{"id":454,"date":"2023-07-29T20:50:57","date_gmt":"2023-07-29T20:50:57","guid":{"rendered":"https:\/\/statorials.org\/tr\/duzgun-dagilim-r\/"},"modified":"2023-07-29T20:50:57","modified_gmt":"2023-07-29T20:50:57","slug":"duzgun-dagilim-r","status":"publish","type":"post","link":"https:\/\/statorials.org\/tr\/duzgun-dagilim-r\/","title":{"rendered":"R&#39;deki d\u00fczg\u00fcn da\u011f\u0131l\u0131m"},"content":{"rendered":"<p><\/p>\n<hr>\n<p><span style=\"color: #000000;\"><a href=\"https:\/\/statorials.org\/tr\/uniforma-dagitimi\/\" target=\"_blank\" rel=\"noopener\">D\u00fczg\u00fcn da\u011f\u0131l\u0131m,<\/a> <em>a&#8217;dan<\/em> <em>b&#8217;ye<\/em> kadar olan aral\u0131ktaki her de\u011ferin ayn\u0131 se\u00e7ilme olas\u0131l\u0131\u011f\u0131na sahip oldu\u011fu bir olas\u0131l\u0131k da\u011f\u0131l\u0131m\u0131d\u0131r.<\/span><\/p>\n<p> <span style=\"color: #000000;\"><em>a&#8217;dan<\/em> <em>b&#8217;ye<\/em> kadar bir aral\u0131kta x <sub>1<\/sub> ile x <sub>2<\/sub> aras\u0131nda bir de\u011fer elde etme olas\u0131l\u0131\u011f\u0131 a\u015fa\u011f\u0131daki form\u00fcl kullan\u0131larak bulunabilir:<\/span><\/p>\n<p style=\"text-align: center;\"> <span style=\"color: #000000;\">P(x <sub>1<\/sub> ile x <sub>2<\/sub> aras\u0131nda bir de\u011fer elde edin) = (x <sub>2<\/sub> \u2013 x <sub>1<\/sub> ) \/ (b \u2013 a)<\/span> <\/p>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"aligncenter wp-image-1565 size-full\" src=\"https:\/\/statorials.org\/wp-content\/uploads\/2023\/08\/uniforme_pic.jpg\" sizes=\"auto, \" srcset=\"\" alt=\"Tekd\u00fcze da\u011f\u0131l\u0131m \u00f6rne\u011fi\" width=\"336\" height=\"203\"><\/p>\n<p> <span style=\"color: #000000;\">D\u00fczg\u00fcn da\u011f\u0131l\u0131m a\u015fa\u011f\u0131daki \u00f6zelliklere sahiptir:<\/span><\/p>\n<ul>\n<li> <span style=\"color: #000000;\">Da\u011f\u0131l\u0131m\u0131n ortalamas\u0131 <strong>\u03bc<\/strong> = (a + b) \/ 2<\/span><\/li>\n<li> <span style=\"color: #000000;\">Da\u011f\u0131l\u0131m\u0131n varyans\u0131 <strong>\u03c3 <sup>2<\/sup><\/strong> = (b \u2013 a) <sup>2<\/sup> \/ 12<\/span><\/li>\n<li> <span style=\"color: #000000;\">Da\u011f\u0131l\u0131m\u0131n standart sapmas\u0131 <strong>\u03c3<\/strong> = \u221a\u03c3 <sup>2&#8217;dir<\/sup><\/span><\/li>\n<\/ul>\n<h2> <strong>R&#8217;de tekd\u00fcze da\u011f\u0131l\u0131m: s\u00f6zdizimi<\/strong><\/h2>\n<p> <span style=\"color: #000000;\">Tek tip da\u011f\u0131l\u0131m kullanarak sorular\u0131 yan\u0131tlamak i\u00e7in kullanaca\u011f\u0131m\u0131z R&#8217;deki iki yerle\u015fik i\u015flev \u015funlard\u0131r:<\/span><\/p>\n<p> <strong><span style=\"color: #000000;\">dunif(x, min, max)<\/span><\/strong> <span style=\"color: #000000;\">\u2013 <em>x&#8217;in<\/em> rastgele bir de\u011fi\u015fkenin de\u011feri oldu\u011fu ve <em>min<\/em> ve <em>max&#8217;\u0131n<\/em> s\u0131ras\u0131yla da\u011f\u0131l\u0131m\u0131n minimum ve maksimum say\u0131lar\u0131 oldu\u011fu tekd\u00fcze da\u011f\u0131l\u0131m i\u00e7in olas\u0131l\u0131k yo\u011funluk fonksiyonunu (pdf) hesaplar.