{"id":2830,"date":"2023-07-20T12:26:30","date_gmt":"2023-07-20T12:26:30","guid":{"rendered":"https:\/\/statorials.org\/tr\/capraz-python-urunu\/"},"modified":"2023-07-20T12:26:30","modified_gmt":"2023-07-20T12:26:30","slug":"capraz-python-urunu","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/capraz-python-urunu\/","title":{"rendered":"Python&#39;da \u00e7apraz \u00e7arp\u0131m nas\u0131l hesaplan\u0131r?"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\">(A <sub>1<\/sub> , A <sub>2<\/sub> , A <sub>3<\/sub> ) elemanlar\u0131na sahip A vekt\u00f6r\u00fcm\u00fcz ve (B <sub>1<\/sub> , B <sub>2<\/sub> , B <sub>3<\/sub> ) elemanlar\u0131na sahip bir B vekt\u00f6r\u00fcm\u00fcz oldu\u011funu varsayarak, bu iki vekt\u00f6r\u00fcn \u00e7apraz \u00e7arp\u0131m\u0131n\u0131 a\u015fa\u011f\u0131daki \u015fekilde hesaplayabiliriz:<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7apraz \u00e7arp\u0131m<\/strong> = [(A <sub>2<\/sub> *B <sub>3<\/sub> ) \u2013 (A <sub>3<\/sub> *B <sub>2<\/sub> ), (A <sub>3<\/sub> *B <sub>1<\/sub> ) \u2013 (A <sub>1<\/sub> *B <sub>3<\/sub> ), (A <sub>1<\/sub> *B <sub>2<\/sub> ) \u2013 (A <sub>2<\/sub> *B <sub>1<\/sub> )]<\/span><\/p>\n<p> <span style=\"color: #000000;\">\u00d6rne\u011fin a\u015fa\u011f\u0131daki vekt\u00f6rlere sahip oldu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">Vekt\u00f6r A: (1, 2, 3)<\/span><\/li>\n<li> <span style=\"color: #000000;\">Vekt\u00f6r B: (4, 5, 6)<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Bu vekt\u00f6rlerin \u00e7apraz \u00e7arp\u0131m\u0131n\u0131 \u015fu \u015fekilde hesaplayabiliriz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">\u00c7apraz \u00e7arp\u0131m = [(A <sub>2<\/sub> *B <sub>3<\/sub> ) \u2013 (A <sub>3<\/sub> *B <sub>2<\/sub> ), (A <sub>3<\/sub> *B <sub>1<\/sub> ) \u2013 (A <sub>1<\/sub> *B <sub>3<\/sub> ), (A <sub>1<\/sub> *B <sub>2<\/sub> ) \u2013 (A <sub>2<\/sub> *B <sub>1<\/sub> )]<\/span><\/li>\n<li> <span style=\"color: #000000;\">\u00c7apraz \u00e7arp\u0131m = [(2*6) \u2013 (3*5), (3*4) \u2013 (1*6), (1*5) \u2013 (2*4)]<\/span><\/li>\n<li> <span style=\"color: #000000;\">\u00c7apraz \u00e7arp\u0131m = (-3, 6, -3)<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Python&#8217;da iki vekt\u00f6r\u00fcn \u00e7apraz \u00e7arp\u0131m\u0131n\u0131 hesaplamak i\u00e7in a\u015fa\u011f\u0131daki iki y\u00f6ntemden birini kullanabilirsiniz:<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>Y\u00f6ntem 1: NumPy&#8217;nin cross() i\u015flevini kullan\u0131n<\/strong><\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008000;\">import<\/span> numpy <span style=\"color: #008000;\">as<\/span> np\n  \n<span style=\"color: #008080;\">#calculate cross product of vectors A and B\n<\/span>n.p. <span style=\"color: #3366ff;\">cross<\/span> (A, B)\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\"><strong>Y\u00f6ntem 2: Kendi i\u015flevinizi tan\u0131mlay\u0131n<\/strong><\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\">#define function to calculate cross product<\/span> \n<span style=\"color: #008000;\">def<\/span> <span style=\"color: #3366ff;\">cross_prod<\/span> (a,b):\n    result = [a[1] <span style=\"color: #800080;\">*<\/span> b[2] - a[2] <span style=\"color: #800080;\">*<\/span> b[1],\n            a[2] <span style=\"color: #800080;\">*<\/span> b[0] - a[0] <span style=\"color: #800080;\">*<\/span> b[2],\n            a[0] <span style=\"color: #800080;\">*<\/span> b[1] - a[1] <span style=\"color: #800080;\">*<\/span> b[0]]\n\n    <span style=\"color: #008000;\">return<\/span> result\n\n<span style=\"color: #008080;\">#calculate cross product\n<\/span>cross_prod(A, B)<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki \u00f6rnekler her y\u00f6ntemin pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6stermektedir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>\u00d6rnek 1: NumPy cross() i\u015flevini kullanma<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki