{"id":3019,"date":"2023-07-19T14:52:35","date_gmt":"2023-07-19T14:52:35","guid":{"rendered":"https:\/\/statorials.org\/tr\/r-cinsinden-siralama-duzeni-siralamasi\/"},"modified":"2023-07-19T14:52:35","modified_gmt":"2023-07-19T14:52:35","slug":"r-cinsinden-siralama-duzeni-siralamasi","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/r-cinsinden-siralama-duzeni-siralamasi\/","title":{"rendered":"Tam k\u0131lavuz: r&#39;de sort(), order() ve rank() nas\u0131l kullan\u0131l\u0131r"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\"><span style=\"color: #000000;\">R&#8217;nin insanlar\u0131n s\u0131kl\u0131kla kar\u0131\u015ft\u0131rd\u0131\u011f\u0131 \u00fc\u00e7 i\u015flevi <strong>s\u0131ralama<\/strong> , <strong>s\u0131ralama<\/strong> ve <strong>s\u0131ralamad\u0131r<\/strong> .<\/span><\/span><\/p>\n<p> <span style=\"color: #000000;\">\u0130\u015fte bu i\u015flevler aras\u0131ndaki fark:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\"><strong>sort()<\/strong> bir vekt\u00f6r\u00fc artan d\u00fczende s\u0131ralar<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>order()<\/strong> bir vekt\u00f6r\u00fcn her \u00f6\u011fesinin indeksini s\u0131ral\u0131 d\u00fczende d\u00f6nd\u00fcr\u00fcr<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>Rank()<\/strong> bir vekt\u00f6r\u00fcn her eleman\u0131na bir derece atayacakt\u0131r (en k\u00fc\u00e7\u00fck = 1)<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki \u00f6rnekte bu i\u015flevlerin her birinin pratikte nas\u0131l kullan\u0131laca\u011f\u0131 g\u00f6sterilmektedir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>\u00d6rnek: Vekt\u00f6rlerle sort(), order() ve Rank()&#8217;\u0131 kullan\u0131n<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki kod, d\u00f6rt de\u011ferli bir vekt\u00f6rle <strong>sort()<\/strong> , <strong>order()<\/strong> ve <strong>Rank()<\/strong> i\u015flevlerinin nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #000000;\"><span style=\"color: #008080;\">#createvector\n<\/span>x &lt;- c(0, 20, 10, 15)\n\n<span style=\"color: #008080;\">#sort vector\n<\/span>sort(s)\n\n[1] 0 10 15 20\n\n<span style=\"color: #008080;\">#order vector\n<\/span>order(s)\n\n[1] 1 3 4 2\n\n<span style=\"color: #008080;\">#rank vector\n<\/span>rank(x)\n\n[1] 1 4 2 3\n<\/span><\/span><\/strong><\/pre>\n<p> <span style=\"color: #000000;\">\u0130\u015fte her fonksiyonun yapt\u0131\u011f\u0131 \u015fey:<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>1.<\/strong> <strong>sort()<\/strong> i\u015flevi, vekt\u00f6r de\u011ferlerini artan d\u00fczende s\u0131ralad\u0131.<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>2.<\/strong> <strong>order()<\/strong> i\u015flevi, her \u00f6\u011fenin dizinini s\u0131ral\u0131 d\u00fczende d\u00f6nd\u00fcrd\u00fc.<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">Orijinal vekt\u00f6r de\u011ferlerini bu indeks de\u011ferlerine g\u00f6re s\u0131ralarsan\u0131z s\u0131ralanm\u0131\u015f bir vekt\u00f6r elde edersiniz.<\/span><\/li>\n<li> <span style=\"color: #000000;\">\u00d6rne\u011fin, order() bize de\u011feri ilk \u00f6nce indeks konumu <strong>1&#8217;e<\/strong> koymam\u0131z\u0131 s\u00f6yler; orijinal vekt\u00f6rde bu 0&#8217;d\u0131r.<\/span><\/li>\n<li> <span style=\"color: #000000;\">Daha sonra order() bize de\u011feri indeks pozisyonu <strong>3&#8217;e<\/strong> koymam\u0131z\u0131 s\u00f6yler; bu, orijinal vekt\u00f6rde 10&#8217;dur.