<\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>punif(x, min, max)<\/strong> \u2013 tekd\u00fcze da\u011f\u0131l\u0131m i\u00e7in k\u00fcm\u00fclatif da\u011f\u0131l\u0131m fonksiyonunu (cdf) hesaplar; burada <em>x<\/em> , rastgele bir de\u011fi\u015fkenin de\u011feridir ve <em>min<\/em> ve <em>max<\/em> , s\u0131ras\u0131yla da\u011f\u0131l\u0131m\u0131n minimum ve maksimum say\u0131lar\u0131d\u0131r.<\/span><\/p>\n<p> <em><span style=\"color: #000000;\">Tek tip da\u011f\u0131t\u0131m i\u00e7in R belgelerinin tamam\u0131n\u0131 <a href=\"https:\/\/stat.ethz.ch\/R-manual\/R-devel\/library\/stats\/html\/Uniform.html\" target=\"_blank\" rel=\"noopener\">burada<\/a> bulabilirsiniz.<\/span><\/em><\/p>\n<h2> <span style=\"color: #000000;\"><strong>R&#8217;de d\u00fczg\u00fcn da\u011f\u0131l\u0131m kullanarak sorunlar\u0131 \u00e7\u00f6zme<\/strong><\/span><\/h2>\n<p> <span style=\"color: #000000;\"><strong>\u00d6rnek 1:<\/strong> <i>Her 20 dakikada bir otob\u00fcs dura\u011f\u0131na bir otob\u00fcs gelmektedir. Otob\u00fcs dura\u011f\u0131na vard\u0131\u011f\u0131n\u0131zda otob\u00fcs\u00fcn 8 dakika veya daha k\u0131sa s\u00fcrede gelme olas\u0131l\u0131\u011f\u0131 nedir?<\/i><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7\u00f6z\u00fcm:<\/strong> Otob\u00fcs\u00fcn 8 dakika veya daha k\u0131sa s\u00fcrede g\u00f6r\u00fcnme olas\u0131l\u0131\u011f\u0131n\u0131 bilmek istedi\u011fimizden, otob\u00fcs\u00fcn 8 dakika veya daha k\u0131sa s\u00fcrede g\u00f6r\u00fcnme olas\u0131l\u0131\u011f\u0131n\u0131 bilmek istedi\u011fimiz i\u00e7in basit\u00e7e punif() fonksiyonunu kullanabiliriz. minimum s\u00fcre 0 dakika ve maksimum s\u00fcre 20 dakikad\u0131r:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>punitive(8, min=0, max=20)<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>## [1] 0.4<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Otob\u00fcs\u00fcn 8 dakika veya daha k\u0131sa s\u00fcrede gelme olas\u0131l\u0131\u011f\u0131 <strong>0,4&#8217;t\u00fcr<\/strong> .<\/span><\/p>\n<hr>\n<p> <span style=\"color: #000000;\"><strong>\u00d6rnek 2:<\/strong> <i>Belirli bir kurba\u011fa t\u00fcr\u00fcn\u00fcn a\u011f\u0131rl\u0131\u011f\u0131 15 ila 25 gram aras\u0131nda e\u015fit olarak da\u011f\u0131lm\u0131\u015ft\u0131r. Rastgele bir kurba\u011fa se\u00e7erseniz a\u011f\u0131rl\u0131\u011f\u0131n\u0131n 17 ile 19 gram aras\u0131nda olma olas\u0131l\u0131\u011f\u0131 nedir?