kod, iki vekt\u00f6r aras\u0131ndaki \u00e7apraz \u00e7arp\u0131m\u0131 hesaplamak i\u00e7in NumPy&#8217;nin <a href=\"https:\/\/numpy.org\/doc\/stable\/reference\/generated\/numpy.cross.html\" target=\"_blank\" rel=\"noopener\">cross()<\/a> i\u015flevinin nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008000;\">import<\/span> numpy <span style=\"color: #008000;\">as<\/span> np\n\n<span style=\"color: #008080;\">#definevectors<\/span>\nA = np. <span style=\"color: #3366ff;\">array<\/span> ([1, 2, 3])\nB = np. <span style=\"color: #3366ff;\">array<\/span> ([4, 5, 6])\n  \n<span style=\"color: #008080;\">#calculate cross product of vectors A and B\n<\/span>n.p. <span style=\"color: #3366ff;\">cross<\/span> (A, B)\n\n[-3, 6, -3]\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">\u00c7apraz \u00e7arp\u0131m <strong>(-3, 6, -3)<\/strong> olur.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bu, daha \u00f6nce manuel olarak hesaplad\u0131\u011f\u0131m\u0131z \u00e7apraz \u00e7arp\u0131ma kar\u015f\u0131l\u0131k gelir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>\u00d6rnek 2: Kendi i\u015flevinizi tan\u0131mlay\u0131n<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki kod, iki vekt\u00f6r aras\u0131ndaki \u00e7apraz \u00e7arp\u0131m\u0131 hesaplamak i\u00e7in kendi fonksiyonunuzu nas\u0131l tan\u0131mlayaca\u011f\u0131n\u0131z\u0131 g\u00f6sterir:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\">#define function to calculate cross product<\/span> \n<span style=\"color: #008000;\">def<\/span> <span style=\"color: #3366ff;\">cross_prod<\/span> (a,b):\n    result = [a[1] <span style=\"color: #800080;\">*<\/span> b[2] - a[2] <span style=\"color: #800080;\">*<\/span> b[1],\n            a[2] <span style=\"color: #800080;\">*<\/span> b[0] - a[0] <span style=\"color: #800080;\">*<\/span> b[2],\n            a[0] <span style=\"color: #800080;\">*<\/span> b[1] - a[1] <span style=\"color: #800080;\">*<\/span> b[0]]\n\n    <span style=\"color: #008000;\">return<\/span> result\n\n<span style=\"color: #008080;\">#definevectors<\/span>\nA = np. <span style=\"color: #3366ff;\">array<\/span> ([1, 2, 3])\nB = np. <span style=\"color: #3366ff;\">array<\/span> ([4, 5, 6])\n\n<span style=\"color: #008080;\">#calculate cross product\n<\/span>cross_prod(A, B)\n\n[-3, 6, -3]\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">\u00c7apraz \u00e7arp\u0131m <strong>(-3, 6, -3)<\/strong> olur.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bu, \u00f6nceki \u00f6rnekte hesaplad\u0131\u011f\u0131m\u0131z \u00e7apraz \u00e7arp\u0131ma kar\u015f\u0131l\u0131k gelir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Ek kaynaklar<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki e\u011fitimlerde Python&#8217;da di\u011fer genel g\u00f6revlerin nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n<p> <a href=\"https:\/\/statorials.org\/tr\/numpy-nokta-carpimi\/\" target=\"_blank\" rel=\"noopener\">NumPy kullan\u0131larak nokta \u00e7arp\u0131m nas\u0131l hesaplan\u0131r<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/numpy-normallestirme-matrisi\/\" target=\"_blank\" rel=\"noopener\">NumPy matrisi nas\u0131l normalle\u015ftirilir<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/numpy-matrise-bir-satir-ekle\/\" target=\"_blank\" rel=\"noopener\">NumPy&#8217;de matrise sat\u0131r nas\u0131l eklenir<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>(A 1 , A 2 , A 3 ) elemanlar\u0131na sahip A vekt\u00f6r\u00fcm\u00fcz ve (B 1 , B 2 , B 3 ) elemanlar\u0131na sahip bir B vekt\u00f6r\u00fcm\u00fcz oldu\u011funu varsayarak, bu iki vekt\u00f6r\u00fcn \u00e7apraz \u00e7arp\u0131m\u0131n\u0131 a\u015fa\u011f\u0131daki \u015fekilde hesaplayabiliriz: \u00c7apraz \u00e7arp\u0131m = [(A 2 *B 3 ) \u2013 (A 3 *B 2 ), (A 3 *B [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-2830","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - 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