger\u00e7ekle\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131m\u0131z i\u00e7in ” de\u011fi\u015ftirme s\u0131f\u0131r uzunlu\u011fa sahip<\/strong> ” hatas\u0131n\u0131 al\u0131yoruz:<\/span><\/p>\n R indeksleri 1’den ba\u015flad\u0131\u011f\u0131 i\u00e7in data[0]<\/strong> de\u011feri mevcut de\u011fildir.<\/span><\/p>\n Bunu, vekt\u00f6r\u00fcn 0 konumunda bulunan de\u011feri yazd\u0131rmaya \u00e7al\u0131\u015farak kontrol edebiliriz:<\/span><\/p>\n Sonu\u00e7, uzunlu\u011fu 0 olan bir dijital vekt\u00f6rd\u00fcr; ba\u015fka bir deyi\u015fle mevcut de\u011fildir.<\/span><\/p>\n Bu hatay\u0131 d\u00fczeltmenin yolu, vekt\u00f6r\u00fcn var olmayan bir de\u011ferine eri\u015fmeye \u00e7al\u0131\u015fmayan bir for()<\/strong> d\u00f6ng\u00fcs\u00fcn\u00fc kullanmakt\u0131r.<\/span><\/p>\n \u00d6rne\u011fimizde for d\u00f6ng\u00fcs\u00fcn\u00fc 1. konum yerine 2. dizin konumunda ba\u015flatarak bu hatay\u0131 d\u00fczeltebiliriz:<\/span><\/p>\n Vekt\u00f6rde var olmayan bir indeks konumuna asla eri\u015fmeye \u00e7al\u0131\u015fmad\u0131\u011f\u0131m\u0131z i\u00e7in bir hata almad\u0131\u011f\u0131m\u0131z\u0131 unutmay\u0131n.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’deki di\u011fer yayg\u0131n hatalar\u0131n nas\u0131l d\u00fczeltilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n “Ko\u015fulun uzunlu\u011fu > 1 ve yaln\u0131zca ilk \u00f6\u011fe kullan\u0131lacak” sorununu d\u00fczeltme<\/a> R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata: Error in x[1] = x[0]: replacement has length zero Bu hata, bir vekt\u00f6rdeki bir de\u011feri “s\u0131f\u0131r uzunlu\u011fa sahip”, yani var olmayan ba\u015fka bir de\u011ferle de\u011fi\u015ftirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar. Bu e\u011fitimde bu hatan\u0131n nas\u0131l d\u00fczeltilece\u011fi tam olarak a\u00e7\u0131klanmaktad\u0131r. Hata nas\u0131l yeniden olu\u015fturulur? R’de 10 de\u011fere sahip a\u015fa\u011f\u0131daki vekt\u00f6r\u00fc olu\u015fturdu\u011fumuzu varsayal\u0131m: data = […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2053","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n Error in x[1] = x[0]: replacement has length zero\n<\/strong><\/pre>\n
Hata nas\u0131l yeniden olu\u015fturulur?<\/strong><\/h3>\n
data = c(1, 4, 5, 5, 7, 9, 12, 14, 15, 17)<\/span>\n<\/span><\/strong><\/span><\/pre>\n for<\/span> (i in<\/span> 1: length<\/span> (data)) {\n data[i] = data[i] * data[i-1]\n}\n\nError in data[i] <- data[i] * data[i - 1]: replacement has length zero\n<\/strong><\/span><\/pre>\n\n
print<\/span> (data[0])\n\nnumeric(0)<\/span>\n<\/span><\/strong><\/span><\/pre>\n Hata nas\u0131l d\u00fczeltilir?<\/strong><\/h3>\n
for<\/span> (i in<\/span> 2: length<\/span> (data)) {\n data[i] = data[i] * data[i-1]\n}\n\n#view updated vector<\/span>\ndata\n\n [1] 1 4 20 100 700 6300 75600\n [8] 1058400 15876000 269892000\n<\/strong><\/span><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
Nas\u0131l d\u00fczeltilir: De\u011fi\u015ftirmede X sat\u0131r var, veride Y var<\/a>
Nas\u0131l d\u00fczeltilir? \u0130kili operat\u00f6r\u00fcn say\u0131sal olmayan ba\u011f\u0131ms\u0131z de\u011fi\u015fkeni<\/a>
Nas\u0131l d\u00fczeltilir? dim(X) pozitif uzunlu\u011fa sahip olmal\u0131d\u0131r<\/a>
Nas\u0131l d\u00fczeltilir? Kullan\u0131lmayan ba\u011f\u0131ms\u0131z de\u011fi\u015fkenlerin se\u00e7ilmesinde hata<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"