{"id":3678,"date":"2023-07-16T04:32:52","date_gmt":"2023-07-16T04:32:52","guid":{"rendered":"https:\/\/statorials.org\/tr\/ne-a-ne-de-b-olasiligi\/"},"modified":"2023-07-16T04:32:52","modified_gmt":"2023-07-16T04:32:52","slug":"ne-a-ne-de-b-olasiligi","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/ne-a-ne-de-b-olasiligi\/","title":{"rendered":"Ne a&#39;n\u0131n ne de b&#39;nin olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur?"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\">A ve B olmak \u00fczere iki olay verildi\u011finde, &#8220;ne A&#8217;n\u0131n ne de B&#8217;nin olma olas\u0131l\u0131\u011f\u0131n\u0131 bulmak&#8221; <strong>, ne A olay\u0131n\u0131n ne de B olay\u0131n\u0131n meydana gelmeme olas\u0131l\u0131\u011f\u0131n\u0131 bulmak anlam\u0131na gelir.<\/strong><\/span><\/p>\n<p> <span style=\"color: #000000;\">Bu olas\u0131l\u0131\u011f\u0131 hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullan\u0131r\u0131z:<\/span><\/p>\n<p> <strong><span style=\"color: #000000;\">P(Ni A Ni B) = 1 \u2013 ( P(A) + P(B) \u2013 P(A\u2229B) )<\/span><\/strong><\/p>\n<p> <span style=\"color: #000000;\">Alt\u0131n:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">P(A): A olay\u0131n\u0131n ger\u00e7ekle\u015fme olas\u0131l\u0131\u011f\u0131.<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(B): B olay\u0131n\u0131n ger\u00e7ekle\u015fme olas\u0131l\u0131\u011f\u0131.<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(A\u2229B): A olay\u0131n\u0131n ve B olay\u0131n\u0131n her ikisinin de meydana gelme olas\u0131l\u0131\u011f\u0131.<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki \u00f6rnekler bu form\u00fcl\u00fcn pratikte nas\u0131l kullan\u0131laca\u011f\u0131n\u0131 g\u00f6stermektedir.<\/span><\/p>\n<h2> <span style=\"color: #000000;\"><strong>\u00d6rnek 1: Ne A&#8217;n\u0131n ne de B&#8217;nin olas\u0131l\u0131\u011f\u0131 (basketbolcular)<\/strong><\/span><\/h2>\n<p> <span style=\"color: #000000;\">Belirli bir kolej basketbol oyuncusunun NBA&#8217;e se\u00e7ilme olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0,03<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ayr\u0131ca belirli bir kolej basketbol oyuncusunun not ortalamas\u0131n\u0131n 4,0 olmas\u0131 olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0,25<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ayr\u0131ca, belirli bir kolej basketbol oyuncusunun 4.0 genel not ortalamas\u0131na sahip olmas\u0131 <em>ve<\/em> NBA&#8217;e se\u00e7ilme olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0.005<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">E\u011fer bir \u00fcniversite basketbol oyuncusunu rastgele se\u00e7ersek, onun draft edilmemesi ve not ortalamas\u0131n\u0131n 4.0 olmamas\u0131 olas\u0131l\u0131\u011f\u0131 nedir?<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7\u00f6z\u00fcm<\/strong> :<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">P (yaz\u0131l\u0131) = 0,03<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(4.0 not ortalamas\u0131) = 0.25<\/span><\/li>\n<li> <span style=\"color: #000000;\">P (\u2229 4,0 GPA yaz\u0131l\u0131r) = 0,005<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">B\u00f6ylece \u015funlar\u0131 hesaplayabiliriz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">P (Ne yaz\u0131l\u0131 ne de 4.0 GPA) = 1 \u2013 (P (yaz\u0131l\u0131) + P (4.0 GPA) \u2013 P (yaz\u0131l\u0131 \u2229 4.0 GPA))<\/span><\/li>\n<li> <span style=\"color: #000000;\">P (Ne taslak ne de 4,0 not ortalamas\u0131) = 1 \u2013 (0,03 + 0,25 \u2013 0,005)<\/span><\/li>\n<li> <span style=\"color: #000000;\">P (Ne taslak ne de 4.0 not ortalamas\u0131) = 0.715<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">E\u011fer bir \u00fcniversite basketbol oyuncusunu rastgele se\u00e7ersek, onun draft edilmemesi veya 4.0 genel not ortalamas\u0131na sahip olmamas\u0131 olas\u0131l\u0131\u011f\u0131 0.715 veya <strong>%71.5&#8217;tir<\/strong> .