<\/p>\n
R’de NaN<\/strong> , Say\u0131 De\u011fil anlam\u0131na gelir.<\/span><\/p>\n NaN de\u011ferleri genellikle ge\u00e7ersiz sonu\u00e7la sonu\u00e7lanan bir hesaplama yapmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar.<\/span><\/p>\n \u00d6rne\u011fin, s\u0131f\u0131ra b\u00f6lmek veya negatif bir say\u0131n\u0131n logunu hesaplamak, her ikisi de NaN de\u011ferleri \u00fcretir:<\/span><\/p>\n NaN de\u011ferlerinin, yaln\u0131zca eksik de\u011ferleri temsil eden NA<\/strong> de\u011ferlerinden farkl\u0131 oldu\u011funu unutmay\u0131n.<\/span><\/p>\n R’de NaN de\u011ferlerini i\u015flemek i\u00e7in a\u015fa\u011f\u0131daki y\u00f6ntemleri kullanabilirsiniz:<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnekler bu y\u00f6ntemlerin her birinin pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6stermektedir.<\/span><\/span><\/p>\n A\u015fa\u011f\u0131daki kod, NaN de\u011ferleri i\u00e7eren bir vekt\u00f6rdeki konumlar\u0131n nas\u0131l tan\u0131mlanaca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n Sonu\u00e7tan vekt\u00f6r\u00fcn 2.<\/strong> ve 4.<\/strong> konumlar\u0131ndaki elemanlar\u0131n NaN de\u011ferleri oldu\u011funu g\u00f6rebiliriz.<\/span><\/span><\/p>\n A\u015fa\u011f\u0131daki kod, R’deki bir vekt\u00f6rdeki toplam NaN de\u011ferlerinin nas\u0131l say\u0131laca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n Sonu\u00e7tan vekt\u00f6rde toplam 2<\/strong> NaN de\u011ferinin oldu\u011funu g\u00f6rebiliriz.<\/span><\/p>\n A\u015fa\u011f\u0131daki kod, orijinal vekt\u00f6rden kald\u0131r\u0131lan NaN de\u011ferlerine sahip yeni bir vekt\u00f6r\u00fcn nas\u0131l olu\u015fturulaca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n \u0130ki NaN de\u011ferinin vekt\u00f6rden kald\u0131r\u0131ld\u0131\u011f\u0131n\u0131 unutmay\u0131n.<\/span><\/span><\/p>\n A\u015fa\u011f\u0131daki kod, bir vekt\u00f6rdeki NaN de\u011ferlerinin s\u0131f\u0131rlarla nas\u0131l de\u011fi\u015ftirilece\u011fini g\u00f6sterir:<\/span><\/p>\n Vekt\u00f6rde her iki NaN de\u011ferinin de s\u0131f\u0131rlarla de\u011fi\u015ftirildi\u011fini unutmay\u0131n.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’de di\u011fer ortak g\u00f6revlerin nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de eksik de\u011ferlerin enterpolasyonu nas\u0131l yap\u0131l\u0131r<\/a> R’de NaN , Say\u0131 De\u011fil anlam\u0131na gelir. NaN de\u011ferleri genellikle ge\u00e7ersiz sonu\u00e7la sonu\u00e7lanan bir hesaplama yapmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar. \u00d6rne\u011fin, s\u0131f\u0131ra b\u00f6lmek veya negatif bir say\u0131n\u0131n logunu hesaplamak, her ikisi de NaN de\u011ferleri \u00fcretir: #attempt to divide by zero 0 \/ 0 [1]NaN #attempt to calculate log of negative value log(-12) [1]NaN NaN de\u011ferlerinin, yaln\u0131zca […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3045","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n #attempt to divide by zero<\/span>\n0 \/ 0\n\n[1]NaN\n\n#attempt to calculate log of negative value<\/span>\nlog(-12)\n\n[1]NaN\n<\/b><\/pre>\n #identify positions in vector with NaN values\n<\/span>which(is. nan<\/span> (x))\n\n#count total NaN values in vector\n<\/span>sum(is. nan<\/span> (x)) \n\n#remove NaN values in vector\n<\/span>x_new <- x[!is. no<\/span> (x)]\n\n#replace NaN values in vector\n<\/span>x[is. nan<\/span> (x)] <- 0 \n<\/strong><\/pre>\n \u00d6rnek 1: NaN de\u011ferlerine sahip bir vekt\u00f6rdeki konumlar\u0131 tan\u0131mlay\u0131n<\/strong><\/span><\/h3>\n
#create vector with some NaN values\nx <- c(1, NaN, 12, NaN, 50, 30)\n<\/span>\n#identify positions with NaN values\nwhich(is. nan<\/span> (x))\n\n[1] 2 4<\/span><\/span><\/strong><\/pre>\n \u00d6rnek 2: Bir Vekt\u00f6rdeki Toplam NaN De\u011ferlerini Sayma<\/strong><\/span><\/h3>\n
#create vector with some NaN values\nx <- c(1, NaN, 12, NaN, 50, 30)\n<\/span>\n#identify positions with NaN values\nsum(is. nan<\/span> (x))\n\n[1] 2<\/span><\/span><\/strong><\/pre>\n \u00d6rnek 3: Vekt\u00f6rdeki NaN de\u011ferlerini kald\u0131r\u0131n<\/strong><\/span><\/h3>\n
#create vector with some NaN values\nx <- c(1, NaN, 12, NaN, 50, 30)\n<\/span>\n#define new vector with NaN values removed\nx_new <- x[!is. no<\/span> (x)]<\/span>\n\n#view new vector\nx_new\n\n[1] 1 12 50 30\n<\/span><\/span><\/strong><\/pre>\n \u00d6rnek 4: Vekt\u00f6rdeki NaN de\u011ferlerini de\u011fi\u015ftirin<\/strong><\/span><\/h3>\n
#create vector with some NaN values\nx <- c(1, NaN, 12, NaN, 50, 30)\n<\/span>\n#replace NaN values with zero\nx[is. nan<\/span> (x)] <- 0<\/span>\n\n#view updated vector\nx\n\n[1] 1 0 12 0 50 30\n<\/span><\/span><\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
R’de eksik de\u011ferler nas\u0131l bulunur ve say\u0131l\u0131r<\/a>
R’de “NA De\u011fildir” nas\u0131l kullan\u0131l\u0131r?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"