<\/p>\n
Binom da\u011f\u0131l\u0131m\u0131,<\/a> sabit say\u0131da denemede meydana gelen belirli say\u0131da “ba\u015far\u0131” olas\u0131l\u0131\u011f\u0131n\u0131 modellemek i\u00e7in kullan\u0131lan bir olas\u0131l\u0131k da\u011f\u0131l\u0131m\u0131d\u0131r.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00fc\u00e7 varsay\u0131m kar\u015f\u0131lan\u0131rsa binom da\u011f\u0131l\u0131m\u0131n\u0131n kullan\u0131lmas\u0131 uygundur:<\/span><\/p>\n Varsay\u0131m 1: Her denemenin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r.<\/strong><\/span><\/p>\n Her denemenin yaln\u0131zca iki olas\u0131 sonucu oldu\u011funu varsay\u0131yoruz. \u00d6rne\u011fin, bir paray\u0131 100 kez atarsak, her seferinde yaln\u0131zca iki olas\u0131 sonu\u00e7 olabilir: yaz\u0131 veya tura.<\/span><\/p>\n Varsay\u0131m 2: Ba\u015far\u0131 olas\u0131l\u0131\u011f\u0131 her deneme i\u00e7in ayn\u0131d\u0131r.<\/strong><\/span><\/p>\n Her denemede \u201cba\u015far\u0131\u201d elde etme olas\u0131l\u0131\u011f\u0131n\u0131n ayn\u0131 oldu\u011funu varsay\u0131yoruz. \u00d6rne\u011fin, belirli bir at\u0131\u015fta paran\u0131n tura gelme olas\u0131l\u0131\u011f\u0131 0,5’tir. Bu olas\u0131l\u0131k bir beraberlikten di\u011ferine de\u011fi\u015fmez.<\/span><\/p>\n Hipotez 3: Her deneme ba\u011f\u0131ms\u0131zd\u0131r.<\/strong><\/span><\/p>\n Her denemenin di\u011fer t\u00fcm denemelerden ba\u011f\u0131ms\u0131z oldu\u011funu varsay\u0131yoruz. \u00d6rne\u011fin bir \u00e7ekili\u015fin sonucu di\u011fer bir \u00e7ekili\u015fin sonucunu etkilemez. \u00c7evirmeler ba\u011f\u0131ms\u0131zd\u0131r.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rneklerde binom da\u011f\u0131l\u0131m\u0131n\u0131n varsay\u0131mlar\u0131n\u0131 kar\u015f\u0131layan \u00e7e\u015fitli senaryolar g\u00f6sterilmektedir.<\/span><\/p>\n Bir basketbolcunun serbest at\u0131\u015f denemelerinin %70’ini yapt\u0131\u011f\u0131n\u0131 varsayal\u0131m. E\u011fer 20 deneme yaparsa bu senaryo binom da\u011f\u0131l\u0131m\u0131 kullan\u0131larak modellenebilir.<\/span><\/p>\n Bu senaryo, binom da\u011f\u0131l\u0131m\u0131n\u0131n varsay\u0131mlar\u0131n\u0131n her birini kar\u015f\u0131lamaktad\u0131r:<\/span><\/p>\n Varsay\u0131m 1: Her denemenin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r.<\/strong><\/span><\/p>\n Her serbest at\u0131\u015f giri\u015fiminin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r: ba\u015far\u0131 veya ba\u015far\u0131s\u0131zl\u0131k.<\/span><\/p>\n Varsay\u0131m 2: Ba\u015far\u0131 olas\u0131l\u0131\u011f\u0131 her deneme i\u00e7in ayn\u0131d\u0131r.<\/strong><\/span><\/p>\n Oyuncunun her denemede serbest at\u0131\u015f yapma olas\u0131l\u0131\u011f\u0131 ayn\u0131d\u0131r: %70. Bu bir denemeden di\u011ferine de\u011fi\u015fmez.<\/span><\/p>\n Hipotez 3: Her deneme ba\u011f\u0131ms\u0131zd\u0131r.<\/strong><\/span><\/p>\n Her serbest at\u0131\u015f giri\u015fimi di\u011fer giri\u015fimlerden ba\u011f\u0131ms\u0131zd\u0131r. Bir oyuncunun bir giri\u015fimde bulunup bulunmamas\u0131, ba\u015fka bir giri\u015fimde bulunup bulunmamas\u0131n\u0131 etkilemez.<\/span><\/p>\n Belirli bir ilac\u0131 alan yeti\u015fkinlerin %5’inin olumsuz yan etkilerle kar\u015f\u0131la\u015ft\u0131\u011f\u0131n\u0131 bildi\u011fimizi varsayal\u0131m. Bir t\u0131p mesle\u011finin belirli bir ayda bu ilac\u0131 100 yeti\u015fkine uygulad\u0131\u011f\u0131n\u0131 varsayal\u0131m.<\/span><\/p>\n Bu senaryo, binom da\u011f\u0131l\u0131m\u0131n\u0131n varsay\u0131mlar\u0131n\u0131n her birini kar\u015f\u0131lamaktad\u0131r:<\/span><\/p>\n Varsay\u0131m 1: Her denemenin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r.