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\u00d6\u011frencilerin s\u0131kl\u0131kla kar\u0131\u015ft\u0131rd\u0131\u011f\u0131 iki istatistiksel test F-Test<\/strong> ve T-Test’tir<\/strong> . Bu e\u011fitimde iki test aras\u0131ndaki fark a\u00e7\u0131klanmaktad\u0131r.<\/span><\/p>\n \u0130ki pop\u00fclasyon varyans\u0131n\u0131n e\u015fit olup olmad\u0131\u011f\u0131n\u0131 test etmek i\u00e7in F testi<\/strong> kullan\u0131l\u0131r. Testin s\u0131f\u0131r ve alternatif hipotezleri a\u015fa\u011f\u0131daki gibidir:<\/span><\/p>\n H 0<\/sub> :<\/strong> \u03c3 1<\/sub> 2<\/sup> = \u03c3 2<\/sub> 2<\/sup> (n\u00fcfus varyanslar\u0131 e\u015fittir)<\/span><\/p>\n H 1<\/sub> :<\/strong> \u03c3 1<\/sub> 2<\/sup> \u2260 \u03c3 2<\/sub> 2<\/sup> (pop\u00fclasyon varyanslar\u0131 e\u015fit de\u011fildir<\/em> )<\/span><\/p>\n F testi istatisti\u011fi s 1<\/sub> 2<\/sup> \/ s 2<\/sub> 2<\/sup> olarak hesaplan\u0131r.<\/span><\/p>\n Test istatisti\u011finin p de\u011feri belirli bir anlaml\u0131l\u0131k d\u00fczeyinin alt\u0131ndaysa (ortak se\u00e7enekler 0,10, 0,05 ve 0,01’dir), bu durumda s\u0131f\u0131r hipotezi reddedilir.<\/span><\/p>\n \u00d6rnek: E\u015fit varyanslar i\u00e7in F testi<\/strong><\/span><\/p>\n Bir ara\u015ft\u0131rmac\u0131, iki bitki t\u00fcr\u00fc aras\u0131ndaki boy fark\u0131n\u0131n ayn\u0131 olup olmad\u0131\u011f\u0131n\u0131 bilmek istiyor. Bunu test etmek i\u00e7in her pop\u00fclasyondan rastgele 20 bitki \u00f6rne\u011fi topluyor ve her \u00f6rnek i\u00e7in \u00f6rnek varyans\u0131n\u0131 hesapl\u0131yor.<\/span><\/p>\n F testi istatisti\u011fi 4,38712 ve buna kar\u015f\u0131l\u0131k gelen p de\u011feri 0,0191 olarak ortaya \u00e7\u0131k\u0131yor. Bu p de\u011feri 0,05’ten k\u00fc\u00e7\u00fck oldu\u011fundan F testinin s\u0131f\u0131r hipotezini reddeder. Bu da iki bitki t\u00fcr\u00fc aras\u0131ndaki boy fark\u0131n\u0131n e\u015fit olmad\u0131\u011f\u0131n\u0131<\/em> s\u00f6ylemek i\u00e7in yeterli delilin oldu\u011fu anlam\u0131na geliyor.<\/span><\/p>\n \u0130ki \u00f6rneklem t testi,<\/strong> iki pop\u00fclasyonun ortalamalar\u0131n\u0131n e\u015fit olup olmad\u0131\u011f\u0131n\u0131 test etmek i\u00e7in kullan\u0131l\u0131r.<\/span><\/p>\n \u0130ki \u00f6rnekli bir t testi her zaman a\u015fa\u011f\u0131daki bo\u015f hipotezi kullan\u0131r:<\/span><\/p>\n Alternatif hipotez iki tarafl\u0131, sol veya sa\u011f olabilir:<\/span><\/p>\n Test istatisti\u011fi \u015fu \u015fekilde hesaplan\u0131r:<\/span><\/p>\n Test istatisti\u011fi:<\/strong> ( x<\/span> 1<\/sub> \u2013 x<\/span> 2<\/sub> ) \/ s p<\/sub> (\u221a1\/n 1<\/sub> + 1\/n 2<\/sub> )<\/span><\/p>\n burada x<\/span> 1<\/sub> ve x<\/span> 2<\/sub> \u00f6rnek ortalamalar\u0131d\u0131r, n 1<\/sub> ve n 2<\/sub> \u00f6rnek boyutlar\u0131d\u0131r ve burada s p<\/sub> a\u015fa\u011f\u0131daki \u015fekilde hesaplan\u0131r:<\/span><\/p>\n s p<\/sub><\/strong> = \u221a (n 1<\/sub> -1)s 1<\/sub> 2<\/sup> + (n 2<\/sub> -1)s 2<\/sub> 2<\/sup> \/ (n 1<\/sub> +n 2<\/sub> -2)<\/span><\/p>\n burada s 1<\/sub> 2<\/sup> ve s 2<\/sub> 2<\/sup> \u00f6rnek varyanslard\u0131r.