<\/p>\n
\u00c7o\u011funlukla, R’deki bir veri \u00e7er\u00e7evesindeki belirli s\u00fctunlara bir i\u015flev uygulamak i\u00e7in Apply()<\/strong> i\u015flevini kullanmak isteyebilirsiniz.<\/span><\/span><\/p>\n Bununla birlikte, application()<\/strong> i\u015flevi, bir i\u015flevi uygulamadan \u00f6nce ilk olarak bir veri \u00e7er\u00e7evesindeki t\u00fcm s\u00fctunlar\u0131n ayn\u0131 nesne t\u00fcr\u00fcne sahip olmas\u0131n\u0131 zorlar ve bu bazen istenmeyen sonu\u00e7lara yol a\u00e7abilir.<\/span><\/p>\n A\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullanan lapply()<\/strong> i\u015flevi daha iyi bir se\u00e7imdir:<\/span><\/p>\n Bu \u00f6zel \u00f6rnek, my_function<\/strong> i\u015flevini yaln\u0131zca veri \u00e7er\u00e7evesindeki col1<\/strong> ve col2’ye<\/strong> uygular.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnek, bu s\u00f6zdiziminin pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir.<\/span><\/p>\n R’de a\u015fa\u011f\u0131daki veri \u00e7er\u00e7evesine sahip oldu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n \u015eimdi de\u011ferleri 2 ile \u00e7arp\u0131p ard\u0131ndan 1 ekleyen a\u015fa\u011f\u0131daki fonksiyonu tan\u0131mlad\u0131\u011f\u0131m\u0131z\u0131 varsayal\u0131m:<\/span><\/span><\/p>\n Bu i\u015flevi yaln\u0131zca veri \u00e7er\u00e7evesindeki noktalara<\/strong> ve s\u0131\u00e7rama<\/strong> s\u00fctunlar\u0131na uygulamak i\u00e7in a\u015fa\u011f\u0131daki lapply()<\/strong> i\u015flevini kullanabiliriz:<\/span><\/p>\n Sonu\u00e7ta say\u0131<\/strong> ve ribaund<\/strong> s\u00fctunlar\u0131ndaki her de\u011feri 2 ile \u00e7arpt\u0131\u011f\u0131m\u0131z\u0131 ve ard\u0131ndan 1 ekledi\u011fimizi g\u00f6rebiliriz.<\/span><\/p>\n Ayr\u0131ca tak\u0131mlar<\/strong> ve asist<\/strong> s\u00fctunlar\u0131n\u0131n de\u011fi\u015fmedi\u011fini unutmay\u0131n.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’de di\u011fer ortak g\u00f6revlerin nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de application(), lapply(), sapply() ve tapply() i\u00e7in bir k\u0131lavuz<\/a> \u00c7o\u011funlukla, R’deki bir veri \u00e7er\u00e7evesindeki belirli s\u00fctunlara bir i\u015flev uygulamak i\u00e7in Apply() i\u015flevini kullanmak isteyebilirsiniz. Bununla birlikte, application() i\u015flevi, bir i\u015flevi uygulamadan \u00f6nce ilk olarak bir veri \u00e7er\u00e7evesindeki t\u00fcm s\u00fctunlar\u0131n ayn\u0131 nesne t\u00fcr\u00fcne sahip olmas\u0131n\u0131 zorlar ve bu bazen istenmeyen sonu\u00e7lara yol a\u00e7abilir. A\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullanan lapply() i\u015flevi daha iyi bir se\u00e7imdir: df[c(‘ col1 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3288","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n df[c(' col1<\/span> ', ' col2<\/span> ')] <- lapply(df[c(' col1<\/span> ', ' col2<\/span> ')], my_function)\n<\/strong><\/pre>\n \u00d6rnek: veri \u00e7er\u00e7evesindeki belirli s\u00fctunlara bir i\u015flev uygulama<\/strong><\/span><\/h2>\n
#create data frame\n<\/span>df <- data. frame<\/span> (team=c('A', 'A', 'A', 'A', 'B', 'B', 'B', 'B'),\n points=c(19, 22, 15, NA, 14, 25, 25, 25),\n rebounds=c(10, 6, 3, 7, 11, 13, 9, 12),\n assists=c(4, 4, 3, 6, 7, 5, 10, 8))\n\n#view data frame\n<\/span>df\n\n team points rebound assists\n1 A 19 10 4\n2 A 22 6 4\n3 to 15 3 3\n4 A NA 7 6\n5 B 14 11 7\n6 B 25 13 5\n7 B 25 9 10\n8 B 25 12 8<\/strong><\/pre>\n #define function\nmy_function <- function<\/span> (x) x*2 + 1<\/span><\/span><\/strong><\/span><\/pre>\n #apply function to specific columns\n<\/span>df[c(' points<\/span> ', ' rebounds<\/span> ')] <- lapply(df[c(' points<\/span> ', ' rebounds<\/span> ')], my_function)\n\n#view updated data frame\n<\/span>df\n\n team points rebound assists\n1 A 39 21 4\n2 A 45 13 4\n3 A 31 7 3\n4 A NA 15 6\n5 B 29 23 7\n6 B 51 27 5\n7 B 51 19 10\n8 B 51 25 8\n<\/strong><\/span><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h2>\n
R’de d\u00f6n\u00fc\u015ft\u00fcrme i\u015flevi nas\u0131l kullan\u0131l\u0131r?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"