<\/p>\n
\u0130statistiklerde g\u00fcven aral\u0131\u011f\u0131<\/strong> , belirli bir g\u00fcven d\u00fczeyine sahip bir pop\u00fclasyon parametresini<\/a> i\u00e7ermesi muhtemel bir de\u011fer aral\u0131\u011f\u0131d\u0131r.<\/span><\/p>\n \u0130ki pop\u00fclasyon ortalamas\u0131 aras\u0131ndaki fark i\u00e7in bir g\u00fcven aral\u0131\u011f\u0131<\/a> hesaplarsak ve g\u00fcven aral\u0131\u011f\u0131n\u0131n s\u0131f\u0131r de\u011ferini i\u00e7erdi\u011fini bulursak, bu, iki pop\u00fclasyon ortalamas\u0131 aras\u0131ndaki ger\u00e7ek fark i\u00e7in s\u0131f\u0131r\u0131n makul bir de\u011fer oldu\u011funu d\u00fc\u015f\u00fcnd\u00fc\u011f\u00fcm\u00fcz anlam\u0131na gelir.<\/span><\/p>\n Ba\u015fka bir deyi\u015fle, e\u011fer bir g\u00fcven aral\u0131\u011f\u0131 s\u0131f\u0131r i\u00e7eriyorsa, iki pop\u00fclasyonun ortalamalar\u0131 aras\u0131nda “anlaml\u0131” bir fark olmad\u0131\u011f\u0131na dair g\u00fc\u00e7l\u00fc bir kan\u0131t oldu\u011funu s\u00f6yleyebiliriz.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnekler g\u00fcven aral\u0131klar\u0131n\u0131n s\u0131f\u0131r de\u011feriyle ve s\u0131f\u0131r de\u011feri olmadan nas\u0131l yorumlanaca\u011f\u0131n\u0131 a\u00e7\u0131klamaktad\u0131r.<\/span><\/p>\n Bir biyolo\u011fun iki farkl\u0131 kaplumba\u011fa t\u00fcr\u00fc aras\u0131ndaki ortalama a\u011f\u0131rl\u0131k fark\u0131n\u0131 tahmin etmek istedi\u011fini varsayal\u0131m. D\u0131\u015far\u0131 \u00e7\u0131k\u0131yor ve her pop\u00fclasyondan 15 kaplumba\u011fadan olu\u015fan rastgele bir \u00f6rnek topluyor.<\/span><\/p>\n Her numunenin \u00f6zet verileri a\u015fa\u011f\u0131da verilmi\u015ftir:<\/span><\/p>\n \u00d6rnek 1:<\/strong><\/span><\/p>\n \u00d6rnek 2:<\/strong><\/span><\/p>\n \u0130ki t\u00fcr aras\u0131ndaki ortalama a\u011f\u0131rl\u0131ktaki ger\u00e7ek fark i\u00e7in a\u015fa\u011f\u0131daki %95 g\u00fcven aral\u0131\u011f\u0131n\u0131 bulmak amac\u0131yla bu say\u0131lar\u0131 Pop\u00fclasyon Ortalamalar\u0131ndaki Fark i\u00e7in G\u00fcven Aral\u0131\u011f\u0131 Hesaplay\u0131c\u0131s\u0131na<\/a> ekleyebiliriz:<\/span><\/p>\n %95 g\u00fcven aral\u0131\u011f\u0131 = [-3,0757, 23,0757]<\/span><\/strong><\/p>\n Bu g\u00fcven aral\u0131\u011f\u0131 s\u0131f\u0131r de\u011ferini i\u00e7erdi\u011finden, bu, iki kaplumba\u011fa t\u00fcr\u00fc aras\u0131ndaki ortalama a\u011f\u0131rl\u0131ktaki ger\u00e7ek fark i\u00e7in s\u0131f\u0131r\u0131n makul bir de\u011fer oldu\u011funa inand\u0131\u011f\u0131m\u0131z anlam\u0131na gelir.<\/span><\/p>\n Yani %95’lik bir g\u00fcven d\u00fczeyiyle iki t\u00fcr aras\u0131nda ortalama a\u011f\u0131rl\u0131k a\u00e7\u0131s\u0131ndan \u00f6nemli bir fark olmad\u0131\u011f\u0131n\u0131 s\u00f6yleyebiliriz.