<\/strong><\/span><\/p>\n \u0130lac\u0131 alan her yeti\u015fkin i\u00e7in yaln\u0131zca iki olas\u0131 sonu\u00e7 vard\u0131r: Ya olumsuz yan etkiler ya\u015farlar ya da hi\u00e7 ya\u015famazlar.<\/span><\/p>\n Varsay\u0131m 2: Ba\u015far\u0131 olas\u0131l\u0131\u011f\u0131 her deneme i\u00e7in ayn\u0131d\u0131r.<\/strong><\/span><\/p>\n Her yeti\u015fkinin olumsuz bir yan etki ya\u015fama \u015fans\u0131 ayn\u0131d\u0131r: %5.<\/span><\/p>\n Hipotez 3: Her deneme ba\u011f\u0131ms\u0131zd\u0131r.<\/strong><\/span><\/p>\n Her yeti\u015fkin i\u00e7in sonu\u00e7 ba\u011f\u0131ms\u0131zd\u0131r. Bir yeti\u015fkinin olumsuz yan etkiler ya\u015fay\u0131p ya\u015famamas\u0131, ba\u015fka bir yeti\u015fkinin ya\u015fay\u0131p ya\u015famamas\u0131 \u00fczerinde hi\u00e7bir etkiye sahip de\u011fildir.<\/span><\/p>\n Bir ma\u011fazaya giren t\u00fcm m\u00fc\u015fterilerin %10’unun geri d\u00f6n\u00fc\u015f yapmak i\u00e7in orada oldu\u011funu bildi\u011fimizi varsayal\u0131m. Belirli bir g\u00fcnde bir ma\u011fazaya 200 ki\u015finin girdi\u011fini ve y\u00f6neticinin geri d\u00f6n\u00fc\u015f yapmak i\u00e7in orada bulunan ki\u015fi say\u0131s\u0131n\u0131 kaydetti\u011fini varsayal\u0131m.<\/span><\/p>\n Bu senaryo, binom da\u011f\u0131l\u0131m\u0131n\u0131n varsay\u0131mlar\u0131n\u0131n her birini kar\u015f\u0131lamaktad\u0131r:<\/span><\/p>\n Varsay\u0131m 1: Her denemenin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r.<\/strong><\/span><\/p>\n Bir m\u00fc\u015fteri ma\u011fazaya her girdi\u011finde oraya gitmesinin yaln\u0131zca iki nedeni vard\u0131r: \u0130ade yapmak ya da yapmamak.<\/span><\/p>\n Varsay\u0131m 2: Ba\u015far\u0131 olas\u0131l\u0131\u011f\u0131 her deneme i\u00e7in ayn\u0131d\u0131r.<\/strong><\/span><\/p>\n Belirli bir m\u00fc\u015fterinin geri d\u00f6n\u00fc\u015f yapmak i\u00e7in orada olma olas\u0131l\u0131\u011f\u0131 ayn\u0131d\u0131r: %10.<\/span><\/p>\n Hipotez 3: Her deneme ba\u011f\u0131ms\u0131zd\u0131r.<\/strong><\/span><\/p>\n Her m\u00fc\u015fterinin sonucu ba\u011f\u0131ms\u0131zd\u0131r. Bir m\u00fc\u015fterinin iade yapmak i\u00e7in orada olup olmamas\u0131, ba\u015fka bir m\u00fc\u015fterinin iade yapmak i\u00e7in orada olup olmad\u0131\u011f\u0131n\u0131 etkilemez.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimler binom da\u011f\u0131l\u0131m\u0131 hakk\u0131nda ek bilgi sa\u011flar:<\/span><\/p>\n Binom da\u011f\u0131l\u0131m\u0131na giri\u015f<\/a> Binom da\u011f\u0131l\u0131m\u0131, sabit say\u0131da denemede meydana gelen belirli say\u0131da “ba\u015far\u0131” olas\u0131l\u0131\u011f\u0131n\u0131 modellemek i\u00e7in kullan\u0131lan bir olas\u0131l\u0131k da\u011f\u0131l\u0131m\u0131d\u0131r. A\u015fa\u011f\u0131daki \u00fc\u00e7 varsay\u0131m kar\u015f\u0131lan\u0131rsa binom da\u011f\u0131l\u0131m\u0131n\u0131n kullan\u0131lmas\u0131 uygundur: Varsay\u0131m 1: Her denemenin yaln\u0131zca iki olas\u0131 sonucu vard\u0131r. Her denemenin yaln\u0131zca iki olas\u0131 sonucu oldu\u011funu varsay\u0131yoruz. \u00d6rne\u011fin, bir paray\u0131 100 kez atarsak, her seferinde yaln\u0131zca iki olas\u0131 sonu\u00e7 olabilir: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2074","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n \u00d6rnek 1: Yap\u0131lan serbest at\u0131\u015f say\u0131s\u0131<\/strong><\/span><\/h3>\n
\u00d6rnek 2: Yan etkilerin say\u0131s\u0131<\/strong><\/span><\/h3>\n
\u00d6rnek 3: Sat\u0131n alma iadelerinin say\u0131s\u0131<\/strong><\/span><\/h3>\n
Ek kaynaklar<\/strong><\/span><\/h3>\n
Binom Da\u011f\u0131l\u0131m\u0131 Hesaplay\u0131c\u0131
Binom da\u011f\u0131l\u0131m\u0131n\u0131n 5 somut \u00f6rne\u011fi<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"