Do\u011frusal regresyonun temel varsay\u0131mlar\u0131ndan biri, art\u0131klar\u0131n, yorday\u0131c\u0131 de\u011fi\u015fken(ler)in her seviyesinde sabit varyansa sahip olmas\u0131d\u0131r.<\/span><\/p>\n E\u011fer bu varsay\u0131m do\u011frulanmazsa, art\u0131klar de\u011fi\u015fen varyans<\/a> sorunu ya\u015fayacakt\u0131r. Bu durumda model katsay\u0131 tahminleri g\u00fcvenilmez hale gelir.<\/span><\/p>\n Bir regresyon modelinin art\u0131klar\u0131n\u0131n sabit varyansa sahip olup olmad\u0131\u011f\u0131n\u0131 belirlemenin en yayg\u0131n yolu, art\u0131klara kar\u015f\u0131 uygun de\u011ferlerin bir grafi\u011fini<\/strong> olu\u015fturmakt\u0131r.<\/span><\/p>\n Bu, regresyon modelinin x ekseni boyunca uydurulmu\u015f de\u011ferlerini ve y ekseni boyunca uydurulmu\u015f bu de\u011ferlerin art\u0131klar\u0131n\u0131 g\u00f6r\u00fcnt\u00fcleyen bir \u00e7izim t\u00fcr\u00fcd\u00fcr.<\/span><\/p>\n Art\u0131klar\u0131n da\u011f\u0131l\u0131m\u0131, uydurulan de\u011ferlerin her seviyesinde yakla\u015f\u0131k olarak e\u015fitse, sabit varyans varsay\u0131m\u0131n\u0131n kar\u015f\u0131land\u0131\u011f\u0131n\u0131 s\u00f6yleriz.<\/span><\/p>\n Aksi takdirde, art\u0131klar\u0131n da\u011f\u0131l\u0131m\u0131 sistematik olarak artar veya azal\u0131rsa, bu varsay\u0131m\u0131n ihlal edilmesi muhtemeldir.<\/span><\/p>\n Not<\/strong> : Bu t\u00fcr bir grafik yaln\u0131zca veri k\u00fcmesine bir regresyon modeli yerle\u015ftirildikten sonra<\/em> olu\u015fturulabilir.<\/span><\/p>\n A\u015fa\u011f\u0131daki grafik, sabit varyans\u0131<\/strong> g\u00f6steren art\u0131klara kar\u015f\u0131 uygun de\u011ferlerin grafi\u011finin bir \u00f6rne\u011fini g\u00f6stermektedir:<\/span> <\/p>\n Art\u0131klar\u0131n, uydurulan de\u011ferlerin her seviyesinde yakla\u015f\u0131k olarak sabit bir varyansla, belirli bir d\u00fczende, s\u0131f\u0131r \u00e7evresinde nas\u0131l rastgele da\u011f\u0131ld\u0131\u011f\u0131na dikkat edin.<\/span><\/p>\n A\u015fa\u011f\u0131daki grafik, sabit olmayan varyans<\/strong> g\u00f6steren art\u0131klara kar\u015f\u0131 uygun de\u011ferlerin grafi\u011finin bir \u00f6rne\u011fini g\u00f6stermektedir:<\/span> <\/p>\n Tak\u0131lan de\u011ferler artt\u0131k\u00e7a art\u0131klar\u0131n da\u011f\u0131l\u0131m\u0131n\u0131n da b\u00fcy\u00fcd\u00fc\u011f\u00fcn\u00fc unutmay\u0131n. Bu, sabit olmayan varyans\u0131n tipik bir i\u015faretidir.<\/span><\/p>\n Bu bize, regresyon modelimizin art\u0131klarda sabit olmayan varyanstan muzdarip oldu\u011funu ve bu nedenle model katsay\u0131 tahminlerinin g\u00fcvenilmez oldu\u011funu s\u00f6yler.<\/span><\/p>\n Sabit varyans varsay\u0131m\u0131 ihlal edilirse, bu sorunu \u00e7\u00f6zmenin en yayg\u0131n yolu, yan\u0131t de\u011fi\u015fkenini \u00fc\u00e7 d\u00f6n\u00fc\u015f\u00fcmden birini kullanarak d\u00f6n\u00fc\u015ft\u00fcrmektir:<\/span><\/p>\n 1. G\u00fcnl\u00fck D\u00f6n\u00fc\u015f\u00fcm\u00fc:<\/strong> Yan\u0131t de\u011fi\u015fkenini y’den log(y)’<\/strong> ye d\u00f6n\u00fc\u015ft\u00fcr\u00fcn<\/span><\/p>\n 2. Karek\u00f6k d\u00f6n\u00fc\u015f\u00fcm\u00fc:<\/strong> yan\u0131t de\u011fi\u015fkenini y’den \u221ay’ye<\/span><\/strong> d\u00f6n\u00fc\u015ft\u00fcr\u00fcn<\/span><\/p>\n 3. K\u00fcp k\u00f6k d\u00f6n\u00fc\u015f\u00fcm\u00fc:<\/strong> yan\u0131t de\u011fi\u015fkenini y’den y 1\/3’e<\/sup><\/strong> d\u00f6n\u00fc\u015ft\u00fcr\u00fcn<\/span><\/p>\n Bu d\u00f6n\u00fc\u015f\u00fcmlerin ger\u00e7ekle\u015ftirilmesiyle sabit olmayan varyans sorunu genel olarak ortadan kalkar.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimler do\u011frusal regresyon ve art\u0131k analiz hakk\u0131nda ek bilgi sa\u011flar:<\/span><\/p>\n Basit Do\u011frusal Regresyona Giri\u015f<\/a> Do\u011frusal regresyon, bir veya daha fazla \u00f6ng\u00f6r\u00fcc\u00fc de\u011fi\u015fken ile bir yan\u0131t de\u011fi\u015fkeni aras\u0131ndaki ili\u015fkiyi \u00f6l\u00e7mek i\u00e7in kulland\u0131\u011f\u0131m\u0131z bir tekniktir. Do\u011frusal regresyonun temel varsay\u0131mlar\u0131ndan biri, art\u0131klar\u0131n, yorday\u0131c\u0131 de\u011fi\u015fken(ler)in her seviyesinde sabit varyansa sahip olmas\u0131d\u0131r. E\u011fer bu varsay\u0131m do\u011frulanmazsa, art\u0131klar de\u011fi\u015fen varyans sorunu ya\u015fayacakt\u0131r. Bu durumda model katsay\u0131 tahminleri g\u00fcvenilmez hale gelir. Sabit varyans nas\u0131l de\u011ferlendirilir? Bir […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2178","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n Sabit varyans nas\u0131l de\u011ferlendirilir?<\/strong><\/span><\/h3>\n
![\"\"](\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/constantevar2.png\")
<\/p>\n![\"\"](\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/constantevar1.png\")
<\/p>\n Sabit sapma ihlali nas\u0131l d\u00fczeltilir?<\/strong><\/span><\/h3>\n
Ek kaynaklar<\/strong><\/span><\/h3>\n
\u00c7oklu Do\u011frusal Regresyona Giri\u015f<\/a>
Do\u011frusal regresyonun d\u00f6rt varsay\u0131m\u0131<\/a>
\u0130statistiklerde art\u0131klar nelerdir?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"