<\/span><\/li>\n<li> <span style=\"color: #000000;\">Daha sonra order() bize de\u011feri indeks pozisyonu <strong>4&#8217;e<\/strong> koymam\u0131z\u0131 s\u00f6yler; bu, orijinal vekt\u00f6rde 15&#8217;tir.<\/span><\/li>\n<li> <span style=\"color: #000000;\">Daha sonra order() bize de\u011feri indeks konumu <strong>2&#8217;ye<\/strong> koymam\u0131z\u0131 s\u00f6yler; bu, orijinal vekt\u00f6rde 20&#8217;dir.<\/span><\/li>\n<li> <span style=\"color: #000000;\">Nihai sonu\u00e7, s\u0131ralanm\u0131\u015f bir vekt\u00f6rd\u00fcr \u2013 0, 10, 15, 20.<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\"><strong>3.<\/strong> <strong>Rank()<\/strong> i\u015flevi, en k\u00fc\u00e7\u00fck de\u011fer i\u00e7in 1&#8217;i kullanarak vekt\u00f6r\u00fcn her \u00f6\u011fesine bir s\u0131ra atad\u0131.<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">\u00d6rne\u011fin, Rank() bize orijinal vekt\u00f6r\u00fcn ilk de\u011ferinin en k\u00fc\u00e7\u00fck (rank = 1) oldu\u011funu ve orijinal vekt\u00f6r\u00fcn ikinci de\u011ferinin en b\u00fcy\u00fck (rank = 4) oldu\u011funu s\u00f6yler.<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\"><strong>sort()<\/strong> , <strong>order()<\/strong> ve <strong>r\u00fctbe()&#8217;yi<\/strong> ters s\u0131rada kullanmak i\u00e7in a\u015fa\u011f\u0131daki s\u00f6zdizimini kullanabilece\u011fimizi unutmay\u0131n:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong><span style=\"color: #008080;\"><span style=\"color: #000000;\"><span style=\"color: #008080;\">#createvector\n<\/span>x &lt;- c(0, 20, 10, 15)\n\n<span style=\"color: #008080;\">#sort vector in decreasing order\n<\/span>sort(x, decreasing= <span style=\"color: #008000;\">TRUE<\/span> )\n\n[1] 20 15 10 0\n\n<span style=\"color: #008080;\">#order vector in decreasing order\n<\/span>order(x, decreasing= <span style=\"color: #008000;\">TRUE<\/span> )\n\n[1] 2 4 3 1\n\n<span style=\"color: #008080;\">#rank vector in reverse order (largest value = 1)\n<\/span>rank(-x)\n\n[1] 4 1 3 2\n<\/span><\/span><\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Bu sonu\u00e7lar\u0131n \u00f6nceki \u00f6rneklerde elde edilen sonu\u00e7lar\u0131n tam tersi oldu\u011funu unutmay\u0131n.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Not: Rank() i\u015fleviyle ba\u011flar\u0131n nas\u0131l ele al\u0131naca\u011f\u0131<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\"><strong>Rank()<\/strong> i\u015flevini kullan\u0131rken ba\u011flar\u0131 nas\u0131l ele almam\u0131z gerekti\u011fini belirtmek i\u00e7in <strong>Tie.method<\/strong> arg\u00fcman\u0131n\u0131 kullanabiliriz:<\/span><\/p>\n<pre style=\"background-color: #ececec; font-size: 15px;\"> <strong>rank(x, ties. <span style=\"color: #3366ff;\">method<\/span> = ' <span style=\"color: #ff0000;\">average<\/span> ')\n<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Ba\u011flant\u0131lar\u0131n nas\u0131l i\u015flenece\u011fini belirtmek i\u00e7in a\u015fa\u011f\u0131daki se\u00e7eneklerden birini kullanabilirsiniz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\"><strong>ortalama<\/strong> : (Varsay\u0131lan) Ba\u011flant\u0131l\u0131 her \u00f6\u011feye ortalama s\u0131ralamay\u0131 atar (3. ve 4. s\u0131radaki \u00f6\u011felerin her ikisi de 3,5 puan