<\/p>\n
\u0130ki nesnenin kesi\u015fimini bulmak i\u00e7in R taban\u0131ndaki intersect()<\/strong> i\u015flevini kullanabilirsiniz.<\/span><\/p>\n “Kesi\u015fme” basit\u00e7e iki nesnenin ortak oldu\u011fu unsurlar\u0131 temsil eder.<\/span><\/p>\n Bu i\u015flev a\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullan\u0131r:<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnekler intersect()<\/strong> fonksiyonunun vekt\u00f6rler ve veri \u00e7er\u00e7eveleriyle nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir.<\/span><\/p>\n A\u015fa\u011f\u0131daki kod, R’deki iki vekt\u00f6r aras\u0131ndaki kesi\u015fimi bulmak i\u00e7in intersect()<\/strong> i\u015flevinin nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n Sonu\u00e7tan, x ve y vekt\u00f6rlerinin \u00fc\u00e7 ortak de\u011fere sahip oldu\u011funu g\u00f6rebiliriz: 1<\/strong> , 5<\/strong> ve 19<\/strong> .<\/span><\/span><\/p>\n intersect()<\/strong> fonksiyonunun karakter vekt\u00f6rleriyle de \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131 unutmay\u0131n:<\/span><\/p>\n Sonu\u00e7tan, x ve y vekt\u00f6rlerinin \u00fc\u00e7 ortak dizgeye sahip oldu\u011funu g\u00f6rebiliriz: C<\/strong> , D<\/strong> ve E.<\/strong><\/span><\/p>\n intersect()<\/strong> fonksiyonunun \u00e7al\u0131\u015fmas\u0131 i\u00e7in iki vekt\u00f6r\u00fcn ayn\u0131 uzunlukta olmas\u0131 gerekmedi\u011fini unutmay\u0131n.<\/span><\/p>\n \u0130ki veri \u00e7er\u00e7evesinin ortak noktalar\u0131n\u0131 bulmak i\u00e7in dplyr<\/strong> paketindeki intersect()<\/strong> fonksiyonunu kullanmam\u0131z gerekiyor.<\/span><\/span><\/p>\n A\u015fa\u011f\u0131daki kod, iki veri \u00e7er\u00e7evesinin ortak oldu\u011fu sat\u0131rlar\u0131 bulmak i\u00e7in bu i\u015flevin nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir:<\/span><\/p>\n Sonu\u00e7ta veri \u00e7er\u00e7evelerinin iki sat\u0131r\u0131n ortak oldu\u011funu g\u00f6rebiliriz.<\/span><\/p>\n Bu intersect()<\/strong> fonksiyonunun yaln\u0131zca iki veri \u00e7er\u00e7evesi aras\u0131ndaki her<\/em> s\u00fctunda ayn\u0131 de\u011ferlere sahip sat\u0131rlar\u0131 d\u00f6nd\u00fcrece\u011fini unutmay\u0131n.<\/span><\/p>\n Ayr\u0131ca, iki veri \u00e7er\u00e7evesinin ortak oldu\u011fu sat\u0131r say\u0131s\u0131n\u0131 bulmak i\u00e7in uzunluk()<\/strong> i\u015flevini intersect()<\/strong> i\u015fleviyle birlikte kullanabilece\u011fimizi de unutmay\u0131n:<\/span><\/p>\n Sonu\u00e7tan her iki veri \u00e7er\u00e7evesinin de ortak 2<\/strong> sat\u0131r\u0131 oldu\u011funu g\u00f6rebiliriz.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’deki di\u011fer yayg\u0131n i\u015flevlerin nas\u0131l kullan\u0131laca\u011f\u0131 a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de dim() i\u015flevi nas\u0131l kullan\u0131l\u0131r?<\/a> \u0130ki nesnenin kesi\u015fimini bulmak i\u00e7in R taban\u0131ndaki intersect() i\u015flevini kullanabilirsiniz. “Kesi\u015fme” basit\u00e7e iki nesnenin ortak oldu\u011fu unsurlar\u0131 temsil eder. Bu i\u015flev a\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullan\u0131r: intersect(object1, object2) A\u015fa\u011f\u0131daki \u00f6rnekler intersect() fonksiyonunun vekt\u00f6rler ve veri \u00e7er\u00e7eveleriyle nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir. \u00d6rnek 1: Intersect() fonksiyonunu vekt\u00f6rlerle kullanma A\u015fa\u011f\u0131daki kod, R’deki iki vekt\u00f6r aras\u0131ndaki kesi\u015fimi bulmak i\u00e7in intersect() i\u015flevinin […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3216","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n intersect(object1, object2)<\/strong><\/pre>\n
\u00d6rnek 1: Intersect() fonksiyonunu vekt\u00f6rlerle kullanma<\/strong><\/span><\/h3>\n
#define two vectors\n<\/span>x <- c(1, 4, 5, 5, 9, 12, 19)\ny <- c(1, 2, 5, 5, 10, 14, 19)\n\n#find intersection between two vectors\n<\/span>intersect(x,y)\n\n[1] 1 5 19\n<\/strong><\/pre>\n #define two vectors\n<\/span>x <- c('A', 'B', 'C', 'D', 'E')\ny <- c('C', 'D', 'E', 'F')\n\n#find intersection between two vectors\n<\/span>intersect(x,y)\n\n[1] \u201cC\u201d \u201cD\u201d \u201cE\u201d\n<\/strong><\/pre>\n \u00d6rnek 2: Intersect() i\u015flevini veri \u00e7er\u00e7eveleriyle kullanma<\/strong><\/span><\/h3>\n
library<\/span> (dplyr) \n\n#define two data frames\n<\/span>df1 <- data. frame<\/span> (team=c('A', 'A', 'B', 'B'),\n dots=c(12, 20, 25, 19))\n\ndf1\n\n team points\n1 to 12\n2 to 20\n3 B 25\n4 B 19\n\ndf2 <- data. frame<\/span> (team=c('A', 'A', 'B', 'C'),\n dots=c(12, 22, 25, 32))\n\ndf2\n\n team points\n1 to 12\n2 to 22\n3 B 25\n4 C 32\n\n#find intersection between two data frames\n<\/span>dplyr::intersect(df1, df2)\n\n team points\n1 to 12\n2 B 25<\/strong><\/pre>\n #find number of rows in common between the two data frames\n<\/span>length(dplyr::intersect(df1, df2))\n\n[1] 2\n<\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h3>\n
R’de transform() i\u015flevi nas\u0131l kullan\u0131l\u0131r?<\/a>
R’de swep () i\u015flevi nas\u0131l kullan\u0131l\u0131r?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"