<\/span><\/p>\n (n 1<\/sub> + n 2<\/sub> -1) serbestlik derecesine sahip t testi istatisti\u011fine kar\u015f\u0131l\u0131k gelen p de\u011feri, se\u00e7ti\u011finiz anlaml\u0131l\u0131k d\u00fczeyinden k\u00fc\u00e7\u00fckse (ortak se\u00e7enekler 0,10, 0,05 ve 0, 01’dir), o zaman s\u0131f\u0131r hipotezini reddedebilir. .<\/span><\/p>\n \u00d6rnek: iki \u00f6rnekli t testi<\/strong><\/span><\/p>\n Bir ara\u015ft\u0131rmac\u0131 iki bitki t\u00fcr\u00fc aras\u0131ndaki ortalama y\u00fcksekli\u011fin e\u015fit olup olmad\u0131\u011f\u0131n\u0131 bilmek istiyor. Bunu test etmek i\u00e7in her pop\u00fclasyondan rastgele 20 bitki \u00f6rne\u011fi topluyor ve her \u00f6rne\u011fin ortalamas\u0131n\u0131 hesapl\u0131yor.<\/span><\/p>\n T testi istatisti\u011fi 1,251 ve kar\u015f\u0131l\u0131k gelen p de\u011feri 0,2148 olarak ortaya \u00e7\u0131k\u0131yor. Bu p de\u011feri 0,05’ten k\u00fc\u00e7\u00fck olmad\u0131\u011f\u0131ndan T testinin s\u0131f\u0131r hipotezini reddetmede ba\u015far\u0131s\u0131z olur. Bu, iki bitki t\u00fcr\u00fc aras\u0131ndaki ortalama boylar\u0131n farkl\u0131 oldu\u011funu iddia etmek i\u00e7in yeterli kan\u0131t\u0131n bulunmad\u0131\u011f\u0131 anlam\u0131na gelir.<\/span><\/p>\n A\u015fa\u011f\u0131daki sorular\u0131 yan\u0131tlamak i\u00e7in genellikle F testi<\/strong> kullan\u0131r\u0131z:<\/span><\/p>\n Ve genellikle a\u015fa\u011f\u0131daki sorular\u0131 yan\u0131tlamak i\u00e7in bir T testi<\/strong> kullan\u0131r\u0131z:<\/span><\/p>\n Hipotez Testine Giri\u015f<\/a> \u00d6\u011frencilerin s\u0131kl\u0131kla kar\u0131\u015ft\u0131rd\u0131\u011f\u0131 iki istatistiksel test F-Test ve T-Test’tir . Bu e\u011fitimde iki test aras\u0131ndaki fark a\u00e7\u0131klanmaktad\u0131r. F testi: temel bilgiler \u0130ki pop\u00fclasyon varyans\u0131n\u0131n e\u015fit olup olmad\u0131\u011f\u0131n\u0131 test etmek i\u00e7in F testi kullan\u0131l\u0131r. Testin s\u0131f\u0131r ve alternatif hipotezleri a\u015fa\u011f\u0131daki gibidir: H 0 : \u03c3 1 2 = \u03c3 2 2 (n\u00fcfus varyanslar\u0131 e\u015fittir) H 1 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[11],"tags":[],"class_list":["post-950","post","type-post","status-publish","format-standard","hentry","category-rehber"],"yoast_head":"\n F testi: temel bilgiler<\/strong><\/span><\/h3>\n
T testi: temel bilgiler<\/strong><\/span><\/h3>\n
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F testi veya T testi: ne zaman kullan\u0131lmal\u0131?<\/strong><\/span><\/h2>\n
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Ek kaynaklar<\/strong><\/span><\/h3>\n
Bir t-testi hesap makinesi \u00f6rne\u011fi<\/a>
\u0130ki \u00f6rnekli t testi hesaplay\u0131c\u0131s\u0131<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"