<\/span><\/p>\n Bir profes\u00f6r\u00fcn iki farkl\u0131 \u00e7al\u0131\u015fma tekni\u011fi aras\u0131ndaki ortalama s\u0131nav puan\u0131 fark\u0131n\u0131 tahmin etmek istedi\u011fini varsayal\u0131m. A tekni\u011fini kullanacak 20 rastgele \u00f6\u011frenciyi ve B tekni\u011fini kullanacak 20 rastgele \u00f6\u011frenciyi se\u00e7iyor ve ard\u0131ndan her \u00f6\u011frenciden ayn\u0131 final s\u0131nav\u0131na girmesini istiyor.<\/span><\/p>\n Her grubun s\u0131nav sonu\u00e7lar\u0131n\u0131n \u00f6zeti a\u015fa\u011f\u0131dad\u0131r:<\/span><\/p>\n Teknik A:<\/strong><\/span><\/p>\n Teknik B:<\/strong><\/span><\/p>\n Ortalama test puanlar\u0131ndaki ger\u00e7ek fark i\u00e7in a\u015fa\u011f\u0131daki %95 g\u00fcven aral\u0131\u011f\u0131n\u0131 bulmak \u00fczere bu say\u0131lar\u0131 N\u00fcfus Ortalamalar\u0131ndaki Fark i\u00e7in G\u00fcven Aral\u0131\u011f\u0131 Hesaplay\u0131c\u0131s\u0131na<\/a> ekleyebiliriz:<\/span><\/p>\n %95 g\u00fcven aral\u0131\u011f\u0131 = [ 2,4550<\/span> , 7,5450<\/span> ]<\/span><\/strong><\/p>\n Bu g\u00fcven aral\u0131\u011f\u0131 s\u0131f\u0131r de\u011ferini i\u00e7ermedi\u011finden bu, iki grup aras\u0131ndaki ortalama test puanlar\u0131 aras\u0131ndaki ger\u00e7ek fark i\u00e7in s\u0131f\u0131r\u0131n makul bir de\u011fer olmad\u0131\u011f\u0131na inand\u0131\u011f\u0131m\u0131z anlam\u0131na gelir.<\/span><\/p>\n Yani %95’lik bir g\u00fcven d\u00fczeyiyle iki grup aras\u0131nda ortalama s\u0131nav puan\u0131nda anlaml\u0131 bir fark oldu\u011funu s\u00f6yleyebiliriz.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6\u011freticiler g\u00fcven aral\u0131klar\u0131 hakk\u0131nda ek bilgi sa\u011flar.<\/span><\/p>\n G\u00fcven aral\u0131\u011f\u0131 ve tahmin aral\u0131\u011f\u0131: fark nedir? \u0130statistiklerde g\u00fcven aral\u0131\u011f\u0131 , belirli bir g\u00fcven d\u00fczeyine sahip bir pop\u00fclasyon parametresini i\u00e7ermesi muhtemel bir de\u011fer aral\u0131\u011f\u0131d\u0131r. \u0130ki pop\u00fclasyon ortalamas\u0131 aras\u0131ndaki fark i\u00e7in bir g\u00fcven aral\u0131\u011f\u0131 hesaplarsak ve g\u00fcven aral\u0131\u011f\u0131n\u0131n s\u0131f\u0131r de\u011ferini i\u00e7erdi\u011fini bulursak, bu, iki pop\u00fclasyon ortalamas\u0131 aras\u0131ndaki ger\u00e7ek fark i\u00e7in s\u0131f\u0131r\u0131n makul bir de\u011fer oldu\u011funu d\u00fc\u015f\u00fcnd\u00fc\u011f\u00fcm\u00fcz anlam\u0131na gelir. Ba\u015fka bir deyi\u015fle, e\u011fer bir […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2162","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n \u00d6rnek 1: G\u00fcven aral\u0131\u011f\u0131 s\u0131f\u0131r i\u00e7eriyor<\/strong><\/span><\/h3>\n
\n
\n
\u00d6rnek 2: G\u00fcven aral\u0131\u011f\u0131 s\u0131f\u0131r i\u00e7ermiyor<\/strong><\/span><\/h3>\n
\n
\n
Ek kaynaklar<\/strong><\/span><\/h3>\n
Ger\u00e7ek Hayattan 4 G\u00fcven Aral\u0131\u011f\u0131 \u00d6rne\u011fi<\/a>
G\u00fcven aral\u0131klar\u0131 nas\u0131l raporlan\u0131r?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"