<\/span><\/p>\n<h2> <span style=\"color: #000000;\"><strong>\u00d6rnek 2: Ne A&#8217;n\u0131n ne de B&#8217;nin olas\u0131l\u0131\u011f\u0131 (s\u0131nav puanlar\u0131)<\/strong><\/span><\/h2>\n<p> <span style=\"color: #000000;\">Belirli bir \u00f6\u011frencinin final s\u0131nav\u0131ndan m\u00fckemmel puan alma olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0,13<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ayr\u0131ca belirli bir \u00f6\u011frencinin yeni bir \u00e7al\u0131\u015fma y\u00f6ntemi kullanma olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0,35<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Ayr\u0131ca belirli bir \u00f6\u011frencinin m\u00fckemmel puan almas\u0131 <em>ve<\/em> yeni bir \u00e7al\u0131\u015fma y\u00f6ntemi kullanmas\u0131 olas\u0131l\u0131\u011f\u0131n\u0131n <strong>0,04<\/strong> oldu\u011funu varsayal\u0131m.<\/span><\/p>\n<p> <span style=\"color: #000000;\">Bir \u00f6\u011frenciyi rastgele se\u00e7ersek, m\u00fckemmel not alamama veya yeni bir \u00e7al\u0131\u015fma y\u00f6ntemi kullanmama olas\u0131l\u0131\u011f\u0131 nedir?<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7\u00f6z\u00fcm<\/strong> :<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">P (m\u00fckemmel puan) = 0,13<\/span><\/li>\n<li> <span style=\"color: #000000;\">P (yeni y\u00f6ntem) = 0,35<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(m\u00fckemmel puan \u2229 yeni y\u00f6ntem) = 0,04<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">B\u00f6ylece \u015funlar\u0131 hesaplayabiliriz:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">P(Ne m\u00fckemmel puan ne de yeni y\u00f6ntem) = 1 \u2013 (P(m\u00fckemmel puan) + P(yeni y\u00f6ntem) \u2013 P(m\u00fckemmel puan \u2229 yeni y\u00f6ntem))<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(Ne m\u00fckemmel puan ne de yeni y\u00f6ntem) = 1 \u2013 (0,13 + 0,35 \u2013 0,04)<\/span><\/li>\n<li> <span style=\"color: #000000;\">P(Ne m\u00fckemmel puan ne de yeni y\u00f6ntem) = 0,56<\/span><\/li>\n<\/ul>\n<p> <span style=\"color: #000000;\">Bir \u00f6\u011frenciyi rastgele se\u00e7ersek, m\u00fckemmel puan alamama veya yeni bir \u00e7al\u0131\u015fma y\u00f6ntemi kullanmama olas\u0131l\u0131\u011f\u0131 0,56 veya <strong>%56&#8217;d\u0131r<\/strong> .<\/span><\/p>\n<h2> <span style=\"color: #000000;\"><strong>Ek kaynaklar<\/strong><\/span><\/h2>\n<p> <span style=\"color: #000000;\">A\u015fa\u011f\u0131daki e\u011fitimlerde olas\u0131l\u0131k ile ilgili di\u011fer hesaplamalar\u0131n nas\u0131l ger\u00e7ekle\u015ftirilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n<p> <a href=\"https:\/\/statorials.org\/tr\/a-veya-b-olasiligi\/\" target=\"_blank\" rel=\"noopener\">A veya B olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur?<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/a-ve-b-olasiligi\/\" target=\"_blank\" rel=\"noopener\">A ve B&#8217;nin olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur?<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/anin-olasiligi-b'yi-verir\/\" target=\"_blank\" rel=\"noopener\">Verilen B&#8217;nin A olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur?<\/a><br \/> <a href=\"https:\/\/statorials.org\/tr\/en-az-bir-basari-olasiligi\/\" target=\"_blank\" rel=\"noopener\">\u201cEn az bir\u201d ba\u015far\u0131 olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A ve B olmak \u00fczere iki olay verildi\u011finde, &#8220;ne A&#8217;n\u0131n ne de B&#8217;nin olma olas\u0131l\u0131\u011f\u0131n\u0131 bulmak&#8221; , ne A olay\u0131n\u0131n ne de B olay\u0131n\u0131n meydana gelmeme olas\u0131l\u0131\u011f\u0131n\u0131 bulmak anlam\u0131na gelir. Bu olas\u0131l\u0131\u011f\u0131 hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullan\u0131r\u0131z: P(Ni A Ni B) = 1 \u2013 ( P(A) + P(B) \u2013 P(A\u2229B) ) Alt\u0131n: P(A): A olay\u0131n\u0131n [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3678","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Ne A&#039;n\u0131n ne de B&#039;nin olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur - Statorials<\/title>\n<meta name=\"description\" content=\"Bu e\u011fitimde, ne A ne de B olas\u0131l\u0131\u011f\u0131n\u0131n nas\u0131l bulunaca\u011f\u0131 birka\u00e7 \u00f6rnekle a\u00e7\u0131klanmaktad\u0131r.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/statorials.org\/tr\/ne-a-ne-de-b-olasiligi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ne A&#039;n\u0131n ne de B&#039;nin olas\u0131l\u0131\u011f\u0131 nas\u0131l bulunur - 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