<\/p>\n
Bir pop\u00fclasyon ortalamas\u0131n\u0131n belirli bir de\u011fere e\u015fit olup olmad\u0131\u011f\u0131n\u0131 belirlemek i\u00e7in tek \u00f6rnekli t testi<\/a> kullan\u0131l\u0131r.<\/span><\/p>\n Tek \u00f6rnekli bir t testi ger\u00e7ekle\u015ftirmek i\u00e7in R’de a\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullanabilirsiniz:<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnek, bu s\u00f6zdiziminin pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir.<\/span><\/p>\n Bir botanik\u00e7inin belirli bir bitki t\u00fcr\u00fcn\u00fcn ortalama boyunun 15 in\u00e7 olup olmad\u0131\u011f\u0131n\u0131 bilmek istedi\u011fini varsayal\u0131m.<\/span><\/p>\n 12 bitkiden rastgele basit bir \u00f6rnek<\/a> al\u0131yor ve her birinin y\u00fcksekli\u011fini in\u00e7 cinsinden kaydediyor.<\/span><\/p>\n Bu bitki t\u00fcr\u00fcn\u00fcn ortalama boyunun ger\u00e7ekte 15 in\u00e7 olup olmad\u0131\u011f\u0131n\u0131 belirlemek amac\u0131yla R’de tek \u00f6rnekli bir t testi ger\u00e7ekle\u015ftirmek i\u00e7in a\u015fa\u011f\u0131daki kodu kullanabilir:<\/span><\/p>\n \u00c7\u0131kt\u0131daki her de\u011ferin nas\u0131l yorumlanaca\u011f\u0131 a\u015fa\u011f\u0131da a\u00e7\u0131klanm\u0131\u015ft\u0131r:<\/span><\/p>\n data<\/strong> : t-testinde kullan\u0131lan vekt\u00f6r\u00fcn ad\u0131. Bu \u00f6rnekte my_data’y\u0131<\/strong> kulland\u0131k.<\/span><\/p>\n t<\/strong> : ( x<\/span> \u2013 \u03bc) \/ (s\u221a n<\/span> ) = (14,333-15)\/(1,370689\/\u221a 12<\/span> ) = -1,6848<\/strong> olarak hesaplanan t testi istatisti\u011fi.<\/span><\/p>\n df<\/strong> : n-1 = 12-1 = 11<\/strong> \u015feklinde hesaplanan serbestlik derecesi.<\/span><\/p>\n p-de\u011feri<\/strong> : -1,6848 test istatisti\u011fine ve 11 serbestlik derecesine kar\u015f\u0131l\u0131k gelen iki kuyruklu p de\u011feri. Bu durumda p = 0,1201<\/strong> .<\/span><\/p>\n %95 G\u00fcven Aral\u0131\u011f\u0131<\/strong> : [13.46244, 15.20423]<\/strong> olarak hesaplanan ger\u00e7ek pop\u00fclasyon ortalamas\u0131 i\u00e7in %95 g\u00fcven aral\u0131\u011f\u0131.<\/span><\/p>\n Bu tek \u00f6rneklemli t testi i\u00e7in bo\u015f ve alternatif hipotezler a\u015fa\u011f\u0131daki gibidir:<\/span><\/p>\n H 0<\/sub> :<\/strong> \u00b5 = 15 (Bu bitki t\u00fcr\u00fcn\u00fcn ortalama boyu 15 in\u00e7tir)<\/span><\/p>\n H A<\/sub> :<\/strong> \u00b5 \u226015 (ortalama y\u00fckseklik 15 in\u00e7 de\u011fil<\/em> )<\/span><\/p>\n Testimizin p de\u011feri (0,1201)<\/strong> 0,05’ten b\u00fcy\u00fck oldu\u011fundan testin s\u0131f\u0131r hipotezini reddedemiyoruz.<\/span><\/p>\n Bu, bu belirli bitki t\u00fcr\u00fcn\u00fcn ortalama boyunun 15 in\u00e7ten farkl\u0131 oldu\u011funu s\u00f6yleyecek yeterli kan\u0131t\u0131m\u0131z olmad\u0131\u011f\u0131 anlam\u0131na geliyor.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’de di\u011fer yayg\u0131n testlerin nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de iki \u00f6rnekli T testi nas\u0131l yap\u0131l\u0131r<\/a> Bir pop\u00fclasyon ortalamas\u0131n\u0131n belirli bir de\u011fere e\u015fit olup olmad\u0131\u011f\u0131n\u0131 belirlemek i\u00e7in tek \u00f6rnekli t testi kullan\u0131l\u0131r. Tek \u00f6rnekli bir t testi ger\u00e7ekle\u015ftirmek i\u00e7in R’de a\u015fa\u011f\u0131daki temel s\u00f6zdizimini kullanabilirsiniz: t. test (data, mu= 10 ) A\u015fa\u011f\u0131daki \u00f6rnek, bu s\u00f6zdiziminin pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6sterir. \u00d6rnek: R’deki bir T testi \u00f6rne\u011fi Bir botanik\u00e7inin belirli bir bitki t\u00fcr\u00fcn\u00fcn ortalama […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3428","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n t. test<\/span> (data, mu= 10<\/span> )<\/strong><\/pre>\n \u00d6rnek: R’deki bir T testi \u00f6rne\u011fi<\/strong><\/h2>\n
#create vector to hold plant heights<\/span>\nmy_data <- c(14, 14, 16, 13, 12, 17, 15, 14, 15, 13, 15, 14)\n\n#perform one sample t-test<\/span>\nt. test<\/span> (my_data, mu= 15<\/span> )\n\n\tOne Sample t-test\n\ndata:my_data\nt = -1.6848, df = 11, p-value = 0.1201\nalternative hypothesis: true mean is not equal to 15\n95 percent confidence interval:\n 13.46244 15.20423\nsample estimates:\nmean of x \n 14.33333 \n<\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h2>\n
R’de e\u015fle\u015ftirilmi\u015f \u00f6rnekler t testi nas\u0131l yap\u0131l\u0131r<\/a>
R’de Welch’in T testi nas\u0131l ger\u00e7ekle\u015ftirilir?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"