<\/i><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7\u00f6z\u00fcm:<\/strong> \u00c7\u00f6z\u00fcm\u00fc bulmak i\u00e7in, bir kurba\u011fan\u0131n 19 pound&#8217;dan daha az a\u011f\u0131rl\u0131\u011fa sahip oldu\u011fu k\u00fcm\u00fclatif olas\u0131l\u0131\u011f\u0131n\u0131 hesaplayaca\u011f\u0131z, ard\u0131ndan a\u015fa\u011f\u0131daki s\u00f6zdizimini kullanarak bir kurba\u011fan\u0131n 17 pound&#8217;dan daha az a\u011f\u0131rl\u0131\u011fa sahip oldu\u011fu k\u00fcm\u00fclatif olas\u0131l\u0131\u011f\u0131n\u0131 \u00e7\u0131karaca\u011f\u0131z:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>punitive(19, 15, 25) - punitive(17, 15, 25)\n<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"><strong>## [1] 0.2<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Yani kurba\u011fan\u0131n a\u011f\u0131rl\u0131\u011f\u0131n\u0131n 17 ile 19 gram aras\u0131nda olma olas\u0131l\u0131\u011f\u0131 <strong>0,2&#8217;dir<\/strong> .<\/span><\/p>\n<hr>\n<p> <span style=\"color: #000000;\"><strong>\u00d6rnek 3:<\/strong> <em>Bir NBA ma\u00e7\u0131n\u0131n s\u00fcresi 120 ila 170 dakika aras\u0131nda e\u015fit olarak da\u011f\u0131t\u0131lm\u0131\u015ft\u0131r. Rastgele se\u00e7ilen bir NBA ma\u00e7\u0131n\u0131n 150 dakikadan fazla s\u00fcrme olas\u0131l\u0131\u011f\u0131 nedir?<\/em><\/span><\/p>\n<p> <span style=\"color: #000000;\"><strong>\u00c7\u00f6z\u00fcm:<\/strong> Bu soruyu cevaplamak i\u00e7in form\u00fcl 1 \u2013 (oyunun 150 dakikadan az s\u00fcrmesi olas\u0131l\u0131\u011f\u0131) kullanabiliriz. Bu \u015fu \u015fekilde verilmektedir:<\/span><\/p>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>1 - punitive(150, 120, 170)<\/strong><\/pre>\n<pre style=\"background-color: #e5e5e5; font-size: 15px;\"> <strong>## [1] 0.4<\/strong><\/pre>\n<p> <span style=\"color: #000000;\">Rastgele se\u00e7ilen bir NBA ma\u00e7\u0131n\u0131n 150 dakikadan fazla s\u00fcrme olas\u0131l\u0131\u011f\u0131 <strong>0,4&#8217;t\u00fcr<\/strong> .<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>D\u00fczg\u00fcn da\u011f\u0131l\u0131m, a&#8217;dan b&#8217;ye kadar olan aral\u0131ktaki her de\u011ferin ayn\u0131 se\u00e7ilme olas\u0131l\u0131\u011f\u0131na sahip oldu\u011fu bir olas\u0131l\u0131k da\u011f\u0131l\u0131m\u0131d\u0131r. a&#8217;dan b&#8217;ye kadar bir aral\u0131kta x 1 ile x 2 aras\u0131nda bir de\u011fer elde etme olas\u0131l\u0131\u011f\u0131 a\u015fa\u011f\u0131daki form\u00fcl kullan\u0131larak bulunabilir: P(x 1 ile x 2 aras\u0131nda bir de\u011fer elde edin) = (x 2 \u2013 x 1 ) \/ [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-454","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - 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