al\u0131r)<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>birinci<\/strong> : \u0130lk ba\u011flant\u0131l\u0131 \u00f6\u011feyi en d\u00fc\u015f\u00fck s\u0131raya atar (3. ve 4. konumlarda yer alan \u00f6\u011feler s\u0131ras\u0131yla 3. ve 4. s\u0131ralar\u0131 al\u0131r)<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>min<\/strong> : Ba\u011flant\u0131l\u0131 her \u00f6\u011feyi en d\u00fc\u015f\u00fck s\u0131raya atar (3. ve 4. s\u0131radaki \u00f6\u011felerin her ikisi de 3 s\u0131ras\u0131n\u0131 al\u0131r)<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>max<\/strong> : Ba\u011flant\u0131l\u0131 her \u00f6\u011feye en y\u00fcksek s\u0131ralamay\u0131 atar (3. ve 4. s\u0131radaki \u00f6\u011felerin her ikisi de 4 puan alacakt\u0131r)<\/span><\/li>\n<li> <span style=\"color: #000000;\"><strong>rastgele<\/strong> : e\u015fit olan her \u00f6\u011feye rastgele bir s\u0131ralama atar (3. ve 4. konum i\u00e7in e\u015fit olan \u00f6\u011felerden herhangi biri her iki s\u0131ralamay\u0131 da alabilir)<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Senaryonuza ba\u011fl\u0131 olarak bu y\u00f6ntemlerden birinin kullan\u0131lmas\u0131 di\u011ferlerinden daha anlaml\u0131 olabilir.<\/span><\/p>\n<h3> <span style=\"color: #000000;\"><strong>Ek kaynaklar<\/strong><\/span><\/h3>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki e\u011fitimlerde R&#8217;de di\u011fer yayg\u0131n i\u015flemlerin nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n<p> <a href=\"https:\/\/statorials.org\/tr\/rde-birden-cok-sutuna-gore-siralama\/\" target=\"_blank\" rel=\"noopener\">R&#8217;de birden \u00e7ok s\u00fctuna g\u00f6re s\u0131ralama nas\u0131l yap\u0131l\u0131r<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/rde-tarihe-gore-sirala\/\" target=\"_blank\" rel=\"noopener\">R&#8217;de bir veri \u00e7er\u00e7evesi tarihe g\u00f6re nas\u0131l s\u0131ralan\u0131r<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/r-cinsinden-yuzdelik-siralama\/\" target=\"_blank\" rel=\"noopener\">R&#8217;de y\u00fczdelik s\u0131ralama nas\u0131l hesaplan\u0131r<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>R&#8217;nin insanlar\u0131n s\u0131kl\u0131kla kar\u0131\u015ft\u0131rd\u0131\u011f\u0131 \u00fc\u00e7 i\u015flevi s\u0131ralama , s\u0131ralama ve s\u0131ralamad\u0131r . \u0130\u015fte bu i\u015flevler aras\u0131ndaki fark: sort() bir vekt\u00f6r\u00fc artan d\u00fczende s\u0131ralar order() bir vekt\u00f6r\u00fcn her \u00f6\u011fesinin indeksini s\u0131ral\u0131 d\u00fczende d\u00f6nd\u00fcr\u00fcr Rank() bir vekt\u00f6r\u00fcn her eleman\u0131na bir derece atayacakt\u0131r (en k\u00fc\u00e7\u00fck = 1) A\u015fa\u011f\u0131daki \u00f6rnekte bu i\u015flevlerin her birinin pratikte nas\u0131l kullan\u0131laca\u011f\u0131 g\u00f6sterilmektedir. \u00d6rnek: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3019","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Tam K\u0131lavuz: R - Statorials&#039;de Sort(), Order() ve Rank() Nas\u0131l Kullan\u0131l\u0131r<\/title>\n<meta name=\"description\" content=\"Bu e\u011fitimde R&#039;deki sort(), order() ve Rank() i\u015flevleri aras\u0131ndaki fark \u00f6rnekler de dahil olmak \u00fczere a\u00e7\u0131klanmaktad\u0131r.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/tr\/r-cinsinden-siralama-duzeni-siralamasi\/\" 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