<\/p>\n
R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata:<\/span><\/p>\n Bu hata, bir veri \u00e7er\u00e7evesindeki bir veya daha fazla s\u00fctunun de\u011ferlerini kendi s\u00fctunlar\u0131na yaymak i\u00e7in spread()<\/strong> i\u015flevini kullanmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar.<\/span><\/p>\n Ancak her sat\u0131r i\u00e7in benzersiz bir kimlik yoksa hata olu\u015fabilir, dolay\u0131s\u0131yla da\u011f\u0131t\u0131m\u0131 \u00e7al\u0131\u015ft\u0131r\u0131rken hangi de\u011ferlerin hangi g\u00f6zlemlere ait oldu\u011funu belirlemenin bir yolu yoktur.<\/span><\/p>\n A\u015fa\u011f\u0131daki \u00f6rnekte bu hatan\u0131n pratikte nas\u0131l d\u00fczeltilece\u011fi g\u00f6sterilmektedir.<\/span><\/p>\n R’de \u00e7e\u015fitli basketbol oyuncular\u0131 hakk\u0131nda bilgi i\u00e7eren a\u015fa\u011f\u0131daki veri \u00e7er\u00e7evesine sahip oldu\u011fumuzu varsayal\u0131m:<\/span><\/p>\n \u015eimdi, veri \u00e7er\u00e7evesini kimlik s\u00fctunu olarak y\u0131l<\/strong> s\u00fctununa sahip olacak \u015fekilde d\u00f6n\u00fc\u015ft\u00fcrmek istedi\u011fimizi ve her y\u0131l boyunca A ve B oyuncular\u0131n\u0131n asistlerini ve puan de\u011ferlerini temsil etmek i\u00e7in asist_A<\/strong> , asist_B<\/strong> , puan_A<\/strong> ve puan_B<\/strong> ad\u0131 verilen yeni s\u00fctunlar olu\u015fturmak istedi\u011fimizi varsayal\u0131m. .<\/span><\/p>\n Y\u0131l s\u00fctunundaki de\u011ferler benzersiz olmayaca\u011f\u0131ndan (iki adet 1, iki adet 2 vb. olacakt\u0131r), spread()<\/strong> i\u015flevi hata \u00fcretecektir.<\/span><\/p>\n Ancak istenen veri \u00e7er\u00e7evesini \u00fcretmek i\u00e7in pivot_wider()<\/strong> i\u015flevini a\u015fa\u011f\u0131daki s\u00f6zdizimiyle kullanabiliriz:<\/span><\/p>\n Herhangi bir hata almad\u0131\u011f\u0131m\u0131z\u0131 ve d\u00f6rt y\u0131l\u0131n her birinde Oyuncu A ve B’nin puan ve asist de\u011ferlerini g\u00f6steren yeni s\u00fctunlar\u0131 ba\u015far\u0131yla olu\u015fturabildi\u011fimizi unutmay\u0131n.<\/span><\/p>\n A\u015fa\u011f\u0131daki e\u011fitimlerde R’deki di\u011fer yayg\u0131n hatalar\u0131n nas\u0131l d\u00fczeltilece\u011fi a\u00e7\u0131klanmaktad\u0131r:<\/span><\/p>\n R’de nas\u0131l d\u00fczeltilir: Zorlamayla ortaya \u00e7\u0131kan NA’lar<\/a> R’de kar\u015f\u0131la\u015fabilece\u011finiz bir hata: Error: Duplicate identifiers for rows Bu hata, bir veri \u00e7er\u00e7evesindeki bir veya daha fazla s\u00fctunun de\u011ferlerini kendi s\u00fctunlar\u0131na yaymak i\u00e7in spread() i\u015flevini kullanmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131zda ortaya \u00e7\u0131kar. Ancak her sat\u0131r i\u00e7in benzersiz bir kimlik yoksa hata olu\u015fabilir, dolay\u0131s\u0131yla da\u011f\u0131t\u0131m\u0131 \u00e7al\u0131\u015ft\u0131r\u0131rken hangi de\u011ferlerin hangi g\u00f6zlemlere ait oldu\u011funu belirlemenin bir yolu yoktur. A\u015fa\u011f\u0131daki \u00f6rnekte […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-3819","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n Error: Duplicate identifiers for rows\n<\/strong><\/pre>\n
\u00d6rnek: Hata nas\u0131l d\u00fczeltilir?<\/strong><\/h2>\n
#create data frame\n<\/span>df <- data. frame<\/span> (player=rep(c(' A<\/span> ', ' B<\/span> '), each= 4<\/span> ),\n year=rep(1:4, times= 2<\/span> ),\n assists=c(4, 10, 4, 4, 3, 7, 7, 6),\n dots=c(14, 6, 18, 7, 22, 9, 38, 4))\n\n#view data frame\n<\/span>df\n\n player year assists points\n1 A 1 4 14\n2 A 2 10 6\n3 To 3 4 18\n4 To 4 4 7\n5 B 1 3 22\n6 B 2 7 9\n7 B 3 7 38\n8 B 4 6 4\n<\/strong><\/pre>\n library<\/span> (tidyr)\n\n#spread the values in the points and assists columns\n<\/span>pivot_wider(data = df, \n id_cols = year, \n names_from = player, \n values_from = c(' assists<\/span> ', ' points<\/span> '))\n\n# A tibble: 4 x 5\n year assists_A assists_B points_A points_B\n \n1 1 4 3 14 22\n2 2 10 7 6 9\n3 3 4 7 18 38\n4 4 4 6 7 4<\/span><\/span><\/strong><\/pre>\n Ek kaynaklar<\/strong><\/span><\/h2>\n
R’de nas\u0131l onar\u0131l\u0131r: s\u0131n\u0131rlar\u0131n d\u0131\u015f\u0131nda dizin<\/a>
R’de nas\u0131l d\u00fczeltilir: Daha uzun bir nesnenin uzunlu\u011fu, daha k\u0131sa bir nesnenin uzunlu\u011funun kat\u0131 de\u011fildir<\/a>
R’de onar\u0131m nas\u0131l yap\u0131l\u0131r: De\u011fi\u015ftirilecek eleman say\u0131s\u0131, de\u011fi\u015ftirme uzunlu\u011funun kat\u0131 de